All High School Physics Resources
Example Questions
Example Question #3 : Understanding Series And Parallel
Two resistors are placed in a circuit. What is the difference in equivalent resistance when the resistors in series versus when they are in parallel?
In series, the equivalent resistance is equal to the sum of each individual resistance. In parallel, the inverse of equivalent resistance is equal to the sum of the inverses of each individual resistance.
We can calculate these two values, and then find the difference between them.
Find the difference:
Example Question #4 : Understanding Series And Parallel
Basic Computational
Six resistors are arranged in a series. Their resistances are , , , , , and . What is their total resistance?
When working in a series, the total resistance is the sum of the individual resistances.
Use the given values for each individual resistor to solve for the total resistance.
Example Question #1 : Understanding Series And Parallel
What is the total resistance of a parallel circuit with resistors of , , and ?
The formula for resistance in parallel is:
We are given the values for each individual resistor, allowing us to solve for the total resistance.
Example Question #3 : Understanding Series And Parallel
Conceptual
When resistors are connected in series
The potential difference across each is the same
More than one of the given answers are true
The current flowing in each is the same
The same power is dissipated in each one
The current flowing in each is the same
In series, there are no branches for the current to travel down. Therefore it is like a one lane highway so the current is the same throughout the entire circuit.
Example Question #4 : Understanding Series And Parallel
When resistors are connected in parallel, we can be certain that
The same current flows in each one
Their equivalent resistance is greater than the resistance of any one of the individual resistances
The potential difference across each is the same
The power dissipated in each is the same
The potential difference across each is the same
Consider a set of parallel resistors that are connected to the battery. Each resistor is on its own loop to the battery. Therefore each resistor has its own potential difference that is equal to the battery. That is why if one bulb goes out in a parallel circuit, the other stays lit. Each resistor has its own connection independent of the others in the circuit.
Example Question #8 : Understanding Series And Parallel
An electric circuit is set up in series with five resistors. If the resistors remain the same, but the circuit is now set up with the resistors in parallel, how would this affect the total resistance?
Resistance would decrease substantially
Resistance would increase substantially
We need to know the numerical values to solve
Resistance would remain unchanged
Resistance would decrease substantially
Think of resistors as doors, preventing the flow of people (electrons). Imagine the following scenarios: a large group of people are in a room and all try to leave at once. If the five resistors are in series, that's like having all of these people trying to go through all five doors before they can leave. In a circuit, all the electrons in the current must pass through every resistor.
If the resistors are in parallel, it's like having five separate doors from the room. All of a sudden, the group can leave MUCH faster, encountering less resistance to their flow out of the room. The path of the electrons can split, allowing each particle to pass through only one resistor.
From a formula perspective, the resistors in series are simply summed together to find the equivalent resistance.
In parallel, however, the reciprocals are summed to find the reciprocal equivalent resistance.
Adding whole numbers will always give you a much greater result than adding fractions. For the exact same set of resistors, arrangement in series will have a greater total resistance than arrangement in parallel.
Example Question #9 : Understanding Series And Parallel
What is the net resistance of the circuit connected to the battery?
To find the net resistance of the circuit, we must summarize all of the different resistors, one piece at a time. To begin, let’s start with the two resistors in the upper left had corner which are in series. In series resistance can be added together. We can replace these two resistors with a single resistor that is valued at .
Next, this new resistor is in parallel with the resistor that is on the diagonal line from point A to point B. In parallel we can add resistors through the equation
This new resistor is now in series with the resistor that is between points B & C. In series we can just add these resistors up.
This new resistor is now in parallel with the resistor that is between points A & C. In parallel we can add resistors through the equation
This new resistor is now in series with the resistor that is between the battery and point C. In series we can just add these resistors up.
Example Question #10 : Understanding Series And Parallel
What is the net resistance of the circuit connected to the battery?
To begin, let us start with the resistor and the resistor that are in parallel. In parallel we can add resistors through the equation
This new resistor is now in series with the two resistors. In series we can just add these resistors up.
This new resistor is now in parallel with the resistor. In parallel we can add resistors through the equation
This new resistor is now in series with the and resistor. In series we can just add these resistors up.
Example Question #21 : Electric Circuits
A closed electric circuit is set up so that there is a resistance of and a voltage of . What is the current in the circuit?
For this problem, use Ohm's law: .
We are given the voltage and the resistance. Using these terms, we can solve for the current.
Example Question #1 : Understanding Voltage In A Circuit
A closed electric circuit is set up so that there is a current of and a resistance of . What is the voltage in the circuit?
For this problem, use Ohm's law: .
We are given the current and the resistance. Using these terms, we can solve for the voltage.