New SAT Math - Calculator : New SAT Math - Calculator

Study concepts, example questions & explanations for New SAT Math - Calculator

varsity tutors app store varsity tutors android store

Example Questions

Example Question #11 : How To Find An Angle Of A Line

If  , , and , what is the measure, in degrees, of 

Alternate interior angles   

 

Possible Answers:

62

32

58

122

148

Correct answer:

148

Explanation:

The question states that . The alternate interior angle theorem states that if two parallel lines are cut by a transversal, then pairs of alternate interior angles are congruent; therefore, we know the following measure:

The sum of angles of a triangle is equal to 180 degrees. The question states that ; therefore we know the following measure:

Use this information to solve for the missing angle:

The degree measure of a straight line is 180 degrees; therefore, we can write the following equation:

The measure of  is 148 degrees. 

Example Question #11 : How To Find An Angle Of A Line

Lines A and B in the diagram below are parallel. The triangle at the bottom of the figure is an isosceles triangle.

Act2

What is the degree measure of angle ?

Possible Answers:

Correct answer:

Explanation:

Since A and B are parallel, and the triangle is isosceles, we can use the supplementary rule for the two angles,  and  which will sum up to . Setting up an algebraic equation for this, we get . Solving for , we get . With this, we can get either  (for the smaller angle) or  (for the larger angle - must then use supplementary rule again for inner smaller angle). Either way, we find that the inner angles at the top are 80 degrees each. Since the sum of the angles within a triangle must equal 180, we can set up the equation as

 degrees.

Example Question #61 : Arithmetic

Which of the following is equal to  ?

Possible Answers:

Correct answer:

Explanation:

√75 can be broken down to √25 * √3. Which simplifies to 5√3.

Example Question #62 : Arithmetic

Simplify \sqrt{a^{3}b^{4}c^{5}}.

Possible Answers:

a^{2}bc\sqrt{bc}

a^{2}bc^{2}\sqrt{ac}

ab^{2}c^{2}\sqrt{ac}

a^{2}b^{2}c\sqrt{ab}

a^{2}b^{2}c^{2}\sqrt{bc}

Correct answer:

ab^{2}c^{2}\sqrt{ac}

Explanation:

Rewrite what is under the radical in terms of perfect squares:

x^{2}=x\cdot x

x^{4}=x^{2}\cdot x^{2}

x^{6}=x^{3}\cdot x^{3}

Therefore, \sqrt{a^{3}b^{4}c^{5}}= \sqrt{a^{2}a^{1}b^{4}c^{4}c^{1}}=ab^{2}c^{2}\sqrt{ac}.

Example Question #995 : Sat Mathematics

What is ?

Possible Answers:

Correct answer:

Explanation:

We know that 25 is a factor of 50. The square root of 25 is 5. That leaves  which can not be simplified further.

Example Question #996 : Sat Mathematics

Which of the following is equivalent to \frac{x + \sqrt{3}}{3x + \sqrt{2}}?

Possible Answers:

\frac{3x^{2} - \sqrt{6}}{9x^{2} + 2}

\frac{3x^{2} + \sqrt{6}}{3x - 2}

\frac{3x^{2} -x \sqrt{2} + 3x\sqrt{3} - \sqrt{6}}{9x^{2} - 2}

\frac{3x^{2} + 3x\sqrt{2} + x\sqrt{3} +\sqrt{6}}{9x^{2} - 2}

\frac{4x + \sqrt{5}}{3x + 2}

Correct answer:

\frac{3x^{2} -x \sqrt{2} + 3x\sqrt{3} - \sqrt{6}}{9x^{2} - 2}

Explanation:

Multiply by the conjugate and the use the formula for the difference of two squares:

\frac{x + \sqrt{3}}{3x + \sqrt{2}}

\frac{x + \sqrt{3}}{3x + \sqrt{2}}\cdot \frac{3x - \sqrt{2}}{3x - \sqrt{2}}

\frac{3x^{2} -x \sqrt{2} + 3x\sqrt{3} - \sqrt{6}}{(3x)^{2} - (\sqrt{2})^{2}} 

\frac{3x^{2} -x \sqrt{2} + 3x\sqrt{3} - \sqrt{6}}{9x^{2} - 2}

Example Question #1 : Simplifying Square Roots

Which of the following is the most simplified form of:

 

Possible Answers:

Correct answer:

Explanation:

First find all of the prime factors of 

So 

Example Question #115 : Arithmetic

What is  equal to?

Possible Answers:

Correct answer:

Explanation:

 

1. We know that , which we can separate under the square root:

 

2. 144 can be taken out since it is a perfect square: . This leaves us with:

This cannot be simplified any further.

Example Question #5 : Simplifying Square Roots

Which of the following is equal to ?

Possible Answers:

Correct answer:

Explanation:

When simplifying square roots, begin by prime factoring the number in question. For , this is:

Now, for each pair of numbers, you can remove that number from the square root. Thus, you can say:

Another way to think of this is to rewrite  as . This can be simplified in the same manner.

Example Question #2 : Simplifying Square Roots

Which of the following is equivalent to ?

Possible Answers:

Correct answer:

Explanation:

When simplifying square roots, begin by prime factoring the number in question. This is a bit harder for . Start by dividing out :

Now,  is divisible by , so:

 is a little bit harder, but it is also divisible by , so:

With some careful testing, you will see that 

Thus, we can say:

Now, for each pair of numbers, you can remove that number from the square root. Thus, you can say:

Another way to think of this is to rewrite  as . This can be simplified in the same manner.

Learning Tools by Varsity Tutors