Force is given by the product of mass and acceleration. If an object has a constant velocity, then it has no acceleration.

\(\displaystyle a=\frac{v_2-v_1}{t}\)

\(\displaystyle v_2=v_1\rightarrow a=\frac{0}{t}=0\frac{m}{s^2}\)

If an object has no acceleration, then it must also have no net force.

\(\displaystyle F=ma\)

\(\displaystyle F=m*0\frac{m}{s}\)

\(\displaystyle F=0N\)

No additional information is needed to solve this question.

Since the object is moving with a constant velocity, it has no acceleration. Acceleration is only produced by a change in the velocity.

\(\displaystyle a=\frac{\Delta v}{\Delta t}\)

\(\displaystyle \Delta v=0\frac{m}{s}\rightarrow a=\frac{0\frac{m}{s}}{\Delta t}=0\frac{m}{s^2}\)

If acceleration is zero, no force is produced. This conclusion comes from Newton's second law:

\(\displaystyle F=ma\)

Since the acceleration is zero:

\(\displaystyle F=m*0\frac{m}{s^2}\)

\(\displaystyle F=0N\)

Newton's second law states that:

\(\displaystyle F=ma\)

We are told that the force on the object remains constant, even after it breaks in half. The mass of the broken piece will be equal to half the mass of the total object.

\(\displaystyle F_1=F_2\)

\(\displaystyle m_1=2m_2\)

Using these values, we can set up equations for the initial and final accelerations.

\(\displaystyle a_1=\frac{F_1}{m_1}\)

\(\displaystyle a_2=\frac{F_2}{m_2}=\frac{F_1}{\frac{1}{2}m_1}\)

\(\displaystyle a_2=2\frac{F_1}{m_1}=2a_1\)

\(\displaystyle a_2:a_1=2:1\)

If the force remains constant while the mass is cut in half, the acceleration of the object will double. The ratio of the new acceleration to the old acceleration will be 2:1. If the question asked for the ratio of the old acceleration to the new one, it would be 1:2.

Newton's second law states that:

\(\displaystyle F=ma\)

We are given the mass of the object and the acceleration. Using these values, we can solve for the necessary force.

\(\displaystyle F=5kg*3\frac{m}{s^{2}}\)
\(\displaystyle F=15N\)

If an object is moving with constant velocity, then its acceleration must be zero.

\(\displaystyle a=\frac{v_2-v_1}{t}\)

\(\displaystyle v_2=v_1\rightarrow a=\frac{v-v}{t}=\frac{0}{t}=0\)

We can then look at Newton's second law. If the acceleration is zero, then the net force must also be zero.

\(\displaystyle F=ma\)

\(\displaystyle F=m(0)=0N\)

This means that the gravitational force and normal force cancel out, and the propulsion force of the car cancels out the force of friction. Forces may still be acting in respective directions, but the net sum of these forces is zero.

First we need to find the net force, which will be equal to the sum of the forces on the bone.

\(\displaystyle F_{net}=F_1+F_2\)

Since the forces are going in opposite directions, we know that one force will be negative (since force is a vector). Conventionally, right is assigned a positive directional value. The force to the left will be negative.

\(\displaystyle F_{net}=22N+(-17N)\)

\(\displaystyle F_{net}=5N\)

From here we can use Newton's second law to expand the force and solve for the acceleration, using the mass of the bone.

\(\displaystyle F=ma\)

\(\displaystyle 5N=(0.07kg)a\)

\(\displaystyle \frac{5N}{0.07kg}=a\)

\(\displaystyle 71.4\frac{m}{s^2}=a\)