All GRE Subject Test: Chemistry Resources
Example Questions
Example Question #1 : Calibrations And Precision
What is the molar concentration of a 2% by mass solution with a density of ?
By definition, 2% by mass means 2 grams of in every 100 grams of solution. In order to solve this problem, we may assume we are dealing with 100 grams of solution. We can use the density as a conversion factor to determine the volume of solution we are dealing with:
In order to calculate the number of moles of , we need to convert 2 grams of to moles using it's molecular weight. This is because we are assuming we are dealing 100 grams of a 2% solution.
In order to calculate molarity, we need to plug the moles and volumes calculated into the following equation:
Example Question #11 : Analytical Chemistry
Using the calibration curve given, if given the absorbance of 1.51, what would be the concentration?
A calibration curve is a graph that gives the relationship between a measured quantity and an analytical signal. In this question the analytical signal is absorbance and the measured quantity is the concentration. To answer this problem, simply determine where the absorbance value 1.5 is on the y-axis and find what point the x-axis crosses this absorbance.
Example Question #11 : Analytical Chemistry
Determine the percentage yield if the expected yield of in the above reaction is 40.911 grams but the actual yield is 35.322 grams.
In chemistry, percentage yield is a term used to quantify the efficiency of a chemical reaction. In order to calculate this quantity, the value for the actual yield and theoretical yield is needed. The actual yield is the amount of product obtained during a chemical reaction. The theoretical yield is the maximum amount of product possible to be obtain by a chemical reaction which is based on the amount of reactants used. Below is the formula needed to calculate the percentage yield.
Example Question #1 : Other Statistics
0.0031 moles of was reacted with 0.0071 moles of giving an actual yield of 0.1733 grams of . What is the percent yield of this reaction?
is the limiting reactant because based on the equation, and react in a 1:1 mole ratio. However, there is 0.0040 moles more of than present. Therefore the amount of produced is limited by the amount of present in the reaction. Based on the equation, for every 1 mole of reacted, 1 mole of was produced:
Therefore,
Example Question #12 : Analytical Chemistry
Determine the percentage yield if the expected yield of in the above reaction is 1.2124 grams but the actual yield is 0.9749 grams.
In chemistry, percentage yield is a term used to quantify the efficiency of a chemical reaction. In order to calculate this quantity, the value for the actual yield and theoretical yield is needed. The actual yield is the amount of product obtained during a chemical reaction. The theoretical yield is the maximum amount of product possible to be obtain by a chemical reaction which is based on the amount of reactants used. Below is the formula needed to calculate the percentage yield.
Example Question #2 : How To Find Standard Deviation Of A Random Variable
Robert's work schedule for next week will be released today. Robert will work either 45, 40, 25, or 12 hours. The probabilities for each possibility are listed below:
45 hours: 0.3
40 hours: 0.2
25 hours: 0.4
12 hours: 0.1
What is the standard deviation of the possible outcomes?
There are four steps to finding the standard deviation of random variables. First, calculate the mean of the random variables. Second, for each value in the group (45, 40, 25, and 12), subtract the mean from each and multiply the result by the probability of that outcome occurring. Third, add the four results together. Fourth, find the square root of the result.
Example Question #1 : How To Find Standard Deviation Of A Random Variable
We have two independent, normally distributed random variables and such that has mean and variance and has mean and variance . What is the probability distribution of the difference of the random variables, ?
Normal distribution with mean and variance .
Normal distribution with mean and variance .
Normal distribution with mean and variance .
Normal distribution with mean and variance .
Normal distribution with mean and variance .
The mean for any set of random variables is additive in the sense that
The difference is also additive, so we have
This means the mean of is .
The variance is additive when the random variables are independent, which they are in this case. But it's additive in the sense that for any real numbers (even when negative), we have
.
So for this difference, we have
.
So the mean and variance are and , respectively. In addition to that, is normally distributed because the sum or difference of any set of independent normal random variables is also normally distributed.
Example Question #1 : Diagrams, Graphs, And Tables
A researcher performs a Bradford assay to determine the quantity of an unknown protein in his sample. The standard protein returns absorbance values of 0.101, 0.204, 0.302, 0.405 for the respective quantities of 10ug, 20ug, 30ug, and 40ug of protein. The unknown sample returns an absorbance value of 0.265. What is the quantity of protein in the unknown sample?
For this problem we need to determine the equation of our standard curve. This can be done by creating a graph from the data points and determining the slope.
Assuming that a sample of zero concentration will also have zero absorbance, we can find the equation for the line generated by finding the slope.
Pick two points on the line to find the slope. We will use (0,0) and (40,0.405).
Use this equation and the absorbance given in the question to find the concentration of the unknown sample.
Example Question #1 : Diagrams, Graphs, And Tables
Using the graph given, what is the value for the slope of the line?
The slope of the line, , can be calculated by the following equation:
The subscripts are simply the points you chose in the order you arbitrarily chose.The most important thing to do is plug the values into equation in the order you chose them.
To determine the slope of the line we need to use two points on the graph. Assuming the two points chosen correspond to and , plugging these values into the equation gives:
Therefore the slope of the line is equal to
Example Question #12 : Analytical Chemistry
In the above reaction, by what factor would the reaction quotient change if the concentration of were doubled?
No change
For a general chemical equation , where A, B, C, and D are elements and the Greek letters are their coefficients, we have the reaction quotient equation:
We can find the reaction quotient equation for our reaction by substituting the variables.
Notice that the concentration of is in the denominator and is squared, so doubling the concentration of changes the reaction quotient by a factor of one-fourth.
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