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ISEE Middle Level Math : Quadrilaterals

Study concepts, example questions & explanations for ISEE Middle Level Math

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All ISEE Middle Level Math Resources

6 Diagnostic Tests 303 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #47 : Rectangles

Find the area of a rectangle with a length of 24in and a width that is a third of the length.

Possible Answers:

$192\text{in}^2$

$212\text{in}^2$

$72\text{in}^2$

$156\text{in}^2$

$96\text{in}^2$

Correct answer:

$192\text{in}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$A = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, we know the length of the rectangle is 24in. We also know the width is a third of the length. Therefore, the width is 8in.

Knowing this, we can substitute into the formula. We get

$A = 24\text{in} \cdot 8\text{in}$

$A = 196\text{in}^2$

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Example Question #48 : Rectangles

Find the area of a rectangle with a width of 6in and a length that is four times the width.

Possible Answers:

$96\text{in}^2$

$121\text{in}^2$

$48\text{in}^2$

$136\text{in}^2$

$144\text{in}^2$

Correct answer:

$144\text{in}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$A = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, we know the width of the rectangle is 6in. We also know the length is four times the width. Therefore, the length is 24in.

Knowing this, we can substitute into the formula. We get

$A = 24\text{in} \cdot 6\text{in}$

$A = 144\text{in}^2$

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Example Question #49 : Rectangles

Find the area of a rectangle with a length of 21in and a width that is a third of the length.

Possible Answers:

$126\text{in}^2$

$84\text{in}^2$

$147\text{in}^2$

$49\text{in}^2$

$63\text{in}^2$

Correct answer:

$147\text{in}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$A = l \cdot w$

where l is the length and w is the width of the rectangle.

We know the length of the rectangle is 21in. We also know the width of the rectangle is a third of the length. Therefore, the width is 7in.

Knowing this, we can substitute into the formula. We get

$A = 21\text{in} \cdot 7\text{in}$

$A = 147\text{in}^2$

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Example Question #51 : How To Find The Area Of A Rectangle

Use the following rectangle to answer the question:

Rectangle1

Find the area.

Possible Answers:

$9\text{in}^2$

$18\text{in}^2$

$36\text{in}^2$

$24\text{in}^2$

$15\text{in}^2$

Correct answer:

$18\text{in}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$A = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, given the rectangle

Rectangle1

we can see the length is 6in and the width is 3in. Knowing this, we can substitute into the formula. So, we get

$A = 6\text{in} \cdot 3\text{in}$

$A = 18\text{in}^2$

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Example Question #51 : How To Find The Area Of A Rectangle

Find the area of a rectangle with a length of 16in and a width that is a quarter of the length.

Possible Answers:

$20\text{in}^2$

$40\text{in}^2$

$4\text{in}^2$

$36\text{in}^2$

$64\text{in}^2$

Correct answer:

$64\text{in}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$A = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, we know the length of the rectangle is 16in.

We know the width is a quarter of the length. So, we will divide the length by 4. Therefore, the width is 4in.

So, we can substitute.

$A = 16\text{in} \cdot 4\text{in}$

$A = 64\text{in}^2$

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Example Question #211 : Plane Geometry

Find the area of a rectangle with a length of 16in and a width that is half the length.

Possible Answers:

$144\text{in}^2$

$64\text{in}^2$

$32\text{in}^2$

$96\text{in}^2$

$128\text{in}^2$

Correct answer:

$128\text{in}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$A = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, we know the length of the rectangle is 16in. We know the width is half the length. Therefore, the width is 8in. So, we can substitute. We get

$A = 16\text{in} \cdot 8\text{in}$

$A =128\text{in}^2$

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Example Question #54 : How To Find The Area Of A Rectangle

Find the area of a rectangle with a length of 20in and a width that is a quarter of the length.

Possible Answers:

$80\text{in}^2$

$50\text{in}^2$

$20\text{in}^2$

$100\text{in}^2$

$75\text{in}^2$

Correct answer:

$100\text{in}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$A = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, we know the length of the rectangle is 20in. We know the width is a quarter of the length. So, we will divide by 4. Therefore, the width is 5in. So, we can substitute. We get

$A = 20\text{in} \cdot 5\text{in}$

$A = 100\text{in}^2$

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Example Question #55 : How To Find The Area Of A Rectangle

Find the area of a rectangle with a length of 10in and a width that is half the length.

Possible Answers:

$30\text{in}^2$

$20\text{in}^2$

$25\text{in}^2$

$50\text{in}^2$

$45\text{in}^2$

Correct answer:

$50\text{in}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$A = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, we know the length of the rectangle is 10in. We also know the width of the rectangle is half the length. Therefore, the width is 5in. So, we get

$A = 10\text{in} \cdot 5\text{in}$

$A = 50\text{in}^2$

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Example Question #56 : How To Find The Area Of A Rectangle

Find the area of a rectangle with a length of 16cm and a width that is a quarter of the length.

Possible Answers:

$64\text{cm}^2$

$62\text{cm}^2$

$31\text{cm}^2$

$128\text{cm}^2$

$32\text{cm}^2$

Correct answer:

$64\text{cm}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$A = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, we know the length of the rectangle is 16cm. We also know the width of the rectangle is a quarter of the length. To find the width, we will divide 16 by 4. Therefore, the width the 4cm.

Knowing this, we will substitute into the formula. We get

$A = 16\text{cm} \cdot 4\text{cm}$

$A = 64\text{cm}^2$

Report an Error

Example Question #51 : Rectangles

Find the area of a rectangle with the base of 12 and a height of 7.

Possible Answers:

Correct answer:

Explanation:

The area of a rectangle is:

$A_{rectangle} = bh$

Substitute the known lengths.

$A_{rectangle} = (12)(7) = 84$

The answer is:

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All ISEE Middle Level Math Resources

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ISEE Middle Level Math : Quadrilaterals

Study concepts, example questions & explanations for ISEE Middle Level Math

All ISEE Middle Level Math Resources

Example Questions

Example Question #47 : Rectangles

Example Question #48 : Rectangles

Example Question #49 : Rectangles

Example Question #51 : How To Find The Area Of A Rectangle

Example Question #51 : How To Find The Area Of A Rectangle

Example Question #211 : Plane Geometry

Example Question #54 : How To Find The Area Of A Rectangle

Example Question #55 : How To Find The Area Of A Rectangle

Example Question #56 : How To Find The Area Of A Rectangle

Example Question #51 : Rectangles

All ISEE Middle Level Math Resources

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