To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$\displaystyle A=4\times 4$            $\displaystyle A=12\times 3$

$\displaystyle A=16in^2$           $\displaystyle A=36in^2$

To find our final answer, we need to add the areas together. 

$\displaystyle 16in^2+36in^2=52in^2$

To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$\displaystyle A=9\times 6$            $\displaystyle A=7\times 5$

$\displaystyle A=54in^2$           $\displaystyle A=35in^2$

To find our final answer, we need to add the areas together. 

$\displaystyle 54in^2+35in^2=89in^2$

To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$\displaystyle A=11\times 3$            $\displaystyle A=3\times 3$

$\displaystyle A=33in^2$           $\displaystyle A=9in^2$

To find our final answer, we need to add the areas together. 

$\displaystyle 33in^2+9in^2=42in^2$

To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$\displaystyle A=7\times 3$            $\displaystyle A=5\times 2$

$\displaystyle A=21in^2$           $\displaystyle A=10in^2$

To find our final answer, we need to add the areas together. 

$\displaystyle 21in^2+10in^2=31in^2$

To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$\displaystyle A=4\times 4$            $\displaystyle A=3\times 2$

$\displaystyle A=16in^2$           $\displaystyle A=6in^2$

To find our final answer, we need to add the areas together. 

$\displaystyle 16in^2+6in^2=22in^2$

To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$\displaystyle A=7\times 9$            $\displaystyle A=8\times 6$

$\displaystyle A=63in^2$           $\displaystyle A=48in^2$

To find our final answer, we need to add the areas together. 

$\displaystyle 63in^2+48in^2=111in^2$

To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$\displaystyle A=8\times 4$            $\displaystyle A=7\times 4$

$\displaystyle A=32in^2$           $\displaystyle A=28in^2$

To find our final answer, we need to add the areas together. 

$\displaystyle 32in^2+28in^2=60in^2$

To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$\displaystyle A=9\times 4$            $\displaystyle A=8\times 5$

$\displaystyle A=36in^2$           $\displaystyle A=40in^2$

To find our final answer, we need to add the areas together. 

$\displaystyle 36in^2+40in^2=76in^2$

To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$\displaystyle A=11\times 10$            $\displaystyle A=10\times 5$

$\displaystyle A=110in^2$           $\displaystyle A=50in^2$

To find our final answer, we need to add the areas together. 

$\displaystyle 110in^2+50in^2160in^2$

To find the area of the figure above, we need to slip the figure into two rectangles. 

$\displaystyle A=8\times 6$            $\displaystyle A=6\times 4$

$\displaystyle A=48in^2$           $\displaystyle A=24in^2$

To find our final answer, we need to add the areas together. 

$\displaystyle 48in^2+24in^2=72in^2$