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GED Math : Solving for the Variable

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Example Questions

Example Question #51 : Solving For The Variable

Give the solution set:

4x < 8x + 72

Possible Answers:

$\left \{ x | x<6\right \}$

$\left \{ x | x > 6\right \}$

$\left \{ x | x > -18\right \}$

$\left \{ x | x<-19\right \}$

Correct answer:

$\left \{ x | x > -18\right \}$

Explanation:

Collect the like terms by subtracting from both sides:

4x - 8x < 8x + 72 - 8x

-4x < 72

Isolate on the right by dividing both sides by . Reverse the direction of the inequality symbol, since you are dividing by a negative number:

$\frac{-4x}{-4} > \frac{72}{-4}$

x > -18

The solution set is $\left \{ x | x > -18\right \}$ .

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Example Question #52 : Solving For The Variable

Solve for : 7x-3 = -5-2x

Possible Answers:

$-\frac{8}{9}$

$-\frac{8}{5}$

$\frac{8}{9}$

$\frac{5}{8}$

$-\frac{2}{9}$

Correct answer:

$-\frac{2}{9}$

Explanation:

Add on both sides.

7x-3 +2x= -5-2x+2x

9x-3 = -5

Add three on both sides.

9x-3+3 = -5+3

9x =-2

Divide by 9 on both sides.

$\frac{9x}{9} =\frac{-2}{9}$

The answer is: $-\frac{2}{9}$

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Example Question #101 : Algebra

Solve for : -8x+7 = 9x+1

Possible Answers:

$-\frac{8}{17}$

$-\frac{6 }{17}$

$\frac{6 }{17}$

Correct answer:

$\frac{6 }{17}$

Explanation:

Add on both sides.

-8x+7+8x = 9x+1+8x

7= 17x+1

Subtract 1 from both sides.

7-1= 17x+1-1

6 = 17x

Divide by 17 on both sides.

$\frac{6 }{17}= \frac{17x}{17}$

The answer is: $\frac{6 }{17}$

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Example Question #54 : Solving For The Variable

Solve the for : -3x+5 = -8

Possible Answers:

$\frac{13}{3}$

$-\frac{13}{3}$

Correct answer:

$\frac{13}{3}$

Explanation:

Subtract 5 from both sides.

-3x+5 -5= -8-5

-3x = -13

Divide by negative three on both sides.

$\frac{-3x}{-3} = \frac{-13}{-3}$

The answer is: $\frac{13}{3}$

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Example Question #55 : Solving For The Variable

Which of the following makes this equation true:

8x - 13 = 99

Possible Answers:

x=14

x=12

x=13

x=8

x=9

Correct answer:

x=14

Explanation:

To answer the question, we will solve for x. We get

8x - 13 = 99

8x-13+13=99+13

8x-0=112

8x=112

$\frac{8x}{8} = \frac{112}{8}$

x = 14

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Example Question #56 : Solving For The Variable

Solve for x:

2(x-3 )= -13

Possible Answers:

$\frac{7}{12}$

$\frac{21}{2}$

$\frac{7}{4}$

$-\frac{21}{2}$

$-\frac{7}{2}$

Correct answer:

$-\frac{7}{2}$

Explanation:

Distribute the two with both of the terms inside the binomial.

2x-6 = -13

Add 6 on both sides.

2x-6 +6= -13+6

2x =-7

Divide by 2 on both sides.

$\frac{2x }{2}=\frac{-7}{2}$

The answer is: $-\frac{7}{2}$

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Example Question #102 : Algebra

Solve for .

$\sqrt{3x-3}+2=14$

Possible Answers:

Correct answer:

Explanation:

$\sqrt{3x-3}+2=14$

Start by subtracting from both sides.

$\sqrt{3x-3}=12$

Square both sides of the equation to get rid of the square root.

3x-3=144

Add to both sides of the equation.

3x=147

Divide both sides by .

x=49

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Example Question #108 : Single Variable Algebra

Which of the following makes this equation true:

7h+19=103

Possible Answers:

h=9

h=8

h=19

h=12

h=13

Correct answer:

h=12

Explanation:

To answer the question, we will solve for h. We get

7h+19=103

7h+19-19=103-19

7h+0=84

7h=84

$\frac{7h}{7} = \frac{84}{7}$

h=12

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Example Question #51 : Solving For The Variable

Solve: $3x = -\frac{1}{11}$

Possible Answers:

$-\frac{1}{33}$

$-\frac{11}{3}$

$-\frac{1}{14}$

$-\frac{1}{3}$

$-\frac{3}{11}$

Correct answer:

$-\frac{1}{33}$

Explanation:

To isolate the x-variable, we will need to multiply by one-third on both sides.

$3x \cdot \frac{1}{3}= -\frac{1}{11} \cdot \frac{1}{3}$

The answer is: $-\frac{1}{33}$

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Example Question #102 : Single Variable Algebra

Which of the following makes this equation true:

9x-5=94

Possible Answers:

x=9

x=12

x=11

x=13

x=5

Correct answer:

x=11

Explanation:

To answer the question, we will solve for x. So, we get

9x-5=94

9x-5+5=94+5

9x-0=99

9x=99

$\frac{9x}{9} = \frac{99}{9}$

x=11

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All GED Math Resources

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GED Math : Solving for the Variable

Study concepts, example questions & explanations for GED Math

All GED Math Resources

Example Questions

Example Question #51 : Solving For The Variable

Example Question #52 : Solving For The Variable

Example Question #101 : Algebra

Example Question #54 : Solving For The Variable

Example Question #55 : Solving For The Variable

Example Question #56 : Solving For The Variable

Example Question #102 : Algebra

Example Question #108 : Single Variable Algebra

Example Question #51 : Solving For The Variable

Example Question #102 : Single Variable Algebra

All GED Math Resources

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