To solve an equation with  we must take the quad root of each side of the equation to get  by itself.

Doing this makes the problem look like $\displaystyle \sqrt[4]{x^{4}}=\sqrt[4]{1296}$

Then we perform the quad root to get the answer.

Remember that $\displaystyle -6^{4}$ can also equal $\displaystyle 1296$ so our answer will be both positive and negative.

The final answer is $\displaystyle x=\pm6$.

To solve an equation with  we must take the quad root of each side of the equation to get  by itself.

Doing this makes the problem look like $\displaystyle \sqrt[4]{x^{4}}=\sqrt[4]{256}$

Then we perform the quad root to get the answer $\displaystyle x=4$

Remember that $\displaystyle -4^{4}$ can also equal $\displaystyle 256$ so our answer will be both positive and negative.

The final answer is $\displaystyle x=\pm 4$.

To solve an equation with  we must take the cube root of each side of the equation to get  by itself.

Doing this makes the problem look like $\displaystyle \sqrt[3]{x^{3}}=\sqrt[3]{729}$

Then we perform the cube root to get the answer $\displaystyle x=9$.

To solve an equation with  we must take the fifth root of each side of the equation to get  by itself.

Doing this makes the problem look like $\displaystyle \sqrt[5]{x^{5}}=\sqrt[5]{32}$.

Then we perform the fifth root to get the answer $\displaystyle x=2$.

The final answer is $\displaystyle x=2$.

To solve an equation with  we must take the cube root of each side of the equation to get  by itself.

Doing this makes the problem look like $\displaystyle \sqrt[3]{x^{3}}=\sqrt[3]{64}$

Then we perform the cube root to get the answer $\displaystyle x=4$.

To solve an equation with  we must take the square root of each side of the equation to get  by itself.

Doing this makes our problem look like $\displaystyle \sqrt{x^{2}}=\sqrt{25}$

Then we perform the square root to get the answer $\displaystyle x=5$

Remember that $\displaystyle -5^{2}$ can also equal $\displaystyle 25$ so our answer will be both positive and negative.

The final answer is $\displaystyle x=\pm5$.

To solve an equation with , take the cube root of each side of the equation:

$\displaystyle \sqrt[3]{x^{3}}=\sqrt[3]{8}$

$\displaystyle x=2$

To solve an equation with , take the fifth root of both sides of the equation:

$\displaystyle \sqrt[5]{x^{5}}=\sqrt[5]{3125}$

$\displaystyle x=5$

We can check our answer by raising it to the fifth power:

$\displaystyle 5^5=3125$

To solve an equation with , take the fourth root of both sides of the equation.

$\displaystyle \sqrt[4]{x^{4}}=\sqrt[4]{2401}$

$\displaystyle x=7$

However, remember that $\displaystyle (-7)^{4}$ is also equal to $\displaystyle 2401$, so the answer is both positive and negative $\displaystyle 7$.

$\displaystyle x=\pm7$

To solve an equation with , take the square root of both sides of the equatio:

$\displaystyle \sqrt{x^{2}}=\sqrt{121}$

$\displaystyle x=11$

However, remember that $\displaystyle (-11)^{2}$ is also equal to $\displaystyle 121$, so the answer is both positive and negative $\displaystyle 11$.

$\displaystyle x=\pm11$