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Flashcards: Interpret Complicated Expressions: CCSS.Math.Content.HSA-SSE.A.1b

Rewrite the following expression.

12x+36 $\displaystyle 12x+36$

12(x-3) $\displaystyle 12(x-3)$

6(2x+3) $\displaystyle 6(2x+3)$

12(x+3) $\displaystyle 12(x+3)$

$\displaystyle 12(x+36)$

2(x+36) $\displaystyle 2(x+36)$

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Flashcards: Interpret Complicated Expressions: CCSS.Math.Content.HSA-SSE.A.1b

Rewrite the following expression.

12x+36 $\displaystyle 12x+36$

12(x-3) $\displaystyle 12(x-3)$

6(2x+3) $\displaystyle 6(2x+3)$

12(x+3) $\displaystyle 12(x+3)$

$\displaystyle 12(x+36)$

2(x+36) $\displaystyle 2(x+36)$

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Flashcards: Interpret Complicated Expressions: CCSS.Math.Content.HSA-SSE.A.1b

Rewrite the following expression.

12x+36 $\displaystyle 12x+36$

Your answer:

12(x-3) $\displaystyle 12(x-3)$

Your answer:

6(2x+3) $\displaystyle 6(2x+3)$

Your answer:

$\displaystyle 12(x+36)$

Your answer:

2(x+36) $\displaystyle 2(x+36)$

Correct answer:

12(x+3) $\displaystyle 12(x+3)$

Explanation:

To rewrite the expression identify common factors that exist in both terms.

First identify the different terms.

$\\\text{Term One}=12x \\\text{Term Two}=36$ $\displaystyle \\\text{Term One}=12x \\\text{Term Two}=36$

Identify the factors of the terms.

$\\\text{Term One Factors}=2\cdot 6x; 1\cdot 12x \\\text{Term Two Factors}=6\cdot 6;3\cdot 12$ $\displaystyle \\\text{Term One Factors}=2\cdot 6x; 1\cdot 12x \\\text{Term Two Factors}=6\cdot 6;3\cdot 12$

Write a new, equivalent expression by factoring out a common term.

12(x+3) $\displaystyle 12(x+3)$

Flashcards: Interpret Complicated Expressions: CCSS.Math.Content.HSA-SSE.A.1b

Rewrite the following expression:

$\displaystyle 7 + (x-2)^2$

$7 + (x-2) \div (x-2)$ $\displaystyle 7 + (x-2) \div (x-2)$

$7 + (x-2) \cdot (x-2)$ $\displaystyle 7 + (x-2) \cdot (x-2)$

$\displaystyle 7 + x^2-4$

$7 \cdot (x-2) \cdot (x-2)$ $\displaystyle 7 \cdot (x-2) \cdot (x-2)$

$7\cdot (x-2)^2$ $\displaystyle 7\cdot (x-2)^2$

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Flashcards: Interpret Complicated Expressions: CCSS.Math.Content.HSA-SSE.A.1b

Rewrite the following expression:

$\displaystyle 7 + (x-2)^2$

Your answer:

$7 + (x-2) \div (x-2)$ $\displaystyle 7 + (x-2) \div (x-2)$

Your answer:

$\displaystyle 7 + x^2-4$

Your answer:

$7 \cdot (x-2) \cdot (x-2)$ $\displaystyle 7 \cdot (x-2) \cdot (x-2)$

Your answer:

$7\cdot (x-2)^2$ $\displaystyle 7\cdot (x-2)^2$

Correct answer:

$7 + (x-2) \cdot (x-2)$ $\displaystyle 7 + (x-2) \cdot (x-2)$

Explanation:

To rewrite the expression, first identify and interpret the individual parts.

Identify the various terms in the expression.

$\displaystyle 7 + (x-2)^2$

$\\\text{Term One}=7 \\\text{Term Two}=(x-2)^2$ $\displaystyle \\\text{Term One}=7 \\\text{Term Two}=(x-2)^2$

Now, recall the general form for exponents.

$\\a^2=a\cdot a \$ax)^3=ax\cdot ax\cdot ax$ \(\displaystyle \\a^2=a\cdot a \\(ax)^3=ax\cdot ax\cdot ax$

From there, expand the second term as follows.

$(x-2)^2=(x-2)\cdot (x-2)$ $\displaystyle (x-2)^2=(x-2)\cdot (x-2)$

From here combine the first term with the expanded second term to result in the final solution.

$7 + (x-2) \cdot (x-2)$ $\displaystyle 7 + (x-2) \cdot (x-2)$

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Flashcards: Interpret Complicated Expressions: CCSS.Math.Content.HSA-SSE.A.1b

All Common Core: High School - Algebra Resources

Flashcards: Interpret Complicated Expressions: CCSS.Math.Content.HSA-SSE.A.1b

Flashcards: Interpret Complicated Expressions: CCSS.Math.Content.HSA-SSE.A.1b

Flashcards: Interpret Complicated Expressions: CCSS.Math.Content.HSA-SSE.A.1b

Flashcards: Interpret Complicated Expressions: CCSS.Math.Content.HSA-SSE.A.1b

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