We are open Saturday and Sunday!

Call Now to Set Up Tutoring:

(888) 888-0446

GED Math : 3-Dimensional Geometry

Study concepts, example questions & explanations for GED Math

Create An Account

All GED Math Resources

4 Diagnostic Tests 263 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

← Previous 1 2 … 8 9 10 11 12 13 14 15 16 Next →

Example Question #15 : Faces And Surface Area

Find the surface area of a sphere with a radius of 8in.

Possible Answers:

$1024\pi \text{ in}^2$

$512\pi \text{ in}^2$

$384\pi \text{ in}^2$

$64\pi \text{ in}^2$

$256\pi \text{ in}^2$

Correct answer:

$256\pi \text{ in}^2$

Explanation:

To find the surface area of a sphere, we will use the following formula:

$SA = 4 \cdot \pi \cdot r^2$

where r is the radius of the sphere.

Now, we know the radius of the sphere is 8in.

Knowing this, we can substitute into the formula. We get

$SA = 4 \cdot \pi \cdot (8\text{in})^2$

$SA = 4 \cdot \pi \cdot 64\text{in}^2$

$SA = 256 \pi \text{ in}^2$

Report an Error

Example Question #16 : Faces And Surface Area

Sphere

Give the surface area of the above sphere.

Possible Answers:

$28 \pi$

$\frac{28 }{3}\pi$

$28 \pi \sqrt{7}$

$\frac{28 }{3}\pi \sqrt{7}$

Correct answer:

$28 \pi$

Explanation:

Given the radius of a sphere, the surface area can be calculated using the formula

$A = 4 \pi r^{2}$ .

Set $r = \sqrt{7}$ in the formula and evaluate:

$A = 4 \pi ( \sqrt{7})^{2}$

$A = 4 \pi \cdot 7$

$A = 28 \pi$

Report an Error

Example Question #11 : Faces And Surface Area

A cube has a width of 8in. Find the surface area.

Possible Answers:

$128\text{in}^2$

$512\text{in}^2$

$96\text{in}^2$

$200\text{in}^2$

$384\text{in}^2$

Correct answer:

$384\text{in}^2$

Explanation:

To find the surface area of a cube, we will use the following formula:

$SA = 6 \cdot l \cdot w$

where l is the length, and w is the width of the cube.

Now, we know the width of the cube is 8in. Because it is a cube, all sides/lengths are equal. Therefore, the length is also 8in. So, we can substitute. We get

$SAA = 6 \cdot 8\text{in} \cdot 8\text{in}$

$SA = 6 \cdot 64\text{in}^2$

$SA = 384\text{in}^2$

Report an Error

Example Question #18 : Faces And Surface Area

Let $\pi = 3.14$

Find the surface area of a sphere with a radius of 5in.

Possible Answers:

$62.8\text{in}^2$

$125.6\text{in}^2$

$157\text{in}^2$

$78.5\text{in}^2$

$314\text{in}^2$

Correct answer:

$314\text{in}^2$

Explanation:

To find the surface area of a sphere, we will use the following formula:

$SA = 4 \cdot \pi \cdot r^2$

where r is the radius of the sphere.

Now, we know $\pi = 3.14$ . We know the radius of the sphere is 5in. So, we can substitute. We get

$SA = 4 \cdot 3.14 \cdot (5\text{in})^2$

$SA = 4 \cdot 3.14 \cdot 25\text{in}^2$

$SA = 4 \cdot 25\text{in}^2 \cdot 3.14$

$SA = 100\text{in}^2 \cdot 3.14$

$SA = 314\text{in}^2$

Report an Error

Example Question #19 : Faces And Surface Area

Let $\pi = 3.14$

If a sphere has a radius of 3cm, find the surface area.

Possible Answers:

$339.12\text{cm}^2$

$75.36\text{cm}^2$

$18.84\text{cm}^2$

$37.68\text{cm}^2$

$113.04\text{cm}^2$

Correct answer:

$113.04\text{cm}^2$

Explanation:

To find the surface area of a sphere, we will use the following formula:

$SA = 4 \cdot \pi \cdot r^2$

where r is the radius of the sphere.

Now, we know $\pi = 3.14$ . We know the radius of the sphere is 3cm. So, we substitute. We get

$SA = 4 \cdot 3.14 \cdot (3\text{cm})^2$

$SA = 4 \cdot 3.14 \cdot 9\text{cm}^2$

$SA = 4 \cdot 9\text{cm}^2 \cdot 3.14$

$SA = 36\text{cm}^2 \cdot 3.14$

$SA = 113.04\text{cm}^2$

Report an Error

Example Question #20 : Faces And Surface Area

Find the surface area of a cube with a length of 9in.

Possible Answers:

$384\text{in}^2$

$486\text{in}^2$

$729\text{in}^2$

$108\text{in}^2$

$324\text{in}^2$

Correct answer:

$486\text{in}^2$

Explanation:

To find the surface area of a cube, we will use the following formula.

SA = 6a^2

where a is the length of any side of the cube.

Now, we know the length of the cube is 9in. Because it is a cube, all sides/lengths are equal. Therefore, we can use any side of the cube in the formula. So, we get

$SA = 6 \cdot (9\text{in})^2$

$SA = 6 \cdot 81\text{in}^2$

$SA = 486\text{in}^2$

Report an Error

Example Question #21 : Faces And Surface Area

Find the surface area of a cube with a side length of $3\pi$ .

Possible Answers:

$9\pi^4$

$54 \pi ^2$

$18\pi$

$27\pi^2$

$9\pi^2$

Correct answer:

$54 \pi ^2$

Explanation:

Write the formula for the surface area of a cube.

A =6s^2

Substitute the side length into the formula.

$A =6(3\pi)^2 = 6(9\pi ^2)$

The answer is: $54 \pi ^2$

Report an Error

Example Question #692 : Geometry And Graphs

Find the surface area of a cube with a side length of $3\sqrt2$ .

Possible Answers:

$18\sqrt2$

108

$36\sqrt2$

Correct answer:

108

Explanation:

Write the formula for the surface area of a cube.

A =6s^2

Substitute the side.

$A =6(3\sqrt2)^2=6(3\sqrt2)(3\sqrt2) = 6(9)(2)$

The answer is: 108

Report an Error

Example Question #701 : Geometry And Graphs

A cube has a height of 12in. Find the surface area.

Possible Answers:

$144\text{in}^2$

$864\text{in}^2$

$576\text{in}^2$

$720\text{in}^2$

$1728\text{in}^2$

Correct answer:

$864\text{in}^2$

Explanation:

To find the surface area of a cube, we will use the following formula.

SA = 6a^2

where a is the length of any side of the cube.

Now, we know the height of the cube is 12in. Because it is a cube, all sides are equal (this is why we can use any length/side in the formula). So, we will use 12in in the formula. We get

$SA = 6 \cdot (12\text{in})^2$

$SA = 6 \cdot 144\text{in}^2$

$SA = 864\text{in}^2$

Report an Error

Example Question #702 : Geometry And Graphs

Find the surface area of a cube with a length of 11in.

Possible Answers:

$726\text{in}^2$

$44\text{in}^2$

$121\text{in}^2$

$484\text{in}^2$

$66\text{in}^2$

Correct answer:

$726\text{in}^2$

Explanation:

To find the surface area of a cube, we will use the following formula:

SA = 6a^2

where a is any length of the cube. Because a cube has equal lengths, widths, heights, we can use any of those sides in the formula.

Now, we know the length of the cube is 11in. So, we can substitute. We get

$SA = 6 \cdot (11\text{in})^2$

$SA = 6 \cdot 121\text{in}^2$

$SA = 726\text{in}^2$

Report an Error

← Previous 1 2 … 8 9 10 11 12 13 14 15 16 Next →

View Tutors

Dawn
Certified Tutor

University of Oregon, Bachelor in Arts, Biochemistry and Molecular Biology. Johns Hopkins University, Doctor of Philosophy, E...

View Tutors

Alison
Certified Tutor

University of Illinois at Urbana-Champaign, Bachelor of Science, Accounting.

View Tutors

edward
Certified Tutor

University of South Florida-Main Campus, Bachelor in Business Administration, Business Administration and Management.

All GED Math Resources

4 Diagnostic Tests 263 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

Statistics Tutors in Los Angeles, English Tutors in Dallas Fort Worth, GMAT Tutors in Miami, Reading Tutors in San Diego, MCAT Tutors in Denver, GRE Tutors in Washington DC, Statistics Tutors in Seattle, Statistics Tutors in San Francisco-Bay Area, Calculus Tutors in Phoenix, Chemistry Tutors in Miami

Popular Courses & Classes

ACT Courses & Classes in Houston, LSAT Courses & Classes in Seattle, MCAT Courses & Classes in New York City, LSAT Courses & Classes in Washington DC, GMAT Courses & Classes in Chicago, GRE Courses & Classes in Washington DC, Spanish Courses & Classes in Dallas Fort Worth, SAT Courses & Classes in Seattle, ACT Courses & Classes in Los Angeles, GRE Courses & Classes in Miami

Popular Test Prep

GRE Test Prep in Boston, ACT Test Prep in Los Angeles, LSAT Test Prep in Houston, LSAT Test Prep in San Diego, ISEE Test Prep in New York City, ACT Test Prep in New York City, MCAT Test Prep in Denver, ISEE Test Prep in Atlanta, SSAT Test Prep in Boston, GMAT Test Prep in Denver

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

GED Math : 3-Dimensional Geometry

Study concepts, example questions & explanations for GED Math

All GED Math Resources

Example Questions

Example Question #15 : Faces And Surface Area

Example Question #16 : Faces And Surface Area

Example Question #11 : Faces And Surface Area

Example Question #18 : Faces And Surface Area

Example Question #19 : Faces And Surface Area

Example Question #20 : Faces And Surface Area

Example Question #21 : Faces And Surface Area

Example Question #692 : Geometry And Graphs

Example Question #701 : Geometry And Graphs

Example Question #702 : Geometry And Graphs

All GED Math Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: