Call Now to Set Up Tutoring:

(888) 888-0446

ISEE Middle Level Math : How to find the solution to an equation

Study concepts, example questions & explanations for ISEE Middle Level Math

Create An Account

All ISEE Middle Level Math Resources

6 Diagnostic Tests 303 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #607 : Algebraic Concepts

Which of the following makes this equation true:

8x+8=72

Possible Answers:

x=9

x=8

x=4

x=6

x=7

Correct answer:

x=8

Explanation:

To answer the question, we will solve for x.

8x+8=72

8x+8-8=72-8

8x+0=64

8x=64

$\frac{8x}{8} = \frac{64}{8}$

x=8

Report an Error

Example Question #401 : How To Find The Solution To An Equation

Solve for y in the following equation:

7y-8=48

Possible Answers:

y=6

y=4

y=7

y=8

y=9

Correct answer:

y=8

Explanation:

To solve, we want y to stand alone. We get

7y-8=48

7y-8+8=48+8

7y-0=56

7y=56

$\frac{7y}{7} = \frac{56}{7}$

y=8

Report an Error

Example Question #609 : Algebraic Concepts

Which of the following makes this equation true:

3s + 12 = 36

Possible Answers:

s=2

s=4

s=1

s=6

s=8

Correct answer:

s=8

Explanation:

To answer the question, we will solve for s. So, we get

3s + 12 = 36

3s+12-12=36-12

3s+0=24

3s=24

$\frac{3s}{3} = \frac{24}{3}$

s=8

Report an Error

Example Question #401 : Equations

Solve for j in the following equation:

6j - 8 = 34

Possible Answers:

j=8

j=6

j=5

j=7

j=4

Correct answer:

j=7

Explanation:

To solve for j, we want j to stand alone. So, we get

6j - 8 = 34

6j-8+8=34+8

6j-0=42

6j=42

$\frac{6j}{6} = \frac{42}{6}$

j=7

Report an Error

Example Question #2721 : Isee Middle Level (Grades 7 8) Mathematics Achievement

Solve for h in the following equation:

$\frac{h}{9} = 13$

Possible Answers:

h = 108

h = 117

h = 37

h = 4

h = 21

Correct answer:

h = 117

Explanation:

To solve for h, we want h to stand alone.

So, we get

$\frac{h}{9} = 13$

$\frac{h}{9} \cdot 9 = 13 \cdot 9$

h = 117

Report an Error

Example Question #2722 : Isee Middle Level (Grades 7 8) Mathematics Achievement

Determine the solution to the following equation: 3x-9 = 2x-5

Possible Answers:

$\frac{4}{5}$

Correct answer:

Explanation:

Group the x-terms on one side of the equation, and the integers on the other side.

Subtract on both sides.

3x-9 -(2x)= 2x-5-(2x)

x- 9 = -5

Add 9 on both sides.

x- 9+9 = -5+9

The answer is: x=4

Report an Error

Example Question #611 : Algebraic Concepts

Which of the following makes this equation true:

5x+3=23

Possible Answers:

x=6

x=5

x=3

x=4

x=7

Correct answer:

x=4

Explanation:

To answer the question, we will solve for x. We get

5x+3=23

5x+3-3=23-3

5x+0=20

5x=20

$\frac{5x}{5} = \frac{20}{5}$

x=4

Report an Error

Example Question #612 : Algebraic Concepts

Solve for $\small m$ .

$\small 2m-4=6$

Possible Answers:

$\small m=7$

$\small m=3$

$\small m=6$

$\small m=5$

$\small m=4$

Correct answer:

$\small m=5$

Explanation:

To solve for $\small m$ , we must isolate the variable.

The first step is to add four to each side, so we are left with

$\small 2m=10$ .

Finally, divide each side by 2 and we are left with

$\small m=5$ .

Report an Error

Example Question #615 : Algebraic Concepts

Solve for $\small a$ .

$\small 3a+5=35$

Possible Answers:

$\small a=5$

$\small a=3$

$\small a=10$

$\small a=6$

$\small a=8$

Correct answer:

$\small a=10$

Explanation:

To solve for $\small p$ , we must isolate the variable.

The first step is to subtract 5 from each side, so we are left with

$\small 3p=30$ .

Finally, divide each side by 3 and we are left with

$\small p=10$ .

Report an Error

Example Question #403 : How To Find The Solution To An Equation

Solve for $\small d$ .

$\small 3d+2=d+4$

Possible Answers:

$\small d=1$

$\small d=2$

$\small d=3$

$\small d=4$

$\small d=0$

Correct answer:

$\small d=1$

Explanation:

To solve for $\small d$ , we must get the variable by itself.

The first step is to subtract 2 from both sides of the equation, so we are left with

$\small 3d=d+2$ .

Then we subtract $\small d$ from both sides of the equation, so we are left with

$\small 2d=2$ .

Finally, we divide each side by 2 and are left with

$\small d=1$ .

Report an Error

View Tutors

Joseph
Certified Tutor

Bank Street College of Education , Master's/Graduate, Early Childhood and Childhood General Education.

View Tutors

Gregory
Certified Tutor

Pennsylvania State University-Main Campus, Bachelor of Science, Chemical Engineering. Carnegie Mellon University, Doctor of P...

View Tutors

Robert
Certified Tutor

University of North Carolina at Chapel Hill, Bachelor in Arts, English. North Carolina Central University, Master of Arts, En...

All ISEE Middle Level Math Resources

6 Diagnostic Tests 303 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

ACT Tutors in New York City, Biology Tutors in New York City, Computer Science Tutors in Philadelphia, Calculus Tutors in Houston, ISEE Tutors in Chicago, SAT Tutors in Phoenix, English Tutors in Seattle, SSAT Tutors in New York City, English Tutors in Philadelphia, SSAT Tutors in San Diego

Popular Courses & Classes

ISEE Courses & Classes in San Francisco-Bay Area, LSAT Courses & Classes in Los Angeles, Spanish Courses & Classes in San Diego, GRE Courses & Classes in San Diego, SSAT Courses & Classes in Houston, ACT Courses & Classes in New York City, Spanish Courses & Classes in Chicago, SAT Courses & Classes in Washington DC, SAT Courses & Classes in Seattle, ISEE Courses & Classes in Philadelphia

Popular Test Prep

GMAT Test Prep in Houston, GRE Test Prep in New York City, GRE Test Prep in San Francisco-Bay Area, LSAT Test Prep in San Francisco-Bay Area, SAT Test Prep in Seattle, LSAT Test Prep in Chicago, LSAT Test Prep in Seattle, GMAT Test Prep in Philadelphia, LSAT Test Prep in Dallas Fort Worth, SSAT Test Prep in Seattle

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

ISEE Middle Level Math : How to find the solution to an equation

Study concepts, example questions & explanations for ISEE Middle Level Math

All ISEE Middle Level Math Resources

Example Questions

Example Question #607 : Algebraic Concepts

Example Question #401 : How To Find The Solution To An Equation

Example Question #609 : Algebraic Concepts

Example Question #401 : Equations

Example Question #2721 : Isee Middle Level (Grades 7 8) Mathematics Achievement

Example Question #2722 : Isee Middle Level (Grades 7 8) Mathematics Achievement

Example Question #611 : Algebraic Concepts

Example Question #612 : Algebraic Concepts

Example Question #615 : Algebraic Concepts

Example Question #403 : How To Find The Solution To An Equation

All ISEE Middle Level Math Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: