Recall that to find the midpoint of two points  and , you use the equation:

.

(It is just like finding the average of the two points, really.)

So, for our equation, we know the following:

You merely need to solve each coordinate for its respective value.

Then, for the y-coordinate:

Therefore, our other point is: 

Recall that to find the midpoint of two points  and , you use the equation:

.

(It is just like finding the average of the two points, really.)

So, for our equation, we know the following:

You merely need to solve each coordinate for its respective value.

Then, for the y-coordinate:

Therefore, our other point is: 

Recall that the midpoint formula is like finding the average of the  and  values for two points.  For two points  and , it is:

For our points, we are looking for .  We know:

We can solve for each of these coordinates separately:

X-Coordinate

Y-Coordinate:

Therefore, our point is 

What is the other endpoint of a line segment with one point that is  and a midpoint of ?

Recall that the midpoint formula is like finding the average of the  and  values for two points.  For two points  and , it is:

For our points, we are looking for .  We know:

We can solve for each of these coordinates separately:

X-Coordinate

Y-Coordinate:

Therefore, our point is 

The midpoint between two given points is found by solving for the average of each of the correlative coordinates of the given points.  That is:

Midpoint = ( (2 + 14)/2 , (18 + 5)/2) = (16/2, 23/2) = (8, 11.5)

To find the midpoint, we add up the corresponding coordinates and divide by 2.  

[1 + –3] / 2 = –1

[3 + 1] / 2 = 2

[7 + 3] / 2 = 5

Then the midpoint is (–1,2,5).

This is the definition of a bisector. 

A midpoint is the point on a line that divides it into two equal parts. The bisector cuts the line at the midpoint, but the midpoint is not a line.

A transversal is a line that cuts across two or more lines that are usually parallel. 

Parallel line and horizontal line don't make sense as answer choices here. The answer is bisector.

switch 4x+ 3y = 6 to "y=mx+b" form

3y= -4x + 6

y = -4/3 x + 2

m = -4/3; the perpendicular line will have the negative reciprocal of this line so it would be 3/4

The line will be perpendicular if the slope is the negative reciprocal.

First we need to find the slope of our line between points (22,24) and (31,4). Slope = rise/run = (24 – 4)/(22 – 31) = 20/–9 = –2.22.

The negative reciprocal of this must be a positive fraction, so we can eliminate y = –3x + 5 (because the slope is negative).

The negative reciprocal of –2.22, and therefore the slope of the perpendicular line, will be –1/–2.22 = .45, so we can also eliminate y = x (slope of 1).

Now let's look at the line between points (9, 5) and (48, 19). This slope = (5 – 19)/(9 – 48) = .358, which is incorrect.

The next answer choice is y = .45x + 10. The slope is .45, which is what we're looking for so this is the correct answer.

To double check, the last answer choice is the line between (4, 7) and (7, 4). This slope = (7 – 4) / (4 – 7) = –1, which is also incorrect.

We first need to recall the following relationships:

Lines with the same slope and same -intercept are really the same line.

Lines with the same slope and different -intercepts are parallel.

Lines with slopes that are negative reciprocals are perpendicular.

Then we identify the slopes of the two lines by comparing the equations to the slope-intercept form , where  is the slope and  is the -intercept. By inspection we see the lines have slopes of  and . Since these are different, the "parallel" and "same line" choices are eliminated. To test if the slopes are negative reciprocals, we take one of the slopes, change its sign, and flip it upside-down. Starting with  and changing the sign gives , then flipping gives . This is the same as the slope of the second line, so the two slopes are negative reciprocals and the lines are perpendicular.