MCAT Physical : Thermochemistry and Energetics

Study concepts, example questions & explanations for MCAT Physical

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Example Questions

Example Question #5 : Endothermic And Exothermic Reactions

A system experiences the following energetic changes:

Which of the following is true? 

Possible Answers:

The system loses heat

The system loses  of energy

 of energy is input into the system

 of energy is input into the system

Correct answer:

 of energy is input into the system

Explanation:

Remember that a negative sign denotes an exothermic process (heat is released into the surroundings), while a positive energy change denotes an endothermic process (heat is absorbed).

Using the given values we can calculate the total energy change of the system:

Since the overall energy change is positive,  of energy is input into the system rather than lost to the surroundings.

Example Question #1081 : Mcat Physical Sciences

Is the reaction above endothermic or exothermic?

Possible Answers:

Exothermic because an increase in temperture would cause the reaction to shift to the right

Endothermic because an increase in temperture would cause the reaction to shift to the left

Endothermic because an increase in temperture would cause the reaction to shift to the right

Exothermic because an increase in temperture would cause the reaction to shift to the left

Correct answer:

Exothermic because an increase in temperture would cause the reaction to shift to the left

Explanation:

The reaction is an exothermic reaction, since the heat is added on the products side. An endothermic reaction would have the heat on the reactants side. An increase in heat in this reaction would cause the Keq to decrease, and there will be a shift to the left of the reaction (toward the reactants).

Remember that Keq is dependent on temperature, and can be affected by changes in heat. Keep in mind, also, that the reverse reaction that occurs during the leftward shift will be endothermic, using the additional heat as a reactant rather than a product.

Example Question #1082 : Mcat Physical Sciences

A student is performing a reaction with unknown compounds in his chemistry lab. The only information the student knows about the reaction is that it is endothermic and reversible. Using this knowledge alone, how can the student increase the yield of his product?

Possible Answers:

Remove reactant from the reaction

Add product to the reaction

Increase the temperature

Decrease the temperature

Correct answer:

Increase the temperature

Explanation:

To answer this question, we need to have a solid understanding of Le Chatelier's principle.  

In an endothermic reaction, heat is needed to facilitate the reaction. To increase the products, we want to shift the reaction to the right.

We should already know that adding product or removing reactant shifts the equilibrium to the left, and yields more starting material rather than product. In an endothermic reaction, we can consider heat as a reactant; thus, adding heat (increasing temperature) would allow us to shift the reaction to the right.

Decreasing the temperature, removing reactant, or adding product would all increase the yield of the starting materials.

Example Question #81 : Biochemistry, Organic Chemistry, And Other Concepts

For any given chemical reaction, one can draw an energy diagram. Energy diagrams depict the energy levels of the different steps in a reaction, while also indicating the net change in energy and giving clues to relative reaction rate. 

Below, a reaction diagram is shown for a reaction that a scientist is studying in a lab. A student began the reaction the evening before, but the scientist is unsure as to the type of the reaction. He cannot find the student’s notes, except for the reaction diagram below.

 

 

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Growing frustrated by his inability to decipher what chemical reaction the student had started, the scientist decides to measure the reaction vessel's temperature. Based only on the above reaction diagram, what is he most likely to find if the reaction is ongoing?

(Assume that the reaction vessel is defined as the system, and that the entropy of the system decreases)

Possible Answers:

A cold container from an endothermic reaction

A cold container from an exothermic reaction

The products of this reaction have an equal energy level to the reactants

A warm container from an endothermic reaction

A warm container from an exothermic reaction

Correct answer:

A warm container from an exothermic reaction

Explanation:

Point 5 is the energy level of the products of the reaction, while point 1 is the energy level of the reactants. Point 5 is lower than is point 1, indicating that the products of this reaction contain lower overall energy than do the reactants. This energy must be released in some form, likely as heat, characteristic of an exothermic reaction.

The question further specifies that there is a local decrease in entropy of the system, thus, the only way that entropy of the universe can increase is to release heat and increase the entropy of the surroundings.

Example Question #1083 : Mcat Physical Sciences

Why does a chemical ice pack feel cold? 

Possible Answers:

The chemicals in the ice pack undergo an endothermic reaction; this pulls heat from its surroundings for the reaction, making the ice pack feel cold.

The chemicals in the ice pack undergo an endothermic reaction; this releases heat into the surroundings, making the ice pack feel cold.

The chemicals in the ice pack undergo an exothermic reaction; this pulls heat from the surroundings, making the ice pack feel cold.

The chemicals in the ice pack undergo an exothermic reaction; this releases heat into the surroundings, making the ice pack feel cold.

Correct answer:

The chemicals in the ice pack undergo an endothermic reaction; this pulls heat from its surroundings for the reaction, making the ice pack feel cold.

Explanation:

Endothermic reactions by definition, require heat as a reactant. By drawing in heat from the surrounding, the surrounding will have a lower temperature compared to air temperature, which is why the ice pack feels cold. If it were an exothermic reaction, the pack would release heat, making the pack feel warm. 

Example Question #1 : Endergonic And Exergonic Reactions

Boiling point is the temperature a liquid needs to achieve in order to begin its transformation into a gaseous state. Campers and hikers who prepare food during their trips have to account for differences in atmospheric pressure as they ascend in elevation. During the ascent, the decrease in atmospheric pressure changes the temperature at which water boils.

Further complicating the matter is the observation that addition of a solute to a pure liquid also changes the boiling point. Raoult’s Law can be used to understand the changes in boiling point if a non-volatile solute is present, as expressed here.

In this law,  is the mole fraction of the solvent, is the vapor pressure of the pure solvent, and  is the vapor pressure of the solution. When this vapor pressure is equal to the local atmospheric pressure, the solution boils.

A scientist is studying solution chemistry to better understand vapor pressure. He finds that, for one solution he creates, the beaker is cool to the touch after the solute is fully dissolved. Which of the following is true of this solution? (Note: The beaker, solute, and solvent are the system, the remainder of the universe is the surroundings)

Possible Answers:

It always forms spontaneously

It forms spontaneously only if dissolution decreases entropy of the system

It forms spontaneously only at high temperatures

It forms spontaneously only at low temperatures

It never forms spontaneously

Correct answer:

It forms spontaneously only at high temperatures

Explanation:

The act of dissolving a solute in a solvent is a local increase in entropy, converting a single molecule to multiple ions. The absorption of heat from the surroundings (cool beaker) indicates that this is an endothermic dissolution. We can look at the equation for Gibbs free energy to evaluate the possible answers.

In order to be spontaneous, the reaction must have a negative Gibbs free energy. To accomplish this, a reaction may have a negative enthalpy (exothermic) and positive entropy, however we know that our reaction has a positive enthalpy (endothermic) and positive entropy. A reaction will be spontaneous if it has a positive  and a positive  only when temperature is high.

Example Question #1 : Endergonic And Exergonic Reactions

A scientist is studying a reaction, and places the reactants in a beaker at room temperature. The reaction progresses, and she analyzes the products via NMR. Based on the NMR readout, she determines the reaction proceeds as follows:

In an attempt to better understand the reaction process, she varies the concentrations of the reactants and studies how the rate of the reaction changes. The table below shows the reaction concentrations as she makes modifications in three experimental trials.

 

Assume that the forward reaction in the passage is exothermic, and has a  value of .  Which of the following is true?

Possible Answers:

The reaction is never spontaneous

The reaction is spontaneous only at low temperatures

The reaction is always spontaneous

The reaction is spontaneous only at high temperatures

The spontaneity of the reaction cannot be predicted

Correct answer:

The reaction is always spontaneous

Explanation:

The question specifies that this reaction is exothermic, and that it has a positive local increase in entropy as it progresses. This means that the change in enthaply is negative and the change in entropy is positive.

For a reaction to be spontaneous, Gibbs free energy must be negative.

If enthalpy is negative and entropy is positive, the temperature is irrelevant and Gibbs free energy will always be negative.

The reaction is spontaneous at any temperature.

Example Question #1 : Endergonic And Exergonic Reactions

For “Reaction A,”  is +300kJ and  is -98J. The reaction will be spontaneous under which of the following conditions?

Possible Answers:

The reaction is always spontaneous

Moderate temperature and high pressure

Low temperature

High temperature

The reaction cannot be spontaneous

Correct answer:

The reaction cannot be spontaneous

Explanation:

The spontaneity of a reaction is determined by the equation for Gibbs free energy. 

Here, H is a positive number and S is negative, meaning that G will always be a positive value. T will be given in Kelvin, and cannot be negative. Reactions with positive Gibbs free energy values are never spontaneous.

Example Question #14 : Physical Chemistry

The equation for the change in Gibbs free energy is given below.

ΔH = change in enthalpy

ΔS = change in entropy

Which of the following scenarios guarantees a nonspontaneous reaction?

Possible Answers:

When ΔH is positive and ΔS is positive

When ΔH is positive and ΔS is negative

When ΔH is negative and ΔS is positive

When ΔH is negative and ΔS is negative

Correct answer:

When ΔH is positive and ΔS is negative

Explanation:

A positive value for ΔG (Gibbs free energy) will guarantee a nonspontaneous reaction. When ΔH (enthalpy) is postive and ΔS (entropy) is negative, the change in Gibbs free energy must be positive and, therefore, nonspontaneous.

Because T (temperature) will always have a positive value, a negative entropy and positive enthalpy will always result in a positive Gibbs free energy.

Example Question #1 : Endergonic And Exergonic Reactions

The equation for the change in Gibbs free energy is given below.

ΔH = change in enthalpy

ΔS = change in entropy

In which of the scenarios will the reaction be spontaneous?

Possible Answers:

When both ΔH and ΔS are postive and T is high

When ΔH is negative and ΔS is postive

When both ΔH and ΔS are negative and T is low

All of these scenarios would result in spontaneous reactions

Correct answer:

All of these scenarios would result in spontaneous reactions

Explanation:

All of the following scenarios would lead to spontaneous reaction, since each scenario would result in a negative Gibbs free energy (-ΔG).

Negative enthalpy, positive entropy:

Positive enthalpy and entropy with high temperature:

Negative enthalpy and entropy with low temperature:

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