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GRE Subject Test: Chemistry : Oxidation-Reduction Analysis

Study concepts, example questions & explanations for GRE Subject Test: Chemistry

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Example Questions

Example Question #291 : Gre Subject Test: Chemistry

Which molecule would be considered a Lewis acid?

Possible Answers:

Cu(s)

$O_{2}$

$OH^{-}$

$NH_{3}$

$Zn^{2+}$

Correct answer:

$Zn^{2+}$

Explanation:

A lewis acid is an electron pair acceptor. $Zn^{2+}$ would be considered a lewis acid based on the definition. Because $Zn^{2+}$ is electron-deficient based on its oxidation number, it is able to accept an electron pair.

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Example Question #11 : Analyzing Reactions

Which of the following would be considered a Lewis base?

Possible Answers:

$CH_{2}Cl_{2}$

$H^{+}$

$Mn^{2+}$

$Br^{-}$

Zn(s)

Correct answer:

$Br^{-}$

Explanation:

A lewis base is an electron pair donor. $Br^{-}$ would be considered a lewis base based on the definition. Because $Br^{-}$ is electron rich based on its oxidation number, it is able to donate an electron pair to an electron deficient ion.

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Example Question #302 : Gre Subject Test: Chemistry

Which of the following types of reactions best describes the following reaction:

$Ce^{4+}+Fe^{2+}\rightarrow\ Ce^{3+}+Fe^{3+}$

Possible Answers:

Redox reaction

Combustion

Catalytic

Double replacement

Combination

Correct answer:

Redox reaction

Explanation:

A redox reaction is also known as an oxidation/reduction reaction. This type of reaction involves the transfer of electrons from on reactant to another. In this reaction, an electron is transferred from $Fe^{2+}$ to $Ce^{4+}$ forming the products $Ce^{3+}$ and $Fe^{3+}$ . The substance that gains an electron is referred to as being reduced. The substance that loses an electron is referred to as being oxidized.

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Example Question #1 : Oxidation Reduction Analysis

What is the oxidation state of manganese in $KMnO_{4}$ ?

Possible Answers:

Correct answer:

Explanation:

In this compound oxygen has an oxidation number of . There are 4 oxygens, therefore the total oxidation number for the oxygens in $KMnO_{4}$ is: $Total\ oxygen\ oxidation\ number=(-2) \times 4=-8$ . Potassium,, is a group 1 metal and has an oxidation number of . The sum of all oxidation number in a neutral compound such as $KMnO_{4}$ is zero. We will give the oxidation number of equal to :

$((-2) \times 4)+(+1)+x=0$

Simplifying the above equation:

(-8)+(+1)+x=0

(-7)+x=0

Rearranging to solve for :

x=+7

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Example Question #31 : Analytical Chemistry

What is the oxidation state of manganese in $K_{3}MnO_{4}$ ?

Possible Answers:

Correct answer:

Explanation:

In this compound oxygen has an oxidation number of . There are 4 oxygens, therefore the total oxidation number for the oxygens in $K_{3}MnO_{4}$ is: $Total\ O\ oxidation\ number=(-2) \times 4=-8$ . Potassium, , is a group 1 metal and has an oxidation number of . There are 3 potassium ions present in $K_{3}MnO_{4}$ , therefore the total oxidation number for the potassium ions is:

$Total\ K\ oxidation\ number=(+1) \times 3=+3$ .The sum of all oxidation number in a neutral compound such as $K_{3}MnO_{4}$ is zero. We will give the oxidation number of equal to :

(-8)+(+3)+x=0

Simplifying the above equation:

(-5)+x=0

Rearranging to solve for :

x=+5

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GRE Subject Test: Chemistry : Oxidation-Reduction Analysis

Study concepts, example questions & explanations for GRE Subject Test: Chemistry

All GRE Subject Test: Chemistry Resources

Example Questions

Example Question #291 : Gre Subject Test: Chemistry

Example Question #11 : Analyzing Reactions

Example Question #302 : Gre Subject Test: Chemistry

Example Question #1 : Oxidation Reduction Analysis

Example Question #31 : Analytical Chemistry

All GRE Subject Test: Chemistry Resources

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