To do this problem, all we need to do is put the coefficients for each variable into a matrix. The first column will be x values, 2nd column will be y values, and 3rd column will be what the equations are equal to.

It will look like this

\(\displaystyle \begin{bmatrix} x_1 & y_1 &c_1 \\ x_2& y_2& c_2 \end{bmatrix}\)

 where \(\displaystyle x_1,y_1\),\(\displaystyle x_2,y_2\) are coefficients of \(\displaystyle x\) and \(\displaystyle y\) in the first and second equation respectively. \(\displaystyle c_1, c_2\) refer to what the equations are equal to. So after placing the coefficients and what the equations are equal to in a matrix, it will look like the following.

\(\displaystyle \begin{bmatrix} -10 & 4 &9 \\ -1& 16& 4 \end{bmatrix}\)

To do this problem, all we need to do is put the coefficients for each variable into a matrix. The first column will be x values, 2nd column will be y values, and 3rd column will be what the equations are equal to.

It will look like this

\(\displaystyle \begin{bmatrix} x_1 & y_1 &c_1 \\ x_2& y_2& c_2 \end{bmatrix}\)

 where \(\displaystyle x_1,y_1\),\(\displaystyle x_2,y_2\) are coefficients of \(\displaystyle x\) and \(\displaystyle y\) in the first and second equation respectively. \(\displaystyle c_1, c_2\) refer to what the equations are equal to. So after placing the coefficients and what the equations are equal to in a matrix, it will look like the following.

\(\displaystyle \begin{bmatrix} -14 & -1 &-6 \\ 14& 18& 17 \end{bmatrix}\)

To do this problem, all we need to do is put the coefficients for each variable into a matrix. The first column will be x values, 2nd column will be y values, and 3rd column will be what the equations are equal to.

It will look like this

\(\displaystyle \begin{bmatrix} x_1 & y_1 &c_1 \\ x_2& y_2& c_2 \end{bmatrix}\)

 where \(\displaystyle x_1,y_1\),\(\displaystyle x_2,y_2\) are coefficients of \(\displaystyle x\) and \(\displaystyle y\) in the first and second equation respectively. \(\displaystyle c_1, c_2\) refer to what the equations are equal to. So after placing the coefficients and what the equations are equal to in a matrix, it will look like the following.

\(\displaystyle \begin{bmatrix} 10 & -14 &-17 \\ -9& 18& -12 \end{bmatrix}\)

To do this problem, all we need to do is put the coefficients for each variable into a matrix. The first column will be x values, 2nd column will be y values, and 3rd column will be what the equations are equal to.

It will look like this

\(\displaystyle \begin{bmatrix} x_1 & y_1 &c_1 \\ x_2& y_2& c_2 \end{bmatrix}\)

 where \(\displaystyle x_1,y_1\),\(\displaystyle x_2,y_2\) are coefficients of \(\displaystyle x\) and \(\displaystyle y\) in the first and second equation respectively. \(\displaystyle c_1, c_2\) refer to what the equations are equal to. So after placing the coefficients and what the equations are equal to in a matrix, it will look like the following.

\(\displaystyle \begin{bmatrix} -1 & -14 &-1 \\ -5& 8& 9 \end{bmatrix}\)

In order to compute this, we need to multiply each entry by the scalar \(\displaystyle 3\). 

 \(\displaystyle 3\begin{bmatrix} 2 & 4&-2 \\ 1&20 &-4 \end{bmatrix}=\begin{bmatrix} 2\cdot3 & 4\cdot3&-2\cdot3 \\ 1\cdot3&20\cdot3 &-4\cdot3 \end{bmatrix}=\begin{bmatrix} 6 & 12&-6 \\ 3&60 &-12 \end{bmatrix}\)

In order to compute this, we need to multiply each entry by the scalar \(\displaystyle 5\). 

 \(\displaystyle 5\begin{bmatrix} 20 & 4&-3 \\ 2&14 &-1 \end{bmatrix}=\begin{bmatrix} 5\cdot20 & 5\cdot4&5\cdot(-3) \\ 5\cdot2&5\cdot14 &5\cdot(-1) \end{bmatrix}=\begin{bmatrix} 100 & 20&-15 \\ 10&70 &-5 \end{bmatrix}\)

In order to compute this, we need to multiply each entry by the scalar \(\displaystyle -17\). 

 \(\displaystyle -17\begin{bmatrix} -9 & -12&16\\ 0&-7 &10 \end{bmatrix}=\begin{bmatrix} -17\cdot(-9) & -17\cdot(-12)&-17\cdot16 \\ -17\cdot0&-17\cdot-7 &-17\cdot10 \end{bmatrix}=\begin{bmatrix} 153 & 204&-272 \\ 0&119 &-170 \end{bmatrix}\)

In order to compute this, we need to multiply each entry by the scalar \(\displaystyle -19\). 

 \(\displaystyle -19\begin{bmatrix} 4 & 0&17 \\ 7&15 &-9 \end{bmatrix}=\begin{bmatrix} -19\cdot4 & -19\cdot0&-19\cdot17 \\ -19\cdot7&-19\cdot15 &-19\cdot(-9) \end{bmatrix}=\begin{bmatrix} -76& 0&-323 \\ -133&-285 &171 \end{bmatrix}\)

In order to compute this, we need to multiply each entry by the scalar \(\displaystyle 21\). 

 \(\displaystyle 21\begin{bmatrix} 9 & -3&2 \\ 14&0 &14 \end{bmatrix}=\begin{bmatrix} 21\cdot9 & 21\cdot(-3)&21\cdot2 \\ 21\cdot14&21\cdot0 &21\cdot14 \end{bmatrix}=\begin{bmatrix} 189 & -63&42 \\ 294&0 &294 \end{bmatrix}\)

In order to compute this, we need to multiply each entry by the scalar \(\displaystyle 7\). 

 \(\displaystyle 7\begin{bmatrix} 7 & 12&-3 \\ 17&3 &6 \end{bmatrix}=\begin{bmatrix} 7\cdot7 & 7\cdot12&7\cdot(-3) \\ 7\cdot17&7\cdot3 &7\cdot6 \end{bmatrix}=\begin{bmatrix} 49 & 84&-21 \\ 119&21 &42 \end{bmatrix}\)