ISEE Middle Level Quantitative : ISEE Middle Level (grades 7-8) Quantitative Reasoning

Study concepts, example questions & explanations for ISEE Middle Level Quantitative

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Example Questions

Example Question #5 : Squares / Square Roots

\(\displaystyle Q^{2} = 49\)

Which is the greater quantity?

(A) \(\displaystyle Q\)

(B) \(\displaystyle -8\)

Possible Answers:

It is impossible to tell which is greater from the information given

(B) is greater

(A) and (B) are equal

(A) is greater

Correct answer:

(A) is greater

Explanation:

If \(\displaystyle Q^{2} = 49\), then one of two things is true - either \(\displaystyle Q=7\) or \(\displaystyle Q=- 7\). Since \(\displaystyle 7 > -8\) and \(\displaystyle -7 > -8\)\(\displaystyle Q > -8\) either way, so (A) is greater.

Example Question #201 : Isee Middle Level (Grades 7 8) Quantitative Reasoning

Which is the greater quantity?

(A) \(\displaystyle \sqrt{9} + \sqrt{25}\)

(B) \(\displaystyle \sqrt{34}\)

Possible Answers:

It is impossible to tell which is greater from the information given

(B) is greater

(A) is greater

(A) and (B) are equal

Correct answer:

(A) is greater

Explanation:

\(\displaystyle \sqrt{9} + \sqrt{25} = 3 + 5 = 8\)

since \(\displaystyle 8^{2} = 8 \times 8 = 64\)\(\displaystyle 8 = \sqrt{64}\).

Since \(\displaystyle 64 > 34\)\(\displaystyle \sqrt{64} > \sqrt{34}\), and (A) is greater

Example Question #202 : Isee Middle Level (Grades 7 8) Quantitative Reasoning

Which is the greater quantity?

(A) \(\displaystyle \sqrt{4 \cdot 9 \cdot 25}\)

(B) \(\displaystyle 2 \cdot 3 \cdot 5\)

Possible Answers:

(A) and (B) are equal

It is impossible to tell which is greater from the information given

(B) is greater

(A) is greater

Correct answer:

(A) and (B) are equal

Explanation:

\(\displaystyle \sqrt{4 \cdot 9 \cdot 25} = \sqrt{900} = 30\)

\(\displaystyle 2 \cdot 3 \cdot 5 = 30\)

The quantities are equal.

Example Question #203 : Isee Middle Level (Grades 7 8) Quantitative Reasoning

Which is the greater quantity?

(A) \(\displaystyle 25\)

(B) \(\displaystyle \sqrt{600}\)

Possible Answers:

(B) is greater

(A) and (B) are equal

It is impossible to tell which is greater from the information given

(A) is greater

Correct answer:

(A) is greater

Explanation:

\(\displaystyle 25 ^{2} = 25 \times 25 = 625\), so 

\(\displaystyle 25 = \sqrt{625} > \sqrt{600}\)

This makes (A) greater.

Example Question #202 : Isee Middle Level (Grades 7 8) Quantitative Reasoning

Which is the greater quantity?

(A) \(\displaystyle \sqrt{100^{4}}\)

(B) \(\displaystyle 100^{2}\)

 

Possible Answers:

It is impossible to tell which is greater from the information given

(B) is greater

(A) is greater

(A) and (B) are equal

Correct answer:

(A) and (B) are equal

Explanation:

\(\displaystyle \sqrt{100^{4}} = \sqrt{100 \times 100 \times 100 \times 100} = \sqrt{100,000,000} = 10,000\)

\(\displaystyle 100^{2} = 100 \times 100 = 10,000\)

The quantities are equal.

Example Question #203 : Isee Middle Level (Grades 7 8) Quantitative Reasoning

Which of the following is equal to \(\displaystyle \sqrt{4 \cdot 9 \cdot 16}\) ?

Possible Answers:

\(\displaystyle 9\)

\(\displaystyle 24\)

\(\displaystyle 16\)

\(\displaystyle 22\)

\(\displaystyle 12\)

Correct answer:

\(\displaystyle 24\)

Explanation:

First, simplify the terms within the square root by multiplying.

\(\displaystyle \sqrt{4 \cdot 9 \cdot 16} = \sqrt{36 \cdot 16} = \sqrt{576}\)

Then, solve the sqaure root.

\(\displaystyle \sqrt{576}=24\)

Example Question #206 : Isee Middle Level (Grades 7 8) Quantitative Reasoning

Which of the following is equal to \(\displaystyle \sqrt{4^{2} \cdot 3^{2}}\) ?

Possible Answers:

\(\displaystyle 12\)

\(\displaystyle 10\)

\(\displaystyle 14\)

\(\displaystyle 7\)

\(\displaystyle 9\)

Correct answer:

\(\displaystyle 12\)

Explanation:

First, evalutate the terms under the radical:

\(\displaystyle \sqrt{4^{2} \cdot 3^{2}} = \sqrt{16 \cdot 9} =\sqrt{144}\)

Then, take the square root:

\(\displaystyle \sqrt{144}=12\)

Example Question #17 : Squares / Square Roots

Which is the greater quantity?

(A) \(\displaystyle \sqrt{1+ 4+ 9 + 16 + 25 + 36}\)

(B) \(\displaystyle 9\)

Possible Answers:

(A) and (B) are equal

(A) is greater

(B) is greater

It is impossible to tell which is greater from the information given

Correct answer:

(A) is greater

Explanation:

\(\displaystyle 1+ 4+ 9 + 16 + 25 + 36\)

\(\displaystyle =5 + 9 + 16 + 25 + 36\)

\(\displaystyle =14 + 16 + 25 + 36\)

\(\displaystyle =30+ 25 + 36\)

\(\displaystyle =55 + 36\)

\(\displaystyle =91\)

Therefore, \(\displaystyle \sqrt{1+ 4+ 9 + 16 + 25 + 36} = \sqrt{91}\).

 

Since \(\displaystyle 9^{2} = 9 \times 9 = 81\)\(\displaystyle 9 = \sqrt{81}\).

 

\(\displaystyle 91 > 81\), so \(\displaystyle \sqrt{91 }>\sqrt{ 81}\), and (A) is greater.

Example Question #204 : Isee Middle Level (Grades 7 8) Quantitative Reasoning

Which of the following is equal to 39?

 

Possible Answers:

\(\displaystyle 12\cdot3+3\)

\(\displaystyle 12\cdot2+3\)

\(\displaystyle 12\cdot3+6\)

\(\displaystyle 16\cdot3+3\)

Correct answer:

\(\displaystyle 12\cdot3+3\)

Explanation:

\(\displaystyle 12\cdot3+3\) is equal to:

\(\displaystyle 36+3\)

\(\displaystyle 39\)

Therefore, \(\displaystyle 12\cdot3+3\) is the correct answer. 

Example Question #19 : Squares / Square Roots

\(\displaystyle A\) is a positive integer; \(\displaystyle B\) is a negative integer; \(\displaystyle A +B =1\).

Which is the greater quantity?

(a) \(\displaystyle \sqrt{A^{2}}\)

(b) \(\displaystyle \sqrt{B^{2}}\)

Possible Answers:

It is impossible to determine which is greater from the information given

(b) is the greater quantity

(a) and (b) are equal

(a) is the greater quantity

Correct answer:

(a) is the greater quantity

Explanation:

\(\displaystyle A +B =1\), then \(\displaystyle B = 1-A\). Since \(\displaystyle B\) is negative, let \(\displaystyle C\) be the opposite of \(\displaystyle B\). Therefore, \(\displaystyle C= - B = - ( 1-A) =A-1\).

Two numbers that are each other's opposite have the same square, so

\(\displaystyle C^{2} = B^{2}\)

\(\displaystyle C = A-1 < A\), so, since \(\displaystyle C\) and \(\displaystyle A\) are positive,

\(\displaystyle C^{2} < A^{2}\)

By substitution,

\(\displaystyle B^{2}< A^{2}\),

and

\(\displaystyle \sqrt{B^{2}}< \sqrt{ A^{2}}\).

 

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