We are open Saturday and Sunday!

Call Now to Set Up Tutoring:

(888) 888-0446

ISEE Upper Level Math : Radius

Study concepts, example questions & explanations for ISEE Upper Level Math

Create An Account

All ISEE Upper Level Math Resources

6 Diagnostic Tests 244 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

← Previous 1 2 3 4 5 Next →

Example Question #184 : Geometry

Find the area of a circle with a radius of 6in.

Possible Answers:

$24\pi \text{ in}^2$

$42\pi \text{ in}^2$

$12\pi \text{ in}^2$

$18\pi \text{ in}^2$

$36\pi \text{ in}^2$

Correct answer:

$36\pi \text{ in}^2$

Explanation:

To find the area of a circle, we will use the following formula:

$A = \pi \cdot r^2$

Now, we know the radius of the circle is 6in.

Knowing this, we can substitute into the formula. We get

$A = \pi \cdot (6\text{in})^2$

$A = \pi \cdot 36\text{in}^2$

$A = 36\pi \text{ in}^2$

Report an Error

Example Question #185 : Geometry

Find the area of a circle with a diameter of 10in.

Possible Answers:

$10\pi \text{ in}^2$

$50\pi \text{ in}^2$

$100\pi \text{ in}^2$

$75\pi \text{ in}^2$

$25\pi \text{ in}^2$

Correct answer:

$25\pi \text{ in}^2$

Explanation:

To find the area of a circle, we will use the following formula:

$A = \pi \cdot r^2$

where r is the radius of the circle.

Now, we know the diameter of the circle is 10in. We also know the diameter is two times the radius. Therefore, the radius is 5in.

Knowing this, we can substitute into the formula. We get

$A = \pi \cdot (5\text{in})^2$

$A = \pi \cdot 25\text{in}^2$

$A = 25\pi \text{ in}^2$

Report an Error

Example Question #186 : Geometry

Find the area of a circle with a diameter of 14cm.

Possible Answers:

$21\pi \text{ cm}^2$

$49\pi \text{ cm}^2$

$63\pi \text{ cm}^2$

$196\pi \text{ cm}^2$

$56\pi \text{ cm}^2$

Correct answer:

$49\pi \text{ cm}^2$

Explanation:

To find the area of a circle, we will use the following formula:

$A = \pi \cdot r^2$

where r is the radius of the circle.

Now, we know the diameter of the circle is 14cm. We also know the diameter is two times the radius. Therefore, the radius is 7cm.

Knowing this, we can substitute into the formula. We get

$A = \pi \cdot (7\text{cm})^2$

$A = \pi \cdot 49\text{cm}^2$

$A = 49\pi \text{ cm}^2$

Report an Error

Example Question #11 : How To Find The Area Of A Circle

You have a tomato plant growing in a pot. If the base of the pot has a radius of 6 inches, find the area of the footprint of the pot.

Possible Answers:

$12 \pi in^2$

36 in^2

120 in ^2

$36 \pi in^2$

Correct answer:

$36 \pi in^2$

Explanation:

You have a tomato plant growing in a pot. If the base of the pot has a radius of 6 inches, find the area of the footprint of the pot.

To solve this problem, first recall the formula for area of a circle.

$A=\pi r ^2$

Now, we know our r=6 inches, so we just need to plug in and simplify.

$A=\pi (6in) ^2=36 \pi in^2$

So, our answer is:

$36 \pi in^2$

Report an Error

Example Question #188 : Geometry

Let $\pi = 3.14$ .

Find the area of a circle with a diameter of 14cm. If necessary, round to the nearest tenths.

Possible Answers:

$153.8\text{cm}^2$

$150.7\text{cm}^2$

$201.0\text{cm}^2$

$113.1\text{cm}^2$

$153.9\text{cm}^2$

Correct answer:

$153.9\text{cm}^2$

Explanation:

To find the area of a circle, we will use the following formula:

$A = \pi \cdot r^2$

where r is the radius of the circle.

Now, we know the diameter of the circle is 14cm. We also know that the diameter is two times the radius. Therefore, the radius is 7cm.

We also know $\pi = 3.14$ .

Knowing all of this, we can substitute into the formula. We get

$A = 3.14 \cdot (7\text{cm})^2$

$A = 3.14 \cdot 49\text{cm}^2$

$A = 153.86\text{cm}^2$

We were asked to round to the nearest tenth. So, we get

$A = 153.9\text{cm}^2$

Report an Error

Example Question #189 : Geometry

Find the area of a circle with a radius of 16in.

Possible Answers:

$256\pi \text{ in}^2$

$121\pi \text{ in}^2$

$187\pi \text{ in}^2$

$32\pi \text{ in}^2$

$89\pi \text{ in}^2$

Correct answer:

$256\pi \text{ in}^2$

Explanation:

To find the area of a circle, we will use the following formula:

$A = \pi r^2$

where r is the radius of the circle.

Now, we know the radius is 16in. Knowing this, we can substitute into the formula. We get

$A = \pi \cdot (16\text{in})^2$

$A = \pi \cdot 256\text{in}^2$

$A = 256\pi \text{ in}^2$

Report an Error

Example Question #190 : Geometry

You are conducting fieldwork, when you find a tree whose radius at chest height is . What is the area of a cross section of the tree at chest height?

Possible Answers:

$A=2.25\pi m^2$

$A=3\pi m^2$

$A=4.50\pi m^2$

A=2.25m^2

Correct answer:

$A=2.25\pi m^2$

Explanation:

You are conducting fieldwork, when you find a tree whose radius at chest height is . What is the area of a cross section of the tree at chest height?

Begin with the formula for area of a circle

$A=\pi r^2$

Now, we know r, so all we have to do is plug it in and solve.

$A=\pi (1.5m)^2=\pi 2.25m^2=2.25\pi m^2$

So, our answer is:

$A=2.25\pi m^2$

Report an Error

Example Question #21 : How To Find The Area Of A Circle

Find the area of a circle with a diameter of 16in.

Possible Answers:

$64\pi \text{ in}^2$

$128\pi \text{ in}^2$

$36\pi \text{ in}^2$

$96\pi \text{ in}^2$

$84\pi \text{ in}^2$

Correct answer:

$64\pi \text{ in}^2$

Explanation:

To find the area of a circle, we will use the following formula:

$A = \pi r^2$

where r is the radius of the circle.

Now, we know the diameter is 16in. We also know the diameter is two times the radius. Therefore, the radius is 8in. So, we get

$A = \pi \cdot (8\text{in})^2$

$A = \pi \cdot 64\text{in}^2$

$A = 64\pi \text{ in}^2$

Report an Error

Example Question #22 : How To Find The Area Of A Circle

A circle has a diameter of 18cm. Find the area.

Possible Answers:

$36\pi \text{ cm}^2$

$324\pi \text{ cm}^2$

$64\pi \text{ cm}^2$

$124\pi \text{ cm}^2$

$81\pi \text{ cm}^2$

Correct answer:

$81\pi \text{ cm}^2$

Explanation:

To find the area of a circle, we will use the following formula:

$A = \pi \cdot r^2$

where r is the radius of the circle.

Now, we know the diameter of the circle is 18cm. We also know the diameter is two times the radius. Therefore, the radius is 9cm.

Knowing this, we can substitute into the formula. We get

$A = \pi \cdot (9\text{cm})^2$

$A = \pi \cdot 81\text{cm}^2$

$A = 81\pi \text{ cm}^2$

Report an Error

Example Question #51 : Circles

What is the circumference of a circle with a radius equal to ?

Possible Answers:

$14\pi$

$7\pi$

$196\pi$

$49\pi$

Correct answer:

$14\pi$

Explanation:

The circumference can be solved using the following equation:

$C=2r\pi=2(7)\pi=14\pi$

Report an Error

← Previous 1 2 3 4 5 Next →

View Tutors

Joseph
Certified Tutor

University of Waterloo, Doctor of Philosophy, Applied Mathematics.

View Tutors

Sumit
Certified Tutor

Calcutta University, Bachelor of Science, Mathematics. Indian Statistical Institute, Master of Science, Mathematics.

View Tutors

Jaroslaw
Certified Tutor

Heriot Watt University, Master of Science, Physics. Heriot Watt University, Doctor of Science, Theoretical and Mathematical P...

All ISEE Upper Level Math Resources

6 Diagnostic Tests 244 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

SAT Tutors in Chicago, Physics Tutors in Phoenix, Spanish Tutors in Dallas Fort Worth, Math Tutors in Boston, Biology Tutors in Seattle, SSAT Tutors in Denver, Computer Science Tutors in Atlanta, Computer Science Tutors in Boston, ACT Tutors in Washington DC, LSAT Tutors in Dallas Fort Worth

Popular Courses & Classes

MCAT Courses & Classes in Seattle, LSAT Courses & Classes in Houston, MCAT Courses & Classes in Atlanta, MCAT Courses & Classes in Philadelphia, Spanish Courses & Classes in Miami, SAT Courses & Classes in Miami, GRE Courses & Classes in Denver, SSAT Courses & Classes in Philadelphia, SAT Courses & Classes in Los Angeles, ISEE Courses & Classes in Houston

Popular Test Prep

GMAT Test Prep in Miami, MCAT Test Prep in Seattle, GRE Test Prep in Denver, SSAT Test Prep in Seattle, ISEE Test Prep in Boston, SAT Test Prep in Denver, ISEE Test Prep in San Diego, SAT Test Prep in New York City, SSAT Test Prep in New York City, ISEE Test Prep in Dallas Fort Worth

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

ISEE Upper Level Math : Radius

Study concepts, example questions & explanations for ISEE Upper Level Math

All ISEE Upper Level Math Resources

Example Questions

Example Question #184 : Geometry

Example Question #185 : Geometry

Example Question #186 : Geometry

Example Question #11 : How To Find The Area Of A Circle

Example Question #188 : Geometry

Example Question #189 : Geometry

Example Question #190 : Geometry

Example Question #21 : How To Find The Area Of A Circle

Example Question #22 : How To Find The Area Of A Circle

Example Question #51 : Circles

All ISEE Upper Level Math Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: