All High School Physics Resources
Example Questions
Example Question #1 : Understanding Gravity And Weight
The acceleration of gravity on the moon is significantly less than the acceleration of gravity on earth. What will happen to an astronaut's weight and mass on the moon, compared to her weight and mass on Earth?
Her weight and mass will decrease
Her weight will increase, but her mass will decrease
Her weight will remain the same and her mass will decrease
Her weight will decrease and her mass will remain the same
Her weight and mass will remain the same
Her weight will decrease and her mass will remain the same
Mass is a measure of how much matter is in an object, while weight is a measurement of the effective force of gravity on the object.
The amount of matter in the astronaut does not change; therefore, she has the same mass on the moon as she has on Earth.
Her weight, however, will change due to the change in gravity. The force of gravity will be the product of the acceleration and the astronaut's mass.
If the gravity is less on the moon than on Earth, then the force of gravity on the astronaut will also be less on the moon; thus, she will weigh less.
Example Question #5 : Understanding Gravity And Weight
If the mass of the object is and , what is the value of W?
W will be the weight of the object. Weight is a very specific force: it is the mass times gravity. As it turns out, the angle is irrelevant in finding weight.
Using Newton's second law and the given values for mass and gravity, we can solve for W.
Note that the weight is negative, because it is acting in the downward direction.
Example Question #13 : Specific Forces
An astronaut lands on a new planet and discovers her weight on this planet is half of her weight on Earth. What is the acceleration due to gravity on this planet in terms of the acceleration due to gravity on Earth ()?
We need to know her mass in order to solve
Weight is a very specific force, equal to the mass times gravity:
On this new planet her weight is half of what it was on Earth. We can write this mathematically, using the weight equation.
Mass cancels out from each side, leaving a relationship between the gravitational accelerations.
That means the acceleration due to gravity on this new planet is half of what it was on earth.
Example Question #1 : Understanding Gravity And Weight
A ball that weighs on Earth weighs on a recently discovered planet. What is the force of gravity on this new planet?
Give your answer with the correct number of significant figures.
Weight is defined as the force of gravity on an object. We can use Newton's second law to write an equation for weight.
If the ball weighs on Earth, then its mass can be found using this equation and the acceleration of gravity on Earth.
Use this mass and the given weight on the new planet to find the acceleration of gravity on this new planet. Though our initial values (and thus our final values) only allow one significant figure, we will not round until the end of all calculations. This ensures that we preserve accuracy before adjusting for precision.
Adjust this value to one significant figure by rounding up. The zero in the tens place is before the decimal, and is not considered significant.
Example Question #22 : Specific Forces
An object is placed in the direct center of the Earth. What would be the perceived weight of the object?
The object would have no weight
The object would have infinite weight downward
The object would have infinite weight upward
The weight of the object would be equal to its weight at the Earth's surface
We must know the mass of the object to draw a conclusion
The object would have no weight
We must use Newton's law of universal gravitation to solve this question.
There are three variables that really change the force of gravity: the mass of each object and the distance between the bodies.
The important thing to recognize here, though, is that when an object is in the center of the earth, the mass of the earth is distributed symmetrically all around it. It's like being in the center of a giant bubble. Because the mass is symmetrically distributed, the mass that is trying to pull the object in each direction is equal. Essentially, the mass pulling upward cancels out the mass pulling downward, and the mass pulling right cancels out the mass pulling left.
This happens for the entirety of the circle, leaving you with a net force of zero acting upon the object.
Example Question #23 : Specific Forces
A satellite is in orbit above the Earth. What is the relationship between the acceleration due to gravity on the satellite, versus the acceleration due to gravity on the Earth's surface?
We would need to know the mass of the satellite to solve
Acceleration due to gravity on the satellite will be greater than
Acceleration due to gravity on the satellite will be
Acceleration due to gravity on the satellite will be less than
Acceleration due to gravity on the satellite will be equal to
Acceleration due to gravity on the satellite will be less than
For this problem, we are comparing the force of gravity on the surface, or weight, to the force of gravity on the satellite. We can use Newton's second law to find the weight of the satellite, and the law of universal gravitation to find the gravity on the satellite. These two terms will be equal to one another.
Let's call the Earth and the mass of the satellite.
Notice that the masses of the satellite cancel out.
This formula gives us the acceleration of gravity in terms of the mass of the Earth and the distance from the Earth's center. We can write two separate equations, one for the surface and one for the satellite. Since the mass of the Earth doesn't change and is a constant, the only variable that can change is , the distance between the objects.
On Earth, is the radius of the earth. For the satellite, is the radius of the Earth PLUS the orbiting distance; therefore . Because we are dividing by our , a greater gives us a smaller .
The satellite in space will have a smaller acceleration due to gravity. It will not be zero, but it will be smaller than the acceleration on the surface.
Example Question #24 : Specific Forces
A satellite orbits above the Earth. What is the satellite's acceleration due to gravity?
To solve this problem, use the law of universal gravitation.
Remember that is the distance between the centers of the two objects. That means it will be equal to the radius of the earth PLUS the orbiting distance.
Use the given values for the masses of the objects and distance to solve for the force of gravity.
Now that we know the force, we can find the acceleretion. Remember that weight is equal to the mass times acceleration due to gravity.
Set our two forces equal and solve for the acceleration.
Example Question #25 : Specific Forces
A satellite orbits above the Earth. What is the gravitational acceleration on the Earth caused by the satellite?
To solve this problem, use the law of universal gravitation.
Remember that is the distance between the centers of the two objects. That means it will be equal to the radius of the earth PLUS the orbiting distance.
Use the given values for the masses of the objects and distance to solve for the force of gravity.
Now that we know the force, we can find the acceleretion. Remember that weight is equal to the mass times acceleration due to gravity.
.
Set our two forces equal and solve for the acceleration.
Example Question #26 : Specific Forces
A woman stands on the edge of a cliff and drops two rocks, one of mass and one of , from the same height. Which one experiences the greater force?
We need to know the height of the cliff to determine the answer
We need to know the volume of the rocks to determine the answer
The rock with mass
The rock with mass
They both experience the same force
The rock with mass
The formula for force is given by Newton's second law:
Both rocks will experience the same acceleration, , or the acceleration due to gravity.
Use the mass of each rock in this equation to find which rock experiences a greater force.
We can see that the force on the rock with mass of is equal to three times for the force on the rock with mass of . The heavier rock experiences the greater force.
Example Question #27 : Specific Forces
A woman stands on the edge of a cliff and drops two rocks, one of mass and one of , from the same height. Which one experiences the greater acceleration?
We need to know the height of the cliff in order to solve
The rock with mass
They experience the same acceleration
The rock with mass
We need to know the density of the rocks in order to solve
They experience the same acceleration
Even though the rocks have different masses, the acceleration on both will be , the acceleration due to gravity. We can look at Newton's second law to see the force experienced by the rocks:
When objects are in free-fall, the acceleration will be equal to the acceleration from gravity, regardless of the mass of the object.