All High School Physics Resources
Example Questions
Example Question #51 : Circular Motion
A disc has a radius of and is thrown horizontally. If it has an angular velocity of , what is the angular momentum of the disc?
The angular momentum of an object is the moment of inertia times the angular velocity:
We can find our moment of inertia using the given formula:
Plug in the given mass and radius.
Using the value of the moment of inertia and the given angular velocity, we can calculate the angular momentum.
Example Question #201 : Motion And Mechanics
A ball rolls around the edge of a circle with a radius of . If it has a centripial force of acting upon it, what is its speed?
Centripetal force is the force that constantly moves the object towards the center; it is what keeps the object moving in a circle rather than flying off tangentially to the circle.
The formula for force is .
Since we know the mass and the force, we can find the accleration.
Centripetal acceleration is given by the formula , where is the perceived tangential velocity and is the radius of the circle.
Plug in the given values and solve for the velocity.
Example Question #1 : Understanding Springs
A spring has a mass attached to one, which oscillates with a period of . What is the frequency?
The mass has no bearing on the relationship between frequency and period. This relationship is given by the equation:
Given the period, the frequency will be equal to its reciprocal.
Example Question #202 : Motion And Mechanics
A spring with a spring constant of is compressed . How much potential energy has been generated?
The formula for the potential energy in a spring is:
Use the given spring constant and displacement to solve for the stored energy.
Example Question #1 : Harmonic Motion
A mass is placed at the end of a spring. It has a starting velocity of and is allowed to oscillate freely. If the mass has a starting velocity of , what would the period be?
The period would be times as long.
The period would be half as long.
The period would be twice as long.
The period would be as long.
The period would remain the same.
The period would remain the same.
When it comes to the period of a spring, the velocity of the object has no effect.
The equation is .
Example Question #203 : Motion And Mechanics
A spring is attached to a mass, oscillating freely in simple harmonic motion. What change can be made to increase the period of the oscillation?
Lengthen the spring
Use a spring with a greater spring constant
Increase the mass at the end of the spring
Take the spring to a planet with a lower acceleration due to gravity
Decrease the mass at the end of the spring
Increase the mass at the end of the spring
The equation for the period of a spring in simple harmonic motion is:
In this formula, is the mass and is the spring constant. The only two things we can adjust that can change the period, then, are the mass and spring constant. The length of the spring and the acceleration due to gravity are irrelevant.
If we increase the mass we get a larger numerator, which in turns will give us a larger period. If we decrease the mass we get a smaller numerator, which would give us a smaller period. If we use a higher spring constant we get a larger denominator, which also gives us a smaller period.
Example Question #204 : Motion And Mechanics
What does the negative sign indicate in the equation below?
The force, , acts downwards
The spring constant, , is always negative
The force, , acts in the opposite direction of the displacement,
The force, , acts in a negative direction
The force, , acts in the opposite direction of the displacement,
The correct answer is that the force acts in the opposite direction of the displacement.
The equation given is Hooke's law, which is used to determine spring force based on the spring constant, , and the displacement of the spring, .Negative and downward are arbitrary, and spring constants are always positive. If a spring is stretched or compressed in a given direction, the force of the spring will always act opposite the direction of the displacement in order to return the spring to the resting equilibrium position.
Example Question #202 : Motion And Mechanics
A pendulum is dropped from rest at above the ground. If no outside forces (except gravity) are acting upon it, what will be its maximum height on the other side?
Less than
Greater than
If no outside forces act upon the pendulum, it will continue to oscillate back to the original height of .
The proof of this is in the law of conservation of energy. At the top, the pendulum has all potential energy, which is given by the formula . As it swings, the potential energy is converted to kinetic energy until, at the bottommost point, there is only kinetic energy. It then changes direction and begins to rise again. When it rises to the maximum height on the other side, all of its kinetic energy will turn back into potential energy.
Mathematically, the initial and final potential energies are equal.
Notice the masses and gravity can cancel out on both sides, as neither of these will change. This leaves us with only height.
Example Question #1 : Understanding Pendulums
A mass on a string is released and swings freely. Which of the following best explains the energy of the pendulum when the string is perpendicular to the ground?
The mass has maximum potential energy
The mass has mostly potential energy, but there is some kinetic energy
The mass has maximum kinetic energy
The mass has equal amounts of kinetic and potential energy
The mass has mostly kinetic energy, but there is some potential energy
The mass has maximum kinetic energy
Conservation of energy dictates that the total mechanical energy will remain constant. Initially, the mass will not be moving and will be at its highest height. When released, it will begin to travel downward (lose potential energy) and gain velocity (gain kinetic energy). When the mass reaches the bottommost point in the swing, the potential energy will be at a minimum and the kinetic energy will be at a maximum. This point corresponds to the string being perpendicular to the ground.
Example Question #1 : Understanding Pendulums
A man swings a bucket back and forth at the end of a rope, creating a pendulum. What factor could be used to increase the period of the pendulum?
Add water to the bucket
Remove water from the bucket
Use a stronger rope
Move the pendulum to a lower altitude
Increase the length of the rope
Increase the length of the rope
The equation for the period of a pendulum is:
Notice that the material of the pendulum and the mass at the end do not enter into the equation at all. The only things that are capable of affecting the period are are the length of the pendulum and the acceleration due to gravity.
While changing the altitude of the pendulum will change the period, it will do it only slightly unless you take it miles above the earth's crust. Furthermore, decreasing the altitude of the pendulum will increase the force due to gravity, which will resulut in a decreased period. The best answer is to increase the length of the rope. This will increase the period of the pendulum.
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