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High School Math : Radius

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Example Questions

Example Question #41 : Radius

A 12x16 rectangle is inscribed in a circle. What is the area of the circle?

Possible Answers:

100π

90π

10π

50π

120π

Correct answer:

100π

Explanation:

Explanation: Visualizing the rectangle inside the circle (corners touching the circumference of the circle and the center of the rectangle is the center of the circle) you will see that the rectangle can be divided into 8 congruent right triangles, with the hypotenuse as the radius of the circle. Calculating the radius you divide each side of the rectangle by two for the sides of each right triangle (giving 6 and 8). The hypotenuse (by pythagorean theorem or just knowing right triangle sets) the hypotenuse is give as 10. Area of a circle is given by πr². 10² is 100, so 100π is the area.

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Example Question #71 : Circles

A circle has a radius of 5 inches. What is the area of the circle in square inches?

Possible Answers:

78.54

31.4

100

Correct answer:

78.54

Explanation:

The area of a circle is found by squaring the circle's radius and multiplying the result by $\pi$ .

$5^{2}=25$

$\pi \cdot 25=78.54$

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Example Question #42 : Radius

A circle is inscribed in a square whose side is 6 in. What is the difference in area between the square and the circle, rounded to the nearest square inch?

Possible Answers:

$11\ in^{2}$

$8\ in^{2}$

$4\ in^{2}$

$12\ in^{2}$

$14\ in^{2}$

Correct answer:

$8\ in^{2}$

Explanation:

The circle is inscribed in a square when it is drawn within the square so as to touch in as many places as possible. This means that the side of the square is the same as the diameter of the circle.

Let $\pi =3.14$

$A_{square}= s^{2} = (6)^{2} = 36 in^{2}$

$A_{circle}= \pi r^{2}=3.14\cdot3^{2}=3.14\cdot9=28.26 in^{2}$

So the approximate difference is in area $8\ \textup{in}^{2}$

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Example Question #96 : Geometry

Find the area of the shaded region:

Circle

Possible Answers:

$144\pi m^2$

$36\pi m^2$

$256\pi m^2$

$156\pi m^2$

$100\pi m^2$

Correct answer:

$156\pi m^2$

Explanation:

The formula for the area of a circle is:

$A=\pi (r^2)$

where is the radius of the circle.

In order to find the area of the shaded region, you must subtract the area of the inside circle from the area of the outside circle.

Therefore, the formula becomes:

$A=\pi (r_{outside})^2-\pi (r_{inside})^2$

Plugging in our values, we get:

$A=\pi (16m)^2-\pi (10m)^2$

$A=256\pi m^{2}-100\pi m^{2}=156\pi m^2$

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Example Question #45 : Radius

Find the area of a circle with a circumference of $16\pi m$ .

Possible Answers:

$48\pi m^2$

$64\pi m^2$

$32\pi m^2$

$52\pi m^2$

$16\pi m^2$

Correct answer:

$64\pi m^2$

Explanation:

The formula for the circumference of a circle is:

$C=2\pi r$ ,

where is the radius of the circle.

To solve for the radius, plug in our existing values:

$16\pi m=2\pi r$

r=8m

The formula for the area of a circle is:

$A=\pi (r)^2$ ,

where is the radius of the circle.

Plugging in our values, we get:

$A=\pi (8m)^2 = 64\pi m^2$

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Example Question #46 : Radius

Find the area of the following circle:

Possible Answers:

$39 \pi\ m^2$

$29 \pi\ m^2$

$59 \pi\ m^2$

$69 \pi\ m^2$

$49 \pi\ m^2$

Correct answer:

$49 \pi\ m^2$

Explanation:

The formula for the area of a circle is

$A = \pi (r)^2$ ,

where is the radius of the circle.

Plugging in our values, we get:

$A = \pi (7\ m)^2$

$A = 49 \pi\ m^2$

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Example Question #231 : High School Math

Two equal circles are cut out of a rectangular sheet of paper with the dimensions 10 by 20. The circles were made to have the greatest possible diameter. What is the approximate area of the paper after the two circles have been cut out?

Figure_2

Possible Answers:

Correct answer:

Explanation:

The length of 20 represents the diameters of both circles. Each circle has a diameter of 10 and since radius is half of the diameter, each circle has a radius of 5. The area of a circle is A = πr² . The area of one circle is 25π. The area of both circles is 50π. The area of the rectangle is (10)(20) = 200. 200 - 50π gives you the area of the paper after the two circles have been cut out. π is about 3.14, so 200 – 50(3.14) = 43.

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Example Question #232 : High School Math

Screen_shot_2013-03-18_at_10.29.01_pm

Kate has a ring-shaped lawn which has an inner radius of 10 feet and an outer radius 25 feet. What is the area of her lawn?

Possible Answers:

525π ft²

275π ft²

125π ft²

175π ft²

325π ft²

Correct answer:

525π ft²

Explanation:

The area of an annulus is

$\pi (R^{2}-r^{2})$

where is the radius of the larger circle, and is the radius of the smaller circle.

$\pi (25^{2}-10^{2})$

$\pi (625-100)$

$525\pi$

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Example Question #233 : High School Math

A 6 by 8 rectangle is inscribed in a circle. What is the area of the circle?

Possible Answers:

$25\pi$

$10\pi$

$4\pi$

$20\pi$

Correct answer:

$25\pi$

Explanation:

The image below shows the rectangle inscribed in the circle. Dividing the rectangle into two triangles allows us to find the diameter of the circle, which is equal to the length of the line we drew. Using a²+b²= c² we get 6²+ 8² = c². c² = 100, so c = 10. The area of a circle is $A=\pi r^2$ . Radius is half of the diameter of the circle (which we know is 10), so r = 5.

$A=\pi *5^2=25\pi$

Diagram_1

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Example Question #234 : High School Math

A park wants to build a circular fountain with a walkway around it. The fountain will have a radius of 40 feet, and the walkway is to be 4 feet wide. If the walkway is to be poured at a depth of 1.5 feet, how many cubic feet of concrete must be mixed to make the walkway?

Possible Answers:

None of the other answers are correct.

$504\pi \ ft^{3}$

$1296\pi \ ft^{3}$

$1936\pi \ ft^{3}$

$336\pi \ ft^{3}$

Correct answer:

$504\pi \ ft^{3}$

Explanation:

The following diagram will help to explain the solution:

Foutain

We are searching for the surface area of the shaded region. We can multiply this by the depth (1.5 feet) to find the total volume of this area.

The radius of the outer circle is 44 feet. Therefore its area is 44²π = 1936π. The area of the inner circle is 40²π = 1600π. Therefore the area of the shaded area is 1936π – 1600π = 336π. The volume is 1.5 times this, or 504π.

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High School Math : Radius

Study concepts, example questions & explanations for High School Math

All High School Math Resources

Example Questions

Example Question #41 : Radius

Example Question #71 : Circles

Example Question #42 : Radius

Example Question #96 : Geometry

Example Question #45 : Radius

Example Question #46 : Radius

Example Question #231 : High School Math

Example Question #232 : High School Math

Example Question #233 : High School Math

Example Question #234 : High School Math

All High School Math Resources

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