Call Now to Set Up Tutoring:

(888) 888-0446

Linear Algebra : Non-Homogeneous Cases

Study concepts, example questions & explanations for Linear Algebra

Create An Account

All Linear Algebra Resources

4 Diagnostic Tests 108 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #1 : Non Homogeneous Cases

$\begin{align*}&\text{Find }\begin{bmatrix}x\\y\\z\end{bmatrix}\\&\text{for the system: }\begin{bmatrix}-3&-15&6\\15&-9&14\\-18&-5&-10\end{bmatrix}\begin{bmatrix}x\\y\\z\end{bmatrix}=\begin{bmatrix}-14\\5\\-8\end{bmatrix}\end{align*}$

Possible Answers:

$\begin{bmatrix}8.086\\0.14516\\-3.9274\end{bmatrix}$

$\begin{bmatrix}11.086\\3.1452\\-0.92742\end{bmatrix}$

$\begin{bmatrix}5.086\\-2.8548\\-6.9274\end{bmatrix}$

$\begin{bmatrix}-2.914\\-10.8548\\-14.9274\end{bmatrix}$

Correct answer:

$\begin{bmatrix}5.086\\-2.8548\\-6.9274\end{bmatrix}$

Explanation:

$- ¬\begin{align*}&\text{When faced with a system of equations like the}\\&\text{one represented by }\\&\begin{bmatrix}-3&-15&6\\15&-9&14\\-18&-5&-10\end{bmatrix}\begin{bmatrix}x\\y\\z\end{bmatrix}=\begin{bmatrix}-14\\5\\-8\end{bmatrix}\\&\text{an approach often taught is to manipulate coefficients to eliminate}\\&\text{variables. There is another to consider.}\\&\text{Note that if a matrix has an inverse, }\\&\text{then the product of that matrix and its inverse is the identity matrix:}\\&A^{-1}A=AA^{-1}=I\\&\text{Knowing this, it stands to reason that if given an equation like: }Ax=B\\&\text{We can isolate x as follows:}\\&A^{-1}Ax=A^{-1}B\\&x=A^{-1}B\\&\text{With this property we can solve our system:}\\&\begin{bmatrix}x\\y\\z\end{bmatrix}=\begin{bmatrix}-0.43011&0.48387&0.41935\\0.27419&-0.37097&-0.35484\\0.6371&-0.68548&-0.67742\end{bmatrix}\begin{bmatrix}-14\\5\\-8\end{bmatrix}\\&\begin{bmatrix}x\\y\\z\end{bmatrix}=\begin{bmatrix}5.086\\-2.8548\\-6.9274\end{bmatrix}\end{align*}$

Report an Error

Example Question #2 : Non Homogeneous Cases

$\begin{align*}&\text{Find the values of }\begin{bmatrix}x\\y\end{bmatrix}\\&\text{for the function: }\begin{bmatrix}7&15\\0&-18\end{bmatrix}\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}-8\\6\end{bmatrix}\end{align*}$

Possible Answers:

$\begin{bmatrix}-0.43\\-0.33\end{bmatrix}$

$\begin{bmatrix}-5.43\\-5.33\end{bmatrix}$

$\begin{bmatrix}-8.43\\-8.33\end{bmatrix}$

$\begin{bmatrix}2.57\\2.67\end{bmatrix}$

Correct answer:

$\begin{bmatrix}-0.43\\-0.33\end{bmatrix}$

Explanation:

$\begin{align*}&\text{When faced with a system of equations like the}\\&\text{one represented by }\\&\begin{bmatrix}7&15\\0&-18\end{bmatrix}\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}-8\\6\end{bmatrix}\\&\text{an approach often taught is to manipulate coefficients to eliminate}\\&\text{variables. This approach works, though there is another to consider.}\\&\text{If a matrix has an inverse, i.e. it has a determinant,}\\&\text{then the product of that matrix and its inverse is the identity matrix:}\\&A^{-1}A=AA^{-1}=I\\&\text{It then stands to reason that if given an equation like: }Ax=B\\&\text{We can isolate x as follows:}\\&A^{-1}Ax=A^{-1}B\\&x=A^{-1}B\\&\text{Using this, we can solve for our values:}\\&\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}0.143&0.119\\0.000&-0.056\end{bmatrix}\begin{bmatrix}-8\\6\end{bmatrix}\\&\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}-0.43\\-0.33\end{bmatrix}\end{align*}$

Report an Error

Example Question #3 : Non Homogeneous Cases

$\begin{align*}&\text{Find }\begin{bmatrix}x\\y\end{bmatrix}\\&\text{for the system: }\begin{bmatrix}12&-6\\-2&-5\end{bmatrix}\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}7\\3\end{bmatrix}\end{align*}$

Possible Answers:

$\begin{bmatrix}7.24\\6.31\end{bmatrix}$

$\begin{bmatrix}2.24\\1.31\end{bmatrix}$

$\begin{bmatrix}5.24\\4.31\end{bmatrix}$

$\begin{bmatrix}0.24\\-0.69\end{bmatrix}$

Correct answer:

$\begin{bmatrix}0.24\\-0.69\end{bmatrix}$

Explanation:

$\begin{align*}&\text{When faced with a system of equations like the}\\&\text{one represented by }\\&\begin{bmatrix}12&-6\\-2&-5\end{bmatrix}\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}7\\3\end{bmatrix}\\&\text{an approach often taught is to manipulate coefficients to eliminate}\\&\text{variables. This approach works, though there is another to consider.}\\&\text{If a matrix has an inverse, i.e. it has a determinant,}\\&\text{then the product of that matrix and its inverse is the identity matrix:}\\&A^{-1}A=AA^{-1}=I\\&\text{It then stands to reason that if given an equation like: }Ax=B\\&\text{We can isolate x as follows:}\\&A^{-1}Ax=A^{-1}B\\&x=A^{-1}B\\&\text{With this property we can solve our system:}\\&\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}0.069&-0.083\\-0.028&-0.167\end{bmatrix}\begin{bmatrix}7\\3\end{bmatrix}\\&\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}0.24\\-0.69\end{bmatrix}\end{align*}$

Report an Error

Example Question #4 : Non Homogeneous Cases

$\begin{align*}&\text{Find }\begin{bmatrix}x\\y\end{bmatrix}\\&\text{for the system: }\begin{bmatrix}12&18\\-20&6\end{bmatrix}\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}7\\-10\end{bmatrix}\end{align*}$

Possible Answers:

$\begin{bmatrix}-8.49\\-8.95\end{bmatrix}$

$\begin{bmatrix}0.51\\0.05\end{bmatrix}$

$\begin{bmatrix}3.51\\3.05\end{bmatrix}$

$\begin{bmatrix}4.51\\4.05\end{bmatrix}$

Correct answer:

$\begin{bmatrix}0.51\\0.05\end{bmatrix}$

Explanation:

$\begin{align*}&\text{When faced with a system of equations like the}\\&\text{one represented by }\\&\begin{bmatrix}12&18\\-20&6\end{bmatrix}\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}7\\-10\end{bmatrix}\\&\text{an approach often taught is to manipulate coefficients to eliminate}\\&\text{variables. This approach works, though there is another to consider.}\\&\text{If a matrix has an inverse, i.e. it has a determinant,}\\&\text{then the product of that matrix and its inverse is the identity matrix:}\\&A^{-1}A=AA^{-1}=I\\&\text{It then stands to reason that if given an equation like: }Ax=B\\&\text{We can isolate x as follows:}\\&A^{-1}Ax=A^{-1}B\\&x=A^{-1}B\\&\text{With this property we can solve our system:}\\&\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}0.014&-0.042\\0.046&0.028\end{bmatrix}\begin{bmatrix}7\\-10\end{bmatrix}\\&\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}0.51\\0.05\end{bmatrix}\end{align*}$

Report an Error

Example Question #5 : Non Homogeneous Cases

$\begin{align*}&\text{Find }\begin{bmatrix}x\\y\\z\end{bmatrix}\\&\text{for the system: }\begin{bmatrix}13&-19&-4\\-10&-1&16\\-9&4&-19\end{bmatrix}\begin{bmatrix}x\\y\\z\end{bmatrix}=\begin{bmatrix}-138\\134\\-122\end{bmatrix}\end{align*}$

Possible Answers:

$\begin{bmatrix}-1.13\\4.81\\7.97\end{bmatrix}$

$\begin{bmatrix}1.87\\7.81\\10.97\end{bmatrix}$

$\begin{bmatrix}4.87\\10.81\\13.97\end{bmatrix}$

$\begin{bmatrix}7.87\\13.81\\16.97\end{bmatrix}$

Correct answer:

$\begin{bmatrix}-1.13\\4.81\\7.97\end{bmatrix}$

Explanation:

$\begin{align*}&\text{When faced with a system of equations like the}\\&\text{one represented by }\\&\begin{bmatrix}13&-19&-4\\-10&-1&16\\-9&4&-19\end{bmatrix}\begin{bmatrix}x\\y\\z\end{bmatrix}=\begin{bmatrix}-138\\134\\-122\end{bmatrix}\\&\text{a common approach is to manipulate coefficients to eliminate}\\&\text{variables. This works, though there is another to consider.}\\&\text{If a matrix has an inverse,}\\&\text{then the product of that matrix and its inverse is the identity matrix:}\\&A^{-1}A=AA^{-1}=I\\&\text{It then stands to reason that if given an equation like: }Ax=B\\&\text{We can isolate x as follows:}\\&A^{-1}Ax=A^{-1}B\\&x=A^{-1}B\\&\text{With this property we can solve our system:}\\&\begin{bmatrix}x\\y\\z\end{bmatrix}=\begin{bmatrix}-0.008&-0.063&-0.052\\-0.056&-0.048&-0.028\\-0.008&0.020&-0.034\end{bmatrix}\begin{bmatrix}-138\\134\\-122\end{bmatrix}\\&\begin{bmatrix}x\\y\\z\end{bmatrix}=\begin{bmatrix}-1.13\\4.81\\7.97\end{bmatrix}\end{align*}$

Report an Error

Example Question #6 : Non Homogeneous Cases

$\begin{align*}&\text{Solve the system of equations: }\begin{bmatrix}-5&-16\\19&-3\end{bmatrix}\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}-167\\87\end{bmatrix}\end{align*}$

Possible Answers:

$\begin{bmatrix}-1.07\\1.58\end{bmatrix}$

$\begin{bmatrix}-0.07\\2.58\end{bmatrix}$

$\begin{bmatrix}7.93\\10.58\end{bmatrix}$

$\begin{bmatrix}5.93\\8.58\end{bmatrix}$

Correct answer:

$\begin{bmatrix}5.93\\8.58\end{bmatrix}$

Explanation:

$\begin{align*}&\text{When faced with a system of equations like the}\\&\text{one represented by }\\&\begin{bmatrix}-5&-16\\19&-3\end{bmatrix}\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}-167\\87\end{bmatrix}\\&\text{a common approach is to manipulate coefficients to eliminate}\\&\text{variables. This works, though there is another way to consider.}\\&\text{If a matrix has an inverse,}\\&\text{then the product of that matrix and its inverse is the identity matrix:}\\&A^{-1}A=AA^{-1}=I\\&\text{As such, if given an equation like: }Ax=B\\&\text{we can isolate x as follows:}\\&A^{-1}Ax=A^{-1}B\\&x=A^{-1}B\\&\text{With this, we can solve our system of equations:}\\&\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}-0.009&0.050\\-0.060&-0.016\end{bmatrix}\begin{bmatrix}-167\\87\end{bmatrix}\\&\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}5.93\\8.58\end{bmatrix}\end{align*}$

Report an Error

Example Question #7 : Non Homogeneous Cases

$\begin{align*}&\text{Find }\begin{bmatrix}x\\y\end{bmatrix}\\&\text{for the system: }\begin{bmatrix}4&18\\-16&16\end{bmatrix}\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}20\\-29\end{bmatrix}\end{align*}$

Possible Answers:

$\begin{bmatrix}2.39\\0.58\end{bmatrix}$

$\begin{bmatrix}-2.61\\-4.42\end{bmatrix}$

$\begin{bmatrix}-5.61\\-7.42\end{bmatrix}$

$\begin{bmatrix}3.39\\1.58\end{bmatrix}$

Correct answer:

$\begin{bmatrix}2.39\\0.58\end{bmatrix}$

Explanation:

$\begin{align*}&\text{When faced with a system of equations like the}\\&\text{one represented by }\\&\begin{bmatrix}4&18\\-16&16\end{bmatrix}\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}20\\-29\end{bmatrix}\\&\text{a common approach is to manipulate coefficients to eliminate}\\&\text{variables. This works, though there is another way to consider.}\\&\text{If a matrix has an inverse,}\\&\text{then the product of that matrix and its inverse is the identity matrix:}\\&A^{-1}A=AA^{-1}=I\\&\text{As such, if given an equation like: }Ax=B\\&\text{we can isolate x as follows:}\\&A^{-1}Ax=A^{-1}B\\&x=A^{-1}B\\&\text{With this property we can solve our system:}\\&\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}0.045&-0.051\\0.045&0.011\end{bmatrix}\begin{bmatrix}20\\-29\end{bmatrix}\\&\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}2.39\\0.58\end{bmatrix}\end{align*}$

Report an Error

Example Question #101 : Linear Equations

$\begin{align*}&\text{Find the values of }\begin{bmatrix}x\\y\\z\end{bmatrix}\\&\text{for the function: }\begin{bmatrix}-4&4&6\\-15&0&-8\\3&18&-3\end{bmatrix}\begin{bmatrix}x\\y\\z\end{bmatrix}=\begin{bmatrix}-187\\172\\170\end{bmatrix}\end{align*}$

Possible Answers:

$\begin{bmatrix}-1.26\\-2.41\\-36.40\end{bmatrix}$

$\begin{bmatrix}6.74\\5.59\\-28.40\end{bmatrix}$

$\begin{bmatrix}4.74\\3.59\\-30.40\end{bmatrix}$

$\begin{bmatrix}-3.26\\-4.41\\-38.40\end{bmatrix}$

Correct answer:

$\begin{bmatrix}4.74\\3.59\\-30.40\end{bmatrix}$

Explanation:

$\begin{align*}&\text{When faced with a system of equations like the}\\&\text{one represented by }\\&\begin{bmatrix}-4&4&6\\-15&0&-8\\3&18&-3\end{bmatrix}\begin{bmatrix}x\\y\\z\end{bmatrix}=\begin{bmatrix}-187\\172\\170\end{bmatrix}\\&\text{a common approach is to manipulate coefficients to eliminate}\\&\text{variables. This works, though there is another way to consider.}\\&\text{If a matrix has an inverse,}\\&\text{then the product of that matrix and its inverse is the identity matrix:}\\&A^{-1}A=AA^{-1}=I\\&\text{As such, if given an equation like: }Ax=B\\&\text{we can isolate x as follows:}\\&A^{-1}Ax=A^{-1}B\\&x=A^{-1}B\\&\text{Using this, we can solve for our values:}\\&\begin{bmatrix}x\\y\\z\end{bmatrix}=\begin{bmatrix}-0.058&-0.049&0.013\\0.028&0.002&0.049\\0.109&-0.034&-0.024\end{bmatrix}\begin{bmatrix}-187\\172\\170\end{bmatrix}\\&\begin{bmatrix}x\\y\\z\end{bmatrix}=\begin{bmatrix}4.74\\3.59\\-30.40\end{bmatrix}\end{align*}$

Report an Error

Example Question #102 : Linear Equations

$\begin{align*}&\text{Solve the system of equations: }\begin{bmatrix}18&-17&14\\17&-20&1\\6&-5&6\end{bmatrix}\begin{bmatrix}x\\y\\z\end{bmatrix}=\begin{bmatrix}105\\30\\53\end{bmatrix}\end{align*}$

Possible Answers:

$\begin{bmatrix}54.31\\44.23\\-8.62\end{bmatrix}$

$\begin{bmatrix}53.31\\43.23\\-9.62\end{bmatrix}$

$\begin{bmatrix}63.31\\53.23\\0.38\end{bmatrix}$

$\begin{bmatrix}49.31\\39.23\\-13.62\end{bmatrix}$

Correct answer:

$\begin{bmatrix}54.31\\44.23\\-8.62\end{bmatrix}$

Explanation:

$\begin{align*}&\text{When faced with a system of equations like the}\\&\text{one represented by }\\&\begin{bmatrix}18&-17&14\\17&-20&1\\6&-5&6\end{bmatrix}\begin{bmatrix}x\\y\\z\end{bmatrix}=\begin{bmatrix}105\\30\\53\end{bmatrix}\\&\text{a common approach is to manipulate coefficients to eliminate}\\&\text{variables. This works, though there is another way to consider.}\\&\text{If a matrix has an inverse,}\\&\text{then the product of that matrix and its inverse is the identity matrix:}\\&A^{-1}A=AA^{-1}=I\\&\text{As such, if given an equation like: }Ax=B\\&\text{we can isolate x as follows:}\\&A^{-1}Ax=A^{-1}B\\&x=A^{-1}B\\&\text{With this, we can solve our system of equations:}\\&\begin{bmatrix}x\\y\\z\end{bmatrix}=\begin{bmatrix}-2.212&0.615&5.058\\-1.846&0.462&4.231\\0.673&-0.231&-1.365\end{bmatrix}\begin{bmatrix}105\\30\\53\end{bmatrix}\\&\begin{bmatrix}x\\y\\z\end{bmatrix}=\begin{bmatrix}54.31\\44.23\\-8.62\end{bmatrix}\end{align*}$

Report an Error

Example Question #103 : Linear Equations

$\begin{align*}&\text{Find the values of }\begin{bmatrix}x\\y\\z\end{bmatrix}\\&\text{for the function: }\begin{bmatrix}-2&-17&10\\-19&-3&-19\\20&1&17\end{bmatrix}\begin{bmatrix}x\\y\\z\end{bmatrix}=\begin{bmatrix}-47\\154\\-98\end{bmatrix}\end{align*}$

Possible Answers:

$\begin{bmatrix}5.98\\-10.63\\-18.88\end{bmatrix}$

$\begin{bmatrix}0.98\\-15.63\\-23.88\end{bmatrix}$

$\begin{bmatrix}3.98\\-12.63\\-20.88\end{bmatrix}$

$\begin{bmatrix}8.98\\-7.63\\-15.88\end{bmatrix}$

Correct answer:

$\begin{bmatrix}8.98\\-7.63\\-15.88\end{bmatrix}$

Explanation:

$\begin{align*}&\text{When faced with a system of equations like the}\\&\text{one represented by }\\&\begin{bmatrix}-2&-17&10\\-19&-3&-19\\20&1&17\end{bmatrix}\begin{bmatrix}x\\y\\z\end{bmatrix}=\begin{bmatrix}-47\\154\\-98\end{bmatrix}\\&\text{a common approach is to manipulate coefficients to eliminate}\\&\text{variables. This works, though there is another way to consider.}\\&\text{If a matrix has an inverse,}\\&\text{then the product of that matrix and its inverse is the identity matrix:}\\&A^{-1}A=AA^{-1}=I\\&\text{As such, if given an equation like: }Ax=B\\&\text{we can isolate x as follows:}\\&A^{-1}Ax=A^{-1}B\\&x=A^{-1}B\\&\text{Using this, we can solve for our values:}\\&\begin{bmatrix}x\\y\\z\end{bmatrix}=\begin{bmatrix}-0.022&0.207&0.245\\-0.040&-0.162&-0.158\\0.028&-0.234&-0.220\end{bmatrix}\begin{bmatrix}-47\\154\\-98\end{bmatrix}\\&\begin{bmatrix}x\\y\\z\end{bmatrix}=\begin{bmatrix}8.98\\-7.63\\-15.88\end{bmatrix}\end{align*}$

Report an Error

View Linear Algebra Tutors

Timothy
Certified Tutor

Bethune-Cookman University, Bachelor of Science, Mathematics. University of Phoenix, Master of Science, Computer and Informat...

View Linear Algebra Tutors

John
Certified Tutor

The Richard Stockton College of New Jersey, Bachelor of Science, Mathematics. University of Texas Rio Grande Valley, Master o...

View Linear Algebra Tutors

Pushpendra
Certified Tutor

university of allahabad, Bachelor of Science, Mathematics.

All Linear Algebra Resources

4 Diagnostic Tests 108 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

English Tutors in Boston, SAT Tutors in Philadelphia, LSAT Tutors in Seattle, Spanish Tutors in Seattle, SSAT Tutors in Washington DC, Math Tutors in Washington DC, Reading Tutors in Phoenix, SSAT Tutors in Seattle, Spanish Tutors in Houston, Algebra Tutors in San Diego

Popular Courses & Classes

ISEE Courses & Classes in Phoenix, ACT Courses & Classes in Atlanta, SAT Courses & Classes in Washington DC, MCAT Courses & Classes in Miami, SSAT Courses & Classes in New York City, GMAT Courses & Classes in San Diego, ISEE Courses & Classes in Chicago, ISEE Courses & Classes in Seattle, MCAT Courses & Classes in San Diego, Spanish Courses & Classes in Phoenix

Popular Test Prep

LSAT Test Prep in Chicago, MCAT Test Prep in Dallas Fort Worth, ISEE Test Prep in Washington DC, LSAT Test Prep in Los Angeles, SAT Test Prep in Miami, ACT Test Prep in Denver, MCAT Test Prep in Seattle, GMAT Test Prep in Phoenix, ACT Test Prep in Atlanta, SAT Test Prep in Washington DC

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

Linear Algebra : Non-Homogeneous Cases

Study concepts, example questions & explanations for Linear Algebra

All Linear Algebra Resources

Example Questions

Example Question #1 : Non Homogeneous Cases

Example Question #2 : Non Homogeneous Cases

Example Question #3 : Non Homogeneous Cases

Example Question #4 : Non Homogeneous Cases

Example Question #5 : Non Homogeneous Cases

Example Question #6 : Non Homogeneous Cases

Example Question #7 : Non Homogeneous Cases

Example Question #101 : Linear Equations

Example Question #102 : Linear Equations

Example Question #103 : Linear Equations

All Linear Algebra Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: