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High School Math : High School Math

Study concepts, example questions & explanations for High School Math

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8 Diagnostic Tests 613 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #35 : How To Find The Area Of A Circle

To the nearest tenth, give the diameter of a circle with area 100 square inches.

Possible Answers:

$22.6 \textrm{ in}$

$31.4 \textrm{ in}$

$11.3 \textrm{ in}$

$20.0 \textrm{ in}$

$5.7 \textrm{ in}$

Correct answer:

$11.3 \textrm{ in}$

Explanation:

The relationship between the radius and the area of a circle can be given as

$A = \pi r^{2}$ .

We can substitute A = 100 and solve for :

$100= \pi r^{2}$

$r^{2} = \frac{100}{\pi}$

$r=\sqrt{ \frac{100}{\pi}} \approx 5.64$

Double this to get the diameter: $d \approx 5.64 \cdot2 =11.28$ , which we round to 11.3.

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Example Question #35 : Radius

To the nearest tenth, give the area of a circle with diameter $7 \frac{1}{2}$ inches.

Possible Answers:

$88.4 \textrm{ in}^{2}$

$56.3 \textrm{ in}^{2}$

$44.2 \textrm{ in}^{2}$

$22.1 \textrm{ in}^{2}$

$176.7 \textrm{ in}^{2}$

Correct answer:

$44.2 \textrm{ in}^{2}$

Explanation:

The radius of a circle with diameter $7 \frac{1}{2}$ inches is half that, or $3 \frac{3}{4} = 3.75$ inches. The area of the circle is

$A = \pi r^{2} = \pi \cdot 3.75^{2} \approx 44.2 \textrm{ in}^{2}$

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Example Question #221 : High School Math

To the nearest tenth, give the area of a circle with diameter 17 inches.

Possible Answers:

$578.0\textrm{ in}^{2}$

$907.9\textrm{ in}^{2}$

$454.0\textrm{ in}^{2}$

$227.0 \textrm{ in}^{2}$

$289.0 \textrm{ in}^{2}$

Correct answer:

$227.0 \textrm{ in}^{2}$

Explanation:

The radius of a circle with diameter 17 inches is half that, or 8.5 inches. The area of the circle is

$A = \pi r^{2} = \pi \cdot 8.5^{2} \approx 227.0$

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Example Question #92 : Plane Geometry

A circle has a radius of . A second circle has a radius of . What is the ratio of the larger circle's area to the smaller circle's area?

Possible Answers:

$\pi : 1$

10:1

8:1

3:1

5:1

Correct answer:

5:1

Explanation:

The area of a circle is given by the equation $A = \pi r^2$ , where is the area and is the radius of the circle. Use this formula to determine the areas of the two circles:

$A = \pi(15)^2$ and $A = \pi(5)^2$

$\rightarrow A = 125\pi$ units squared and $A = 25\pi$ units squared.

The ratio of the larger circle to the smaller circle is $125\pi:25\pi$ . Divide each side of the ratio by $25\pi$ to express it in its simplest form, 5:1 .

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Example Question #222 : High School Math

What is the area of a circle with a radius of $\sqrt{3}$ ?

Possible Answers:

$6\Pi$

$9\Pi$

$\sqrt{3\Pi }$

$3\Pi$

$\sqrt{3}\Pi$

Correct answer:

$3\Pi$

Explanation:

The equation for the area of a circle is $\Pi r^2$ .

By substituing the given radius of $\sqrt{3}$ into the equation, we get $3\Pi$ .

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Example Question #94 : Plane Geometry

Circlesquare

As illustrated above, a square has one side that is the diameter of a circle. If the area of the square is 100 units, what is the area of the circle?

Possible Answers:

$10\pi$ units squared

$50\pi$ units squared

$100\pi$ units squared

$25\pi$ units squared

$5\pi$ units squared

Correct answer:

$25\pi$ units squared

Explanation:

Find the length of one side of the square by using the formula for the area of a square, A = s^2 , where is the length of one side, with the given information.

A = s^2

$\rightarrow 100 = s^2$

$\rightarrow \sqrt{100} = \sqrt{s^2}$

$\rightarrow s = 10$ units

Since the side of the square forms the diameter of the circle, half of the side will be the length of the circle's radius. The radius is thus calculated as

$\frac{10}{2} = 5$ units.

Now use this radius in the equation for the area of a circle, $A = \pi r^2$ :

$A = \pi(5)^2$

$\rightarrow A = 25\pi$ units squared

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Example Question #221 : High School Math

A 12x16 rectangle is inscribed in a circle. What is the area of the circle?

Possible Answers:

100π

50π

120π

90π

10π

Correct answer:

100π

Explanation:

Explanation: Visualizing the rectangle inside the circle (corners touching the circumference of the circle and the center of the rectangle is the center of the circle) you will see that the rectangle can be divided into 8 congruent right triangles, with the hypotenuse as the radius of the circle. Calculating the radius you divide each side of the rectangle by two for the sides of each right triangle (giving 6 and 8). The hypotenuse (by pythagorean theorem or just knowing right triangle sets) the hypotenuse is give as 10. Area of a circle is given by πr². 10² is 100, so 100π is the area.

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Example Question #223 : High School Math

A circle has a radius of 5 inches. What is the area of the circle in square inches?

Possible Answers:

31.4

78.54

100

Correct answer:

78.54

Explanation:

The area of a circle is found by squaring the circle's radius and multiplying the result by $\pi$ .

$5^{2}=25$

$\pi \cdot 25=78.54$

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Example Question #222 : High School Math

A circle is inscribed in a square whose side is 6 in. What is the difference in area between the square and the circle, rounded to the nearest square inch?

Possible Answers:

$14\ in^{2}$

$8\ in^{2}$

$11\ in^{2}$

$4\ in^{2}$

$12\ in^{2}$

Correct answer:

$8\ in^{2}$

Explanation:

The circle is inscribed in a square when it is drawn within the square so as to touch in as many places as possible. This means that the side of the square is the same as the diameter of the circle.

Let $\pi =3.14$

$A_{square}= s^{2} = (6)^{2} = 36 in^{2}$

$A_{circle}= \pi r^{2}=3.14\cdot3^{2}=3.14\cdot9=28.26 in^{2}$

So the approximate difference is in area $8\ \textup{in}^{2}$

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Example Question #96 : Geometry

Find the area of the shaded region:

Circle

Possible Answers:

$144\pi m^2$

$36\pi m^2$

$256\pi m^2$

$156\pi m^2$

$100\pi m^2$

Correct answer:

$156\pi m^2$

Explanation:

The formula for the area of a circle is:

$A=\pi (r^2)$

where is the radius of the circle.

In order to find the area of the shaded region, you must subtract the area of the inside circle from the area of the outside circle.

Therefore, the formula becomes:

$A=\pi (r_{outside})^2-\pi (r_{inside})^2$

Plugging in our values, we get:

$A=\pi (16m)^2-\pi (10m)^2$

$A=256\pi m^{2}-100\pi m^{2}=156\pi m^2$

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High School Math : High School Math

Study concepts, example questions & explanations for High School Math

All High School Math Resources

Example Questions

Example Question #35 : How To Find The Area Of A Circle

Example Question #35 : Radius

Example Question #221 : High School Math

Example Question #92 : Plane Geometry

Example Question #222 : High School Math

Example Question #94 : Plane Geometry

Example Question #221 : High School Math

Example Question #223 : High School Math

Example Question #222 : High School Math

Example Question #96 : Geometry

All High School Math Resources

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