As it is, quantities A and B have different denominators, so making a comparison can be tricky. Making a common denominator will allow for comparison of just the numerators, so that would make a good first step:

Quantity A:

Quantity B:

Disregarding equal denominators, since they'll always have a positive value, compare the numerators. If  is subtracted from quantity A and from quantity B, we're left with  for the former and  for the latter.

Quantity A is greater.

One way to approach this question is to try to reduce the complexity of each quantity. By subtracting the value of Quantity A,  from both A and B, we can make a new comparison:

Quantity A': 

Quantity B': 

Now, it's easy to see that for different values of  Quantity B may be greater, lesser, or equal to Quantity A.

Since  is not restricted in its possible values, the relationship cannot be determined.

To find out how many rhododendrons Rita will need to prune in an hour, we must first find out how many she needs to prune.

If Rhoda can prune  rhododendrons in  hours, then she can prune  in  hours, and if Rhonda can prune  in  hours, she can prune  in  hours.

If this is not readily apparent, it can be found by finding out how many each prunes in one hour, then multiplying by .

Rhoda:

Rhonda: 

Between Rhoda and Rhonda,  of the  rhododendrons can be pruned, leaving  for Rita.

Since she has  hours for the task, her rate of pruning can be found to be:

O is the center of the circle above.

 The length of  is .

Quantity A: The area of the circle.

Quantity B: 

Do not be tricked by this question. It is true that  can be split into halves, each of which are  in length. These halves are not, however, radii to the circle. Since this does not go through the center of the circle, its length is shorter than the diameter. This means that the radius of the circle must be greater than . Now, if it were , the area would be . Since it is larger than , the area must be larger than . Quantity A is larger than quantity B.

Now, we know that the circumference of a circle is:

 or 

This means that the diameter of our circle is must be . Given this, we know that the  must be shorter than , for the diameter is the longer than any chord that does not pass through the center of the circle. Quantity B is larger than quantity A.

We know that the area of a circle can be expressed: a = πr²

If we know that the area is 36π, we can substitute this into said equation and get: 36π = πr²

Solving for r, we get: 36 = r²; (after taking the square root of both sides:) 6 = r

Now, we know that the circuference of a circle is expressed: c = πd.  Since we know that d = 2r (two radii, placed one after the other, make a diameter), we can rewrite the circumference equation to be: c = 2πr

Since we have r, we can rewrite this to be: c = 2π*6 = 12π

Starting with the circle, we need to find the radius in order to get the circumference. Find  by plugging our given area into the equation for the area of a circle:

Then calculate circumference:

 (approximating  as 3.14)

To find the perimeter of the square, we can use  , where  is the perimeter and  is the side length:

, so the circle's circumference is greater.

Based on our information, we know that the 121π = πr²; 121 = r²; r = 11.

Our other circle with half the radius of A has a diameter equal to the radius of A.  Therefore, the circumference of this circle is 11π.  Half of this is 5.5π.  However, since this is a semi circle, it is enclosed and looks like this:

Therefore, we have to include the diameter in the perimeter.  Therefore, the total perimeter of the semi-circle is 5.5π + 11.

Let's compute each value separately. We know that the radii are positive numbers that are greater than or equal to . This means that we do not need to worry about the fact that the area could represent a square of a decimal value like .

Quantity A

Since , we know:

Quantity B

If the diameter is one-fourth the radius of A, we know:

Thus, the radius must be half of that, or .

Now, we need to compute the area of this circle. We know:

Therefore, 

Now, notice that if , Quantity A is larger.

However, if we choose a value like , we have:

Quantity A: 

Quantity B: 

Therefore, the relation cannot be determined!

Since we know that the area of Square  is , we know , where  is the length of one of its sides. From this, we can solve for  by taking the square root of both sides. You will have to do this by estimating upward. Therefore, you know that  is . By careful guessing, you can quickly see that  is . From this, you know that the diameter of your circle must be half of , or  (because it is circumscribed). Therefore, you can draw:

The circumference of this circle is defined as:

 or, for your values:

(You could also compute this from the diameter, but many students just memorize the formula above.)