HSPT Math : Concepts

Study concepts, example questions & explanations for HSPT Math

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Example Questions

Example Question #691 : Concepts

Simplify:

Possible Answers:

The expression is undefined

Correct answer:

Explanation:

Any non-zero number raised to the power of zero is equal to .

Example Question #692 : Concepts

Simplify:

Possible Answers:

Correct answer:

Explanation:

We can apply the power of a power property:

Example Question #51 : How To Multiply Variables

Simplify:

Possible Answers:

Correct answer:

Explanation:

We can first apply the power of a product rule and then apply the power of a power rule. So we can write:

Example Question #52 : How To Multiply Variables

Simplify:

Possible Answers:

None of these

Correct answer:

Explanation:

We can solve it using the pattern for the square of a binominal or by using FOIL:

Example Question #53 : How To Multiply Variables

Simplify:

Possible Answers:

None of these

Correct answer:

Explanation:

We can solve it using the pattern for the square of a binominal or by using FOIL:

Example Question #53 : How To Multiply Variables

At Bess's candy warehouse, she charges M for the first 5 pounds of candy that customers buy and P for each additional pound of candy. What is the cost of buying 128 ounces of candy from Bess's warehouse? (*Note: there are 16 ounces in a pound.)

Possible Answers:

Correct answer:

Explanation:

The first step is the convert ounces into pounds. Given that there are 16 ounces in a pound, there are 8 pounds in 128 ounces because 128 divided by 16 eequals 8. 

Since the first 5 pounds cost M, and each additional pound costs P, there are 3 additional pounds that will have to be paid for at the P price per pound. Thus, the appropriate formula to express the value of the cost of 128 ounces of candy (8 pounds) is:

Example Question #1 : How To Subtract Variables

Simplify:

Possible Answers:

Correct answer:

Explanation:

Example Question #1 : Apply Properties Of Operations To Expand Linear Expressions With Rational Coefficients: Ccss.Math.Content.7.Ee.A.1

Simplify:

Possible Answers:

Correct answer:

Explanation:

Example Question #4 : Expressions & Equations

Simplify:

Possible Answers:

Correct answer:

Explanation:

This problem is just a matter of grouping together like terms.  Remember that terms like  are treated as though they were their own, different variable:

The only part that might be a little hard is:

If you are confused, think of your number line.  This is like "going back" (more negative) from 15.  Therefore, you ranswer will be:

Example Question #1 : How To Subtract Variables

Simplify:

Possible Answers:

Correct answer:

Explanation:

This problem really is a trick question.  There are no common terms among any of the parts of the expression to be simplified.  In each case, you have an independent variable or set of variables:  and .  Therefore, do not combine any of the elements!

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