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MCAT Physical : Reduction Potentials

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Example Question #1 : Oxidation Reduction

Consider the half reaction below.

$\small Ni^{2+}(aq) +2e^{-}\rightarrow Ni(s)$ $\displaystyle \small Ni^{2+}(aq) +2e^{-}\rightarrow Ni(s)$

$E^o_{Ni}=-0.23V$ $\displaystyle E^o_{Ni}=-0.23V$

Which of the following statements is true about the oxidation of nickel?

Possible Answers:

The nickel will gain electrons when oxidized

It is not possible to oxidize nickel

The oxidation of nickel has a potential of 0V

None of these are true

The oxidation of nickel has a potential of 0.23V

Correct answer:

The oxidation of nickel has a potential of 0.23V

Explanation:

Reduction potentials are typically provided in table form. Since the oxidation potential of an element is the negative of the reduction potential, it can be determined by viewing a reduction table.

Since the reduction potential for nickel is given as –0.23V, we can conclude that the oxidation potential for nickel is 0.23V.

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Example Question #1 : Reduction Potentials

The standard reduction potentials for iron and nickel are as follows:

$Fe^{2+} + 2e^{-} \rightarrow Fe$ $\displaystyle Fe^{2+} + 2e^{-} \rightarrow Fe$ $E^{\circ} = -0.45$ $\displaystyle E^{\circ} = -0.45$

$Ni^{2+} + 2e^{-} \rightarrow Ni$ $\displaystyle Ni^{2+} + 2e^{-} \rightarrow Ni$ $E^{\circ} = -0.26$ $\displaystyle E^{\circ} = -0.26$

If a galvanic cell is made using these two metals, what is the standard voltage for the cell?

Possible Answers:

-0.19V $\displaystyle -0.19V$

0.71V $\displaystyle 0.71V$

0.19V $\displaystyle 0.19V$

-0.71V $\displaystyle -0.71V$

Correct answer:

0.19V $\displaystyle 0.19V$

Explanation:

A galvanic cell is spontaneous, meaning that there will be a positive cell voltage. In order for this to take place, the more negative reduction potential must be flipped so that the metal is oxidized.

$Ni^{2+} + 2e^{-} \rightarrow Ni$ $\displaystyle Ni^{2+} + 2e^{-} \rightarrow Ni$ $E^{\circ}_{red} = -0.26$ $\displaystyle E^{\circ}_{red} = -0.26$

$Fe \rightarrow Fe^{2+} + 2e^{-}$ $\displaystyle Fe \rightarrow Fe^{2+} + 2e^{-}$ $E^{\circ}_{ox} = 0.45$ $\displaystyle E^{\circ}_{ox} = 0.45$

Adding these values together gives a standard cell voltage of 0.19V $\displaystyle 0.19V$.

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MCAT Physical : Reduction Potentials

Study concepts, example questions & explanations for MCAT Physical

All MCAT Physical Resources

Example Questions

Example Question #1 : Oxidation Reduction

Example Question #1 : Reduction Potentials

All MCAT Physical Resources

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