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Linear Algebra : Operations and Properties

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4 Diagnostic Tests 108 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #1 : Norms

Find the norm of the vector $\vec{v} = (-1, 3, 2,2)$

Possible Answers:

$2 \sqrt{3}$

$\sqrt{6}$

$3 \sqrt{2}$

Correct answer:

$3 \sqrt{2}$

Explanation:

$|| \vec{v} || = \sqrt{ (-1)^2 + 3^2 + 2^2 + 2^2 } = \sqrt{ 1 + 9 + 4 + 4 } = \sqrt{18}$

This can be simplified:

$\sqrt{18 } = \sqrt{3\cdot3\cdot2 } = 3 \sqrt{2 }$

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Example Question #3 : Norms

Find the norm of the vector $\vec{v} = (2, -3, 1 )$

Possible Answers:

$\sqrt{14 }$

$\sqrt{4}$

$\sqrt{10}$

Correct answer:

$\sqrt{14 }$

Explanation:

$|| \vec{v} || = \sqrt{2^2 + (-3)^2 + 1^2 } = \sqrt{4+9+1} = \sqrt{14}$

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Example Question #1 : Norms

Find the norm of the vector $\vec{v}= (4, 2, -5 )$

Possible Answers:

$5 \sqrt{2}$

$3 \sqrt{5}$

Correct answer:

$3 \sqrt{5}$

Explanation:

$|| \vec{v} || = \sqrt{ 4^2 + 2^2 + (-5)^2 } = \sqrt{16 + 4 + 25 } = \sqrt{45}$

This can be simplified:

$\sqrt{3 \cdot 3 \cdot 5 } = 3 \sqrt {5}$

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Example Question #1 : Norms

Find the norm of the vector $\vec{v} = (2, -3, -6 )$

Possible Answers:

$\sqrt{41 }$

$\sqrt{23}$

Correct answer:

Explanation:

$|| \vec{v} || = \sqrt{ 2^2 + (-3)^2 + (-6)^2 } = \sqrt{4 + 9 + 36 } = \sqrt{49} = 7$

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Example Question #141 : Operations And Properties

Find the norm of the vector $\vec{v} = (3, -2, -2)$

Possible Answers:

$\sqrt{7}$

$\sqrt{15}$

$\sqrt{17}$

Correct answer:

$\sqrt{17}$

Explanation:

$|| \vec{v} || = \sqrt{3^2 + (-2)^2 + (-2)^2 } = \sqrt{9+4+4} = \sqrt{17}$

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Example Question #142 : Operations And Properties

Find the norm of the vector $\vec{v} = (4, -1, 3 )$

Possible Answers:

$\sqrt{24}$

$\sqrt{6}$

$\sqrt{26}$

Correct answer:

$\sqrt{26}$

Explanation:

$|| \vec{v} || = \sqrt{ 4^2 + (-1)^2 + 3^2 } = \sqrt{16+1+9 } = \sqrt{26}$

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Example Question #143 : Operations And Properties

Find the norm of the vector $\vec{v} = (3, 4, 5 )$

Possible Answers:

$5 \sqrt{2}$

$3 \sqrt{2}$

$2 \sqrt{3}$

$2\sqrt{5}$

Correct answer:

$5 \sqrt{2}$

Explanation:

$|| \vec{v} || = \sqrt{ 3^2 + 4^2 + 5^2 } = \sqrt{9+16+25} = \sqrt{50 }$

This can be simplified:

$\sqrt{2 \cdot 5 \cdot 5 } = 5 \sqrt{2 }$

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Example Question #11 : Norms

Let $\textbf{u} = (2, 3, a, 1 )$ for some real number .

Give such that $\left \| \textbf{u} \right \| = 4$ .

Possible Answers:

$\pm \frac{16}{13}$

$\pm \sqrt{2}$

$\pm \frac{4 \sqrt{13}}{13}$

$\frac{2}{3}$

Correct answer:

$\pm \sqrt{2}$

Explanation:

$\left \| \textbf{u} \right \|$ , the norm, or length, of vector $\textbf{u}$ , is equal to the square root of the sum of the squares of its elements. Therefore,

$\left \| \textbf{u} \right \| = \sqrt{2^{2}+3^{2}+a^{2}+1^{2}}$

$= \sqrt{4+9+a^{2}+1}$

$= \sqrt{ a^{2}+14}$

Set this equal to 4:

$\sqrt{ a^{2}+14} = 4$

$a^{2}+14 = 16$

$a^{2}= 2$

$a = \pm \sqrt{2}$

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Example Question #144 : Operations And Properties

$\textbf{u}= (-3, 2, x, x)$ ,

where is a real number.

In terms of , give $\left \| \textbf{u} \right \|$ .

Possible Answers:

$\sqrt{2x-1}$

$\sqrt{2 x ^{2} +13}$

$x \sqrt{6}$

$\sqrt{2x+5}$

$\sqrt{2 x ^{2} -5}$

Correct answer:

$\sqrt{2 x ^{2} +13}$

Explanation:

$\left \| \textbf{u} \right \|$ , the norm, or length, of vector $\textbf{u}$ , is equal to the square root of the sum of the squares of its elements. Therefore,

$\left \| \textbf{u} \right \|= \sqrt{(-3)^{2}+ 2 ^{2}+ x ^{2} +x ^{2}}$

$=\sqrt{9+4+ x ^{2} +x ^{2}}$

$=\sqrt{2 x ^{2} +13}$

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Example Question #223 : Linear Algebra

$\bold{v} = \left ( \frac{1}{3}, - \frac{1}{3},\frac{1}{3} \right )$

True or false: $\textbf{v}$ is an example of a unit vector.

Possible Answers:

False

True

Correct answer:

False

Explanation:

$\textbf{v}$ is a unit vector if and only if its norm, or length, $\left \| \textbf{v} \right \|$ - the square root of the sum of the squares of its elements - is equal to 1. Find the length using this definition:

$\left \| \textbf{v} \right \| = \sqrt{\left ( \frac{1}{3} \right )^{2}+ \left ( -\frac{1}{3} \right )^{2}+ \left ( \frac{1}{3} \right )^{2}}$

$= \sqrt{\frac{1}{9}+ \frac{1}{9} + \frac{1}{9} }$

$= \sqrt{\frac{1}{3} }$

$\left \| \textbf{v} \right \| \ne 1$ , so $\textbf{v}$ is not a unit vector.

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Linear Algebra : Operations and Properties

Study concepts, example questions & explanations for Linear Algebra

All Linear Algebra Resources

Example Questions

Example Question #1 : Norms

Example Question #3 : Norms

Example Question #1 : Norms

Example Question #1 : Norms

Example Question #141 : Operations And Properties

Example Question #142 : Operations And Properties

Example Question #143 : Operations And Properties

Example Question #11 : Norms

Example Question #144 : Operations And Properties

Example Question #223 : Linear Algebra

All Linear Algebra Resources

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