To solve for $\displaystyle x$, first combine like terms.

$\displaystyle x+2x+1=8+4x$

On the left-hand side of the equation there are two terms that contain $\displaystyle x$. Therefore, add $\displaystyle x$ and $\displaystyle 2x$ together.

$\displaystyle 3x+1=8+4x$

Now, move the $\displaystyle x$ term from the left-hand side to the right-hand side. To accomplish this, subtract $\displaystyle 3x$ from both sides.

   $\displaystyle 3x+1=8+4x$

$\displaystyle -3x$                  $\displaystyle -3x$

_____________________

               $\displaystyle 1=8+x$

Next, to isolate $\displaystyle x$, subtract the constant from the right-hand side of the equation to the left-hand side.

    $\displaystyle 1=8+x$

$\displaystyle -8$   $\displaystyle -8$

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$\displaystyle -7=x$

To solve for $\displaystyle x$, first combine like terms.

$\displaystyle 3x-2x+1=8+4x$

On the left-hand side of the equation there are two terms that contain $\displaystyle x$. Therefore, subtract $\displaystyle 2x$ from $\displaystyle 3x$.

$\displaystyle x+1=8+4x$

Now, move the $\displaystyle x$ term from the left-hand side to the right-hand side. To accomplish this, subtract $\displaystyle x$ from both sides.

   $\displaystyle x+1=8+4x$

$\displaystyle -x$                    $\displaystyle -x$

_____________________

           $\displaystyle 1=8+3x$

Next, subtract the constant from the right-hand side of the equation to the left-hand side.

    $\displaystyle 1=8+3x$

$\displaystyle -8$   $\displaystyle -8$

______________

$\displaystyle -7=3x$

Finally divide each side by three to solve for $\displaystyle x$.

$\displaystyle \\\frac{-7}{3}=\frac{3x}{3} \\\\-\frac{7}{3}=x$

To solve for $\displaystyle x$, first combine like terms.

$\displaystyle x+2x+3=8+4x$

On the left-hand side of the equation there are two terms that contain $\displaystyle x$. Therefore, add $\displaystyle x$ and $\displaystyle 2x$ together.

$\displaystyle 3x+3=8+4x$

Now, move the $\displaystyle x$ term from the left-hand side to the right-hand side. To accomplish this, subtract $\displaystyle 3x$ from both sides.

   $\displaystyle 3x+3=8+4x$

$\displaystyle -3x$                  $\displaystyle -3x$

_____________________

               $\displaystyle 3=8+x$

Next, to isolate $\displaystyle x$, subtract the constant from the right-hand side of the equation to the left-hand side.

    $\displaystyle 3=8+x$

 $\displaystyle -8$   $\displaystyle -8$

______________

$\displaystyle -5=x$

To solve for $\displaystyle x$, first combine like terms.

$\displaystyle x+2x+12=8+4x$

On the left-hand side of the equation there are two terms that contain $\displaystyle x$. Therefore, add $\displaystyle x$ and $\displaystyle 2x$ together.

$\displaystyle 3x+12=8+4x$

Now, move the $\displaystyle x$ term from the left-hand side to the right-hand side. To accomplish this, subtract $\displaystyle 3x$ from both sides.

   $\displaystyle 3x+12=8+4x$

$\displaystyle -3x$                     $\displaystyle -3x$

_____________________

               $\displaystyle 12=8+x$

Next, to isolate $\displaystyle x$, subtract the constant from the right-hand side of the equation to the left-hand side.

    $\displaystyle 12=8+x$

 $\displaystyle -8$   $\displaystyle -8$

______________

$\displaystyle 4=x$

To solve for $\displaystyle x$, first combine like terms.

$\displaystyle x+2x+12=9+4x$

On the left-hand side of the equation there are two terms that contain $\displaystyle x$. Therefore, add $\displaystyle x$ and $\displaystyle 2x$ together.

$\displaystyle 3x+12=9+4x$

Now, move the $\displaystyle x$ term from the left-hand side to the right-hand side. To accomplish this, subtract $\displaystyle 3x$ from both sides.

   $\displaystyle 3x+12=9+4x$

$\displaystyle -3x$                     $\displaystyle -3x$

_____________________

               $\displaystyle 12=9+x$

Next, to isolate $\displaystyle x$, subtract the constant from the right-hand side of the equation to the left-hand side.

    $\displaystyle 12=9+x$

 $\displaystyle -9$   $\displaystyle -9$

______________

$\displaystyle 3=x$

To solve for $\displaystyle x$, first combine the like terms on the left-hand side of the equation.

$\displaystyle x-3x+1=x+4$

$\displaystyle x-3x=-2x$

Therefore, the equation becomes,

$\displaystyle -2x+1=x+4$

Now, move all the variables to the right-hand side of the equation by adding $\displaystyle 2x$ to both sides.

$\displaystyle -2x+1=x+4$

$\displaystyle +2x$         $\displaystyle +2x$

____________________

$\displaystyle 1=3x+4$

From here, subtract the constant on the right-hand side from both sides of the equation.

    $\displaystyle 1=3x+4$

$\displaystyle -4$              $\displaystyle -4$

_______________

 $\displaystyle -3=3x$

Lastly, divide by three on both sides of the equation to solve for $\displaystyle x$.

$\displaystyle \\\frac{-3}{3}=\frac{3x}{3} \\\\-1=x$

To solve for $\displaystyle x$, first subtract one from both sides to combine the constant terms.

$\displaystyle \frac{x}{2}+1=3$

     $\displaystyle -1$   $\displaystyle -1$

____________

$\displaystyle \frac{x}{2}=2$

From here, multiply by two on both sides to solve for $\displaystyle x$.

$\displaystyle \\2\times \frac{x}{2}=2\times 2 \\\\x=4$

The two in the numerator cancels the two in the denominator on the left-hand side of the equation; thus, isolating $\displaystyle x$.

To solve for $\displaystyle x$ first combine the constant terms by adding two to both sides of the equation.

$\displaystyle \frac{x}{3}-2=6$

    $\displaystyle +2$   $\displaystyle +2$

_____________

$\displaystyle \frac{x}{3}=8$

From here, multiply each side of the equation by 3 to solve for $\displaystyle x$.

$\displaystyle 3\cdot \frac{x}{3}=8\cdot 3$

The three in the numerator cancels out the three in the denominator on the left-hand side of the equation; thus, solving for $\displaystyle x$.

$\displaystyle x=24$

First, combine like terms on both sides of the equation.

$\displaystyle 3x-2x=7+3+2x$

On the left-hand side:

$\displaystyle \\3x-2x=x \\7+3=10$

Thus the equation becomes,

$\displaystyle x=10+2x$

Now, subtract $\displaystyle 2x$ from both sides.

      $\displaystyle x=10+2x$

$\displaystyle -2x$             $\displaystyle -2x$

__________________

$\displaystyle -x=10$

Lastly, divide by negative one on both sides.

$\displaystyle \frac{-x}{-1}=\frac{10}{-1}$

$\displaystyle x=-10$

First, subtract $\displaystyle x$ from both sides to get the variables on one side.

  $\displaystyle 2x-10=x+7$

$\displaystyle -x$              $\displaystyle -x$

____________________

$\displaystyle x-10=7$

From here, add ten to both sides to get all constants on one side, and solve for $\displaystyle x$.

$\displaystyle x-10=7$

    $\displaystyle +10$  $\displaystyle +10$

_______________

$\displaystyle x=17$