Convert both dimensions from centimeters to meters by dividing by 100:

Height: 240 centimeters = $\displaystyle 240 \div 100 = 2.4$  meters.

Radius: 80 centimeters = $\displaystyle 80 \div 100 = 0.8$ meters.

Substitute $\displaystyle r = 0.8, h = 2.4$ in the volume formula:

$\displaystyle V = \frac{1}{3} \pi r^{2}h$

$\displaystyle V = \frac{1}{3} \cdot \pi \cdot 0.8 ^{2} \cdot 2.4$

$\displaystyle V = \frac{1}{3}\cdot 0.8 \cdot 0.8 \cdot 2.4 \cdot \pi$

$\displaystyle V =0.512 \pi$

A circle with circumference $\displaystyle 6 \pi$ inches has as its radius 

$\displaystyle r = \frac{C }{2\pi }=\frac{6\pi }{2\pi } = 3$ inches.

The area of the base is therefore

$\displaystyle B = \pi r^{2} = \pi \cdot 3^{2} = 9 \pi$ square inches.

To find the volume of the cone, substitute $\displaystyle B = 9 \pi , h = 10$ in the formula for the volume of a cone:

$\displaystyle V = \frac{1}{3} Bh = \frac{1}{3} \cdot 9 \pi \cdot 10 = 30 \pi$ cubic inches

A circle with circumference $\displaystyle 10 \pi$ inches has as its radius 

$\displaystyle r = \frac{C }{2\pi }=\frac{10\pi }{2\pi } = 5$ inches.

The height is also $\displaystyle 5$ inches, so substitute $\displaystyle h = r = 5$ in the volume formula for a cone:

$\displaystyle V = \frac{1}{3} \pi r ^{2}h = \frac{1}{3} \pi \cdot 5 ^{2} \cdot 5 = \frac{125}{3} \pi$ cubic inches

20 feet = $\displaystyle 20 \times 12 = 240$ inches, the diameter of the tank; half of this, or 120 inches, is the radius. Set $\displaystyle r = 120$, substitute in the volume formula, and solve for $\displaystyle V$:

$\displaystyle V = \frac{4}{3} \pi r^{3}$

$\displaystyle V = \frac{4}{3} \pi \cdot 120^{3}$

$\displaystyle V = \frac{4}{3} \pi \cdot 1,728,000$

$\displaystyle V = 2,304,000 \pi$ cubic inches

The diameter of 3 meters is equal to $\displaystyle 3 \times 100 = 300$ centimeters; the radius is half this, or 150 centimeters. Substitute $\displaystyle r = 150$ in the volume formula:

$\displaystyle V= \frac{4}{3} \pi r^{3}$

$\displaystyle V= \frac{4}{3} \cdot \pi \cdot 150^{3}$

$\displaystyle V= \frac{4}{3} \cdot 150 \cdot 150 \cdot 150\cdot \pi$

$\displaystyle V= \frac{4}{3} \cdot 150 \cdot 150 \cdot 150\cdot \pi$

$\displaystyle V= 4,500,000\pi$ cubic centimeters

The volume of a cone is given by the formula:

$\displaystyle \text{Volume}=\frac{1}{3}\pi r^2h$

Now, plug in the values of the radius and height to find the volume of the given cone.

$\displaystyle \text{Volume}=\frac{1}{3}\pi\times3^2\times12=\frac{1}{3}\pi\times9\times12=\frac{108}{3}\pi=36\pi\:in^3$

In order to solve this problem, we need to recall the formula used to calculate the volume of a cylinder:

$\displaystyle V=\pi r^2h$

Now that we have this formula, we can substitute in the given values and solve:

$\displaystyle V=\pi6^2(8)$

$\displaystyle V=\pi36(8)$

$\displaystyle V=\pi288$

$\displaystyle V=904.78\textup{ in}^3$

In order to solve this problem, we need to recall the formula used to calculate the volume of a cone:

$\displaystyle V=\pi r^2\left ( \frac{h}{3} \right )$

Now that we have this formula, we can substitute in the given values and solve:

$\displaystyle V=\pi5^2\left ( \frac{12}{3} \right )$

$\displaystyle V=\pi25(4)$

$\displaystyle V=\pi100$

$\displaystyle V=314.16\textup{ in}^3$

In order to solve this problem, we need to recall the formula used to calculate the volume of a cone:

$\displaystyle V=\pi r^2\left ( \frac{h}{3} \right )$

Now that we have this formula, we can substitute in the given values and solve:

$\displaystyle V=\pi4^2\left ( \frac{9}{3} \right )$

$\displaystyle V=\pi16(3)$

$\displaystyle V=\pi48$

$\displaystyle V=150.80\textup{ in}^3$

In order to solve this problem, we need to recall the formula used to calculate the volume of a cone:

$\displaystyle V=\pi r^2\left ( \frac{h}{3} \right )$

Now that we have this formula, we can substitute in the given values and solve:

$\displaystyle V=\pi3^2\left ( \frac{6}{3} \right )$

$\displaystyle V=\pi9(2)$

$\displaystyle V=\pi18$

$\displaystyle V=56.55\textup{ in}^3$