All GMAT Math Resources
Example Questions
Example Question #592 : Problem Solving Questions
What is the area, to the nearest whole square inch, of a triangle with sides 12, 13, and 15 inches?
None of the other answers are correct.
Use Heron's formula:
where , and
Example Question #1 : Calculating The Area Of An Acute / Obtuse Triangle
Calculate the area of the triangle (not drawn to scale).
In this problem, the base is 12 and the height is 6. Therefore:
Example Question #2 : Calculating The Area Of An Acute / Obtuse Triangle
Note: Figure NOT drawn to scale.
What is the area of the above figure?
More information is needed to answer this question.
The figure is a composite of a rectangle and a triangle, as shown:
The rectangle has area
The triangle has area
The total area of the figure is
Example Question #592 : Gmat Quantitative Reasoning
Which of the following cannot be the measure of the vertex angle of an isosceles triangle?
Each of the other choices can be the measure of the vertex angle of an isosceles triangle.
Each of the other choices can be the measure of the vertex angle of an isosceles triangle.
The only restriction on the measure of the vertex angle of an isosceles triangle is the restriction on any angle of a triangle - that it fall between and , noninclusive. If is any number in that range, each base angle, the two being congruent, will measure , which will fall in the acceptable range.
Since all of these measures fall in that range, the correct response is that all are allowed.
Example Question #2 : Calculating The Area Of An Acute / Obtuse Triangle
What is the area of the triangle on the coordinate plane formed by the -axis and the lines of the equations and ?
The easiest way to solve this is to graph the three lines and to observe the dimensions of the resulting triangle. It helps to know the coordinates of the three points of intersection, which we can do as follows:
The intersection of and the -axis - that is, the line can be found with some substitution:
The lines intersect at
The intersection of and the -axis can be found the same way:
These lines intersect at
The intersection of and can be found via the substitution method:
The lines intersect at
The triangle therefore has these three vertices. It is shown below.
As can be seen, it is a triangle with base 9 and height 12, so its area is
Example Question #3 : Calculating The Area Of An Acute / Obtuse Triangle
What is the area of a triangle on the coordinate plane with its vertices on the points ?
The vertical segment connecting and can be seen as the base of this triangle; this base has length . The height is the perpendicular (horizontal) distance from to this segment, which is 6, the same as the -coordinate of this point. The area of the triangle is therefore
.
Example Question #597 : Problem Solving Questions
Which of the following is the area of a triangle on the coordinate plane with its vertices on the points , where ?
We can view the horizontal segment connecting , and as the base; its length wiill be . The height will be the perpendicular (vertical) distance to this segment from the opposite point , which is , the -coordinate; therefore, the area of the triangle will be half the product of these two numbers, or
.
Example Question #3 : Calculating The Area Of An Acute / Obtuse Triangle
Give the area of a triangle on the coordinate plane with vertices .
This can be illustrated by showing this triangle inscribed inside a rectangle whose vertices are :
The area of the white triangle is the one whose area we calculate. To do this, we need the area of the square:
The area of the red triangle:
The area of the green triangle:
And the area of the beige triangle:
The area of the white triangle will be as follows: