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Common Core: High School - Geometry : Prove Line and Angle Theorems: CCSS.Math.Content.HSG-CO.C.9

Study concepts, example questions & explanations for Common Core: High School - Geometry

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All Common Core: High School - Geometry Resources

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Example Questions

Example Question #1 : Prove Line And Angle Theorems: Ccss.Math.Content.Hsg Co.C.9

What is the supplement of the complement of $50^{\circ}$ ?

Possible Answers:

$130^{\circ}$

$100^{\circ}$

$40^{\circ}$

$140^{\circ}$

$50^{\circ}$

Correct answer:

$140^{\circ}$

Explanation:

In order to solve this problem, we need to break down each word.

We need to first find the complement of $50^{\circ}$ .

The complement is

90 = x + y

Since we are given an angle of $50^{\circ}$ we can substitute it for , and solve for .

$\\90 = y + 50 \\y = 40$

Now since we need to find the supplement of the answer, we just got.

The supplement is

180 = x + y

Now we simply substitute the answer we just got for $\uptext{x}$ .

$\\180 = y + 40 \\y = 140$

So the answer is $140^{\circ}$ .

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Example Question #71 : Congruence

What is the supplement of the complement of $81^{\circ}$ ?

Possible Answers:

$162^{\circ}$

$81^{\circ}$

$171^{\circ}$

$99^{\circ}$

$9^{\circ}$

Correct answer:

$171^{\circ}$

Explanation:

In order to solve this problem, we need to break down each word.

We need to first find the complement of $81^{\circ}$

The complement is

90 = x + y

Since we are given an angle of $81^{\circ}$ we can substitute it for , and solve for .

$\\90 = y + 81 \\y = 9$

Now since we need to find the supplement of the answer, we just got.

The supplement is

180 = x + y

Now we simply substitute the answer we just got for .

$\\180 = y + 9 \\y = 171$

So the answer is $171^{\circ}$ .

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Example Question #74 : Congruence

What is the supplement of the complement of $40^{\circ}$ ?

Possible Answers:

$80^{\circ}$

$140^{\circ}$

$130^{\circ}$

$50^{\circ}$

$40^{\circ}$

Correct answer:

$130^{\circ}$

Explanation:

In order to solve this problem, we need to break down each word.

We need to first find the complement of $40^{\circ}$ .

The complement is

90 = x + y

Since we are given an angle of $40^{\circ}$ we can substitute it for , and solve for .

$\\90 = y + 40 \\y = 50$

Now since we need to find the supplement of the answer, we just got.

The supplement is

180 = x + y

Now we simply substitute the answer we just got for .

$\\180 = y + 50 \\y = 130$

So the answer is $130^{\circ}$

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Example Question #3 : Prove Line And Angle Theorems: Ccss.Math.Content.Hsg Co.C.9

What is the supplement of the complement of $66^{\circ}$ ?

Possible Answers:

$156^{\circ}$

$66^{\circ}$

$114^{\circ}$

$24^{\circ}$

$132^{\circ}$

Correct answer:

$156^{\circ}$

Explanation:

In order to solve this problem, we need to break down each word.

We need to first find the complement of $66^{\circ}$ .

The complement is

90 = x + y

Since we are given an angle of $66^{\circ}$ we can substitute it for $\uptext{x}$ , and solve for $\uptext{y}$ .

$\\90 = y + 66 \\y = 24$

Now since we need to find the supplement of the answer, we just got.

The supplement is

180 = x + y

Now we simply substitute the answer we just got for .

$\\180 = y + 24 \\y = 156$

So the answer is $156^{\circ}$

Report an Error

Example Question #4 : Prove Line And Angle Theorems: Ccss.Math.Content.Hsg Co.C.9

What is the supplement of the complement of $71^{\circ}$ ?

Possible Answers:

$109^{\circ}$

$19^{\circ}$

$161^{\circ}$

$142^{\circ}$

$71^{\circ}$

Correct answer:

$161^{\circ}$

Explanation:

In order to solve this problem, we need to break down each word.

We need to first find the complement of $71^{\circ}$

The complement is

90 = x + y

Since we are given an angle of $71^{\circ}$ we can substitute it for , and solve for .

$\\90 = y + 71 \\y = 19$

Now since we need to find the supplement of the answer, we just got.

The supplement is

180 = x + y

Now we simply substitute the answer we just got for .

$\\180 = y + 19 \\y = 161$

So the answer is $161^{\circ}$

Report an Error

Example Question #6 : Prove Line And Angle Theorems: Ccss.Math.Content.Hsg Co.C.9

What is the supplement of the complement of $65^{\circ}$ ?

Possible Answers:

$155^{\circ}$

$130^{\circ}$

$65^{\circ}$

$25^{\circ}$

$115^{\circ}$

Correct answer:

$155^{\circ}$

Explanation:

In order to solve this problem, we need to break down each word.

We need to first find the complement of $65^{\circ}$

The complement is

90 = x + y

Since we are given an angle of $65^{\circ}$ we can substitute it for , and solve for .

$\\90 = y + 65 \\y = 25$

Now since we need to find the supplement of the answer, we just got.

The supplement is

180 = x + y

Now we simply substitute the answer we just got for

$\\180 = y + 25 \\y = 155$

So the answer is $155^{\circ}$

Report an Error

Example Question #5 : Prove Line And Angle Theorems: Ccss.Math.Content.Hsg Co.C.9

What is the supplement of the complement of $45^{\circ}$ ?

Possible Answers:

$135^{\circ}$

$90^{\circ}$

$45^{\circ}$

Correct answer:

$135^{\circ}$

Explanation:

In order to solve this problem, we need to break down each word.

We need to first find the complement of $45^{\circ}$

The complement is

90 = x + y

Since we are given an angle of $45^{\circ}$ we can substitute it for , and solve for .

$\\90 = y + 45 \\y = 45$

Now since we need to find the supplement of the answer, we just got.

The supplement is

180 = x + y

Now we simply substitute the answer we just got for

$\\180 = y + 45 \\y = 135$

So the answer is $135^{\circ}$ .

Report an Error

Example Question #8 : Prove Line And Angle Theorems: Ccss.Math.Content.Hsg Co.C.9

What is the supplement of the complement of $76^{\circ}$ ?

Possible Answers:

$76^{\circ}$

$104^{\circ}$

$152^{\circ}$

$14^{\circ}$

$166^{\circ}$

Correct answer:

$166^{\circ}$

Explanation:

In order to solve this problem, we need to break down each word.

We need to first find the complement of $76^{\circ}$

The complement is

90 = x + y

Since we are given an angle of $76^{\circ}$ we can substitute it for , and solve for .

$\\90 = y + 76 \\y = 14$

Now since we need to find the supplement of the answer, we just got.

The supplement is

180 = x + y

Now we simply substitute the answer we just got for .

$\\180 = y + 14 \\y = 166$

So the answer is $166^{\circ}$ .

Report an Error

Example Question #6 : Prove Line And Angle Theorems: Ccss.Math.Content.Hsg Co.C.9

What is the supplement of the complement of $48^{\circ}$ ?

Possible Answers:

$42^{\circ}$

$138^{\circ}$

$48^{\circ}$

$132^{\circ}$

$96^{\circ}$

Correct answer:

$138^{\circ}$

Explanation:

In order to solve this problem, we need to break down each word.

We need to first find the complement of $48^{\circ}$ .

The complement is

90 = x + y

Since we are given an angle of $48^{\circ}$ we can substitute it for , and solve for .

$\\90 = y + 48 \\y = 42$

Now since we need to find the supplement of the answer, we just got.

The supplement is

180 = x + y

Now we simply substitute the answer we just got for .

$\\180 = y + 42 \\y = 138$

So the answer is $138^{\circ}$

Report an Error

Example Question #7 : Prove Line And Angle Theorems: Ccss.Math.Content.Hsg Co.C.9

What is the supplement of the complement of $4^{\circ}$ ?

Possible Answers:

$94^{\circ}$

$4^{\circ}$

$86^{\circ}$

$176^{\circ}$

$8^{\circ}$

Correct answer:

$94^{\circ}$

Explanation:

In order to solve this problem, we need to break down each word.

We need to first find the complement of $4^{\circ}$

The complement is

90 = x + y

Since we are given an angle of $4^{\circ}$ we can substitute it for , and solve for .

$\\90 = y + 4 \\y = 86$

Now since we need to find the supplement of the answer, we just got.

The supplement is

180 = x + y

Now we simply substitute the answer we just got for .

$\\180 = y + 86 \\y = 94$

So the answer is $94^{\circ}$

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Common Core: High School - Geometry : Prove Line and Angle Theorems: CCSS.Math.Content.HSG-CO.C.9

Study concepts, example questions & explanations for Common Core: High School - Geometry

All Common Core: High School - Geometry Resources

Example Questions

Example Question #1 : Prove Line And Angle Theorems: Ccss.Math.Content.Hsg Co.C.9

Example Question #71 : Congruence

Example Question #74 : Congruence

Example Question #3 : Prove Line And Angle Theorems: Ccss.Math.Content.Hsg Co.C.9

Example Question #4 : Prove Line And Angle Theorems: Ccss.Math.Content.Hsg Co.C.9

Example Question #6 : Prove Line And Angle Theorems: Ccss.Math.Content.Hsg Co.C.9

Example Question #5 : Prove Line And Angle Theorems: Ccss.Math.Content.Hsg Co.C.9

Example Question #8 : Prove Line And Angle Theorems: Ccss.Math.Content.Hsg Co.C.9

Example Question #6 : Prove Line And Angle Theorems: Ccss.Math.Content.Hsg Co.C.9

Example Question #7 : Prove Line And Angle Theorems: Ccss.Math.Content.Hsg Co.C.9

All Common Core: High School - Geometry Resources

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