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High School Math : High School Math

Study concepts, example questions & explanations for High School Math

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All High School Math Resources

8 Diagnostic Tests 613 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #2 : Using Foil

FOIL (x+2)(x-2) .

Possible Answers:

x^2-2x+2

x^2+x-2

x^2+4x+4

x^2-4

x^2+4

Correct answer:

x^2-4

Explanation:

Remember FOIL stands for First Outer Inner Last. That means we can take (x+2)(x-2) and turn it into x^2+2x-2x-4 .

Simplify to get x^2-4 .

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Example Question #42 : Intermediate Single Variable Algebra

FOIL (x+5)^2 .

Possible Answers:

x^2+25

x^2+25x+25

x^2-10x+25

x^2+10x+25

5x^2

Correct answer:

x^2+10x+25

Explanation:

(x+5)^2 is the same thing as (x+5)(x+5) .

Remember that FOIL stands for First Outer Inner Last.

For this problem, that would be x^2+5x+5x+25 .

Simplify that to x^2+10x+25 .

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Example Question #43 : Intermediate Single Variable Algebra

FOIL (x+5)(x-1) .

Possible Answers:

x^2+24

x^2-4x-5

x^2+5x+5

x^2+4x-5

x^2-5

Correct answer:

x^2+4x-5

Explanation:

Remember that FOIL stands for First Outer Inner Last.

For this problem that would give us:

(x+5)(x-1)

x^2-x+5x-5

Simplify.

x^2+4x-5

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Example Question #44 : Intermediate Single Variable Algebra

FOIL (x+2)(x-2) .

Possible Answers:

x^2-4x

x^2+4

-x^2+4

x^2-4

x^2-4x-4

Correct answer:

x^2-4

Explanation:

Remember that FOIL stands for First Outer Inner Last.

For this problem that would give us:

(x+2)(x-2)

=x^2-2x+2x-4

Simplify:

=x^2-4

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Example Question #3 : Using Foil

Solve the equation for .

$\small \frac{1}{x}=\frac{x+1}{6}$

Possible Answers:

$\small x=-3\ or\ 2$

$\small x=3\ or\ -2$

$\small x=-3\ or\ -2$

$\small x=3\ or\ 2$

Correct answer:

$\small x=-3\ or\ 2$

Explanation:

$\small \small \frac{1}{x}=\frac{x+1}{6}$

Cross multiply.

$\small 6=x(x+1)$

$\small 6=x^2+x$

Set the equation equal to zero.

$\small 0=x^2+x-6$

Factor to find the roots of the polynomial.

3*-2=-6 and 3+(-2)=1

$\small 0=(x+3)(x-2)$

$\small 0=x+3; x=-3$

$\small 0=x-2; x=2$

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Example Question #1 : Foil

Evaluate $(2x+3)^{2}$

Possible Answers:

$\dpi{100} \dpi{100} 4x^{2}+9$

$4x^{2}+12x+9$

$\dpi{100} 4x^{3}+12x^{2}+9x$

$\dpi{100} 4x^{2}+9x+9$

$\dpi{100} 4x+12$

Correct answer:

$4x^{2}+12x+9$

Explanation:

In order to evaluate $(2x+3)^{2}$ one needs to multiply the expression by itself using the laws of FOIL. In the foil method, one multiplies in the following order: first terms, outer terms, inner terms, and last terms.

$\dpi{100} (2x+3)^{2}=(2x+3)(2x+3)$

Multiply terms by way of FOIL method.

=(2x*2x)+(2x*3)+(3*2x)+(3*3)

Now multiply and simplify.

$=4x^{2}+6x+6x+9$

$\rightarrow 4x^{2}+12x+9$

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Example Question #11 : Using Foil

Expand (x+7)(x-2) .

Possible Answers:

x^2+5x-14

x^2-5x-14

x^2+7x-2x-7

x^2-14x+5

x^2+9

Correct answer:

x^2+5x-14

Explanation:

To solve our given equation, we need to use FOIL (First, Outer, Inner, Last).

(x+7)(x-2)=x^2-2x+7x-14

Combine like terms.

(x+7)(x-2)=x^2+5x-14

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Example Question #12 : Using Foil

FOIL (x+1)(x-3) .

Possible Answers:

$x^2+2x-\frac{1}{3}$

x^2-4x-3

x^2-2x-3

x^2+3x+4

$x^2+2x-\frac{2}{3}$

Correct answer:

x^2-2x-3

Explanation:

Remember FOIL stands for First Outer Inner Last.

(x+1)(x-3)=x^2+1x-3x-3

Combine like terms to get x^2-2x-3 .

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Example Question #11 : Quadratic Equations And Inequalities

Use the discriminant to determine the nature of the roots:

4x^2-40x+25=0

Possible Answers:

imaginary roots

rational roots

irrational roots

rational root

imaginary root

Correct answer:

irrational roots

Explanation:

The formula for the discriminant is:

b^2 - 4ac

=(-40)^2 - 4(4)(25)

$=1200^{}$

Since the discriminant is positive and not a perfect square, there are irrational roots.

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Example Question #12 : Quadratic Equations And Inequalities

Use the discriminant to determine the nature of the roots:

2y^2+6y+5=0

Possible Answers:

rational root

imaginary root

imaginary roots

irrational roots

rational roots

Correct answer:

imaginary roots

Explanation:

The formula for the discriminant is:

b^2 - 4ac

=(6)^2 - 4(2)(5)

=-4

Since the discriminant is negative, there are imaginary roots.

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All High School Math Resources

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High School Math : High School Math

Study concepts, example questions & explanations for High School Math

All High School Math Resources

Example Questions

Example Question #2 : Using Foil

Example Question #42 : Intermediate Single Variable Algebra

Example Question #43 : Intermediate Single Variable Algebra

Example Question #44 : Intermediate Single Variable Algebra

Example Question #3 : Using Foil

Example Question #1 : Foil

Example Question #11 : Using Foil

Example Question #12 : Using Foil

Example Question #11 : Quadratic Equations And Inequalities

Example Question #12 : Quadratic Equations And Inequalities

All High School Math Resources

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