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High School Math : How to find the surface area of a pyramid

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Example Question #3 : Pyramids

What is the surface are of a pyramid with a square base length of 15 and a slant height (the height from the midpoint of one of the side lengths to the top of the pyramid) of 12?

Possible Answers:

575

585

565

555

Correct answer:

585

Explanation:

To find the surface area of a pyramid we must add the areas of all five of the shapes creating the pyramid together.

We have four triangles that all have the same area and a square that supports the pyramid.

To find the area of the square we take the side length of 15 and square it $15^{2}=225$

The area of the square is 225 .

To find the area of the triangle we must use the equation for the area of a triangle which is $\frac{base\times height}{2}$

Plug in the slant height 12 as the height of the triangle and use the side length of the square 15 as the base in our equation to get

$\frac{1}{2}*15*12=90$

The area of each triangle is .

We then multiply the area of each triangle by 4 to find the area of all four triangles 4*90=360 .

The four triangles have a surface area of 360 .

We add the surface area of the four triangles with the area of the square to get the answer for the surface area of the pyramid which is 360+225=585 .

The answer is 585 .

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Example Question #75 : Solid Geometry

Find the surface area of the following pyramid.

Pyramid

Possible Answers:

330m^2

320m^2

340m^2

360m^2

350m^2

Correct answer:

340m^2

Explanation:

The formula for the surface area of a pyramid is:

$SA = 4 \left(A_{triangle}\right)+Base$

$SA = 4 \left(\frac{1}{2}{h_{s}}w\right)+(lw)$

Where h_s is the length of the slant height, is the width of the base, and is the length of the base

In order to determine the areas of the triangle, you will need to use the Pythagorean Theorem to find the slant height:

A^2 + B^2 = C^2

A^2 + (5m)^2 = (13m)^2

A^2 = 144m^2

A = 12m

Plugging in our values, we get:

$SA = 4 \left(\frac{1}{2}\cdot (12m)(10m)\right)+((10m)(10m))$

SA = 240m^2+100m^2 = 340m^2

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Example Question #75 : Solid Geometry

Find the surface area of the following pyramid.

Pyramid

Possible Answers:

326m^2

316m^2

356m^2

336m^2

346m^2

Correct answer:

336m^2

Explanation:

The formula for the surface area of a pyramid is:

$SA = (base)+\frac{1}{2}(perimeter)(slant height)$

$SA = (l)(w) + \frac{1}{2}(l+l+w+w)(h_s)$

Where is the length of the base, is the width of the base, and h_s is the slant height

Use the Pythagorean Theorem to find the length of the slant height:

A^2 + B^2 = C^2

A^2 + (6m)^2 = (10m)^2

A = 8m

Plugging in our values, we get:

$SA = (12m)(12m) + \frac{1}{2}(12m+12m+12m+12m)(8m)$

SA = 336m^2

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Example Question #5 : Pyramids

What is the surface area of a square pyramid with a base side equal to 4 and a slant length equal to 6?

Possible Answers:

Correct answer:

Explanation:

The surface area of of a square pyramid can be determined using the following equation:

SA=2bs+b^2

SA=(2)(6)(4)+4^2

SA=48+16=64

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Example Question #1 : How To Find The Surface Area Of A Pyramid

What is the surface area of a square pyramid with a height of 12 in and a base side length of 10 in?

Possible Answers:

$150 \textup{ in}^{2}$

$360 \textup{ in}^{2}$

$260 \textup{ in}^{2}$

$420 \textup{ in}^{2}$

$100 \textup{ in}^{2}$

Correct answer:

$360 \textup{ in}^{2}$

Explanation:

The surface area of a square pyramid can be broken into the area of the square base and the areas of the four triangluar sides. The area of a square is given by:

$A = s^{2} = 100 in^{2}$

The area of a triangle is:

$A = \frac{1}{2} bh$

The given height of 12 in is from the vertex to the center of the base. We need to calculate the slant height of the triangular face by using the Pythagorean Theorem:

$SH^{2} = H^{2} + B^{2}$

where H=12 and B= 5 (half the base side) resulting in a slant height of 13 in.

So, the area of the triangle is:

$A = \frac{1}{2} bh = \frac{1}{2} \cdot 10 \cdot 13 = 65 in^{2}$

There are four triangular sides totaling $260 in^{2}$ for the sides.

The total surface area is thus $360 in^{2}$ , including all four sides and the base.

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High School Math : How to find the surface area of a pyramid

Study concepts, example questions & explanations for High School Math

All High School Math Resources

Example Questions

Example Question #3 : Pyramids

Example Question #75 : Solid Geometry

Example Question #75 : Solid Geometry

Example Question #5 : Pyramids

Example Question #1 : How To Find The Surface Area Of A Pyramid

All High School Math Resources

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