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Common Core: 7th Grade Math : Grade 7

Study concepts, example questions & explanations for Common Core: 7th Grade Math

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All Common Core: 7th Grade Math Resources

7 Diagnostic Tests 110 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #21 : Use Proportional Relationships To Solve Multistep Ratio And Percent Problems: Ccss.Math.Content.7.Rp.A.3

A sweater was originally $\$38.00$ , but the department store is running a $10\%$ off sale. What is the sale price of the sweater?

Possible Answers:

$\$20.40$

$\$26.00$

$\$3.80$

$\$34.20$

$\$14.20$

Correct answer:

$\$34.20$

Explanation:

In order to solve this problem, we need to calculate $10\%$ of . The key word "of" is indicative of multiplication; however, we need to start by converting the percentage into a decimal because you cannot multiply a number by a percent.

We can convert a percent into a decimal by moving the decimal two places to the left:

$10\%\rightarrow0.10$

Next, we can multiply:

$\frac{\begin{array}[b]{r}38\\ \times\ .10\end{array}}{ \ \ \ \space 3.80}$

Remember, we are taking $10\%$ off the original price, which means we need to subtract.

$\frac{\begin{array}[b]{r}38.00\\ -\ 3.80\end{array}}{ \ \ \space 34.20}$

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Example Question #22 : Use Proportional Relationships To Solve Multistep Ratio And Percent Problems: Ccss.Math.Content.7.Rp.A.3

A sweater was originally $\$27.00$ , but the department store is running a $10\%$ off sale. What is the sale price of the sweater?

Possible Answers:

$\$24.30$

$\$30.70$

$\$14.20$

$\$2.70$

$\$28.50$

Correct answer:

$\$24.30$

Explanation:

In order to solve this problem, we need to calculate $10\%$ of $\$27.00$ . The key word "of" is indicative of multiplication; however, we need to start by converting the percentage into a decimal because you cannot multiply a number by a percent.

We can convert a percent into a decimal by moving the decimal two places to the left:

$10\%\rightarrow0.10$

Next, we can multiply:

$\frac{\begin{array}[b]{r}27\\ \times\ .10\end{array}}{ \ \ \ \space 2.70}$

Remember, we are taking $10\%$ off the original price, which means we need to subtract.

$\frac{\begin{array}[b]{r}27.00\\ -\ 2.70\end{array}}{ \ \ \space 24.30}$

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Example Question #23 : Use Proportional Relationships To Solve Multistep Ratio And Percent Problems: Ccss.Math.Content.7.Rp.A.3

A sweater was originally $\$14.00$ , but the department store is running a $10\%$ off sale. What is the sale price of the sweater?

Possible Answers:

$\$10.20$

$\$1.40$

$\$1.60$

$\$6.60$

$\$12.60$

Correct answer:

$\$12.60$

Explanation:

In order to solve this problem, we need to calculate $10\%$ of $\$14.00$ . The key word "of" is indicative of multiplication; however, we need to start by converting the percentage into a decimal because you cannot multiply a number by a percent.

We can convert a percent into a decimal by moving the decimal two places to the left:

$10\%\rightarrow0.10$

Next, we can multiply:

$\frac{\begin{array}[b]{r}14\\ \times\ .10\end{array}}{ \ \ \ \space 1.40}$

Remember, we are taking $10\%$ off the original price, which means we need to subtract.

$\frac{\begin{array}[b]{r}14.00\\ -\ 1.40\end{array}}{ \ \ \space 12.60}$

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Example Question #24 : Use Proportional Relationships To Solve Multistep Ratio And Percent Problems: Ccss.Math.Content.7.Rp.A.3

A sweater was originally $\$50.00$ , but the department store is running a $10\%$ off sale. What is the sale price of the sweater?

Possible Answers:

$\$5.00$

$\$15.00$

$\$45.00$

$\$25.00$

$\$35.00$

Correct answer:

$\$45.00$

Explanation:

In order to solve this problem, we need to calculate $10\%$ of $\$50.00$ . The key word "of" is indicative of multiplication; however, we need to start by converting the percentage into a decimal because you cannot multiply a number by a percent.

We can convert a percent into a decimal by moving the decimal two places to the left:

$10\%\rightarrow0.10$

Next, we can multiply:

$\frac{\begin{array}[b]{r}50\\ \times\ .10\end{array}}{ \ \ \ \space 5.00}$

Remember, we are taking $10\%$ off the original price, which means we need to subtract.

$\frac{\begin{array}[b]{r}50.00\\ -\ 5.00\end{array}}{ \ \ \space 45.00}$

Report an Error

Example Question #25 : Use Proportional Relationships To Solve Multistep Ratio And Percent Problems: Ccss.Math.Content.7.Rp.A.3

A sweater was originally $\$40.00$ , but the department store is running a $20\%$ off sale. What is the sale price of the sweater?

Possible Answers:

$\$32.00$

$\$8.00$

$\$48.00$

$\$43.00$

$\$20.00$

Correct answer:

$\$32.00$

Explanation:

In order to solve this problem, we need to calculate $20\%$ of $\$40.00$ . The key word "of" is indicative of multiplication; however, we need to start by converting the percentage into a decimal because you cannot multiply a number by a percent.

We can convert a percent into a decimal by moving the decimal two places to the left:

$20\%\rightarrow0.20$

Next, we can multiply:

$\frac{\begin{array}[b]{r}40\\ \times\ .20\end{array}}{ \ \ \ \space 8.00}$

Remember, we are taking $20\%$ off the original price, which means we need to subtract.

$\frac{\begin{array}[b]{r}40.00\\ -\ 8.00\end{array}}{ \ \ \space 32.00}$

Report an Error

Example Question #26 : Use Proportional Relationships To Solve Multistep Ratio And Percent Problems: Ccss.Math.Content.7.Rp.A.3

A sweater was originally $\$57.00$ , but the department store is running a $20\%$ off sale. What is the sale price of the sweater?

Possible Answers:

$\$11.40$

$\$50.20$

$\$26.30$

$\$62.80$

$\$45.60$

Correct answer:

$\$45.60$

Explanation:

In order to solve this problem, we need to calculate $20\%$ of $\$57.00$ . The key word "of" is indicative of multiplication; however, we need to start by converting the percentage into a decimal because you cannot multiply a number by a percent.

We can convert a percent into a decimal by moving the decimal two places to the left:

$20\%\rightarrow0.20$

Next, we can multiply:

$\frac{\begin{array}[b]{r}57\\ \times\ .20\end{array}}{ \ \ \ \space 11.40}$

Remember, we are taking $20\%$ off the original price, which means we need to subtract.

$\frac{\begin{array}[b]{r}57.00\\ -\ 11.40\end{array}}{ \ \ \space 45.60}$

Report an Error

Example Question #27 : Use Proportional Relationships To Solve Multistep Ratio And Percent Problems: Ccss.Math.Content.7.Rp.A.3

A sweater was originally $\$31.00$ , but the department store is running a $20\%$ off sale. What is the sale price of the sweater?

Possible Answers:

$\$24.80$

$\$19.30$

$\$12.20$

$\$32.60$

$\$6.20$

Correct answer:

$\$24.80$

Explanation:

In order to solve this problem, we need to calculate $20\%$ of $\$31.00$ . The key word "of" is indicative of multiplication; however, we need to start by converting the percentage into a decimal because you cannot multiply a number by a percent.

We can convert a percent into a decimal by moving the decimal two places to the left:

$20\%\rightarrow0.20$

Next, we can multiply:

$\frac{\begin{array}[b]{r}31\\ \times\ .20\end{array}}{ \ \ \ \space 6.20}$

Remember, we are taking $20\%$ off the original price, which means we need to subtract.

$\frac{\begin{array}[b]{r}31.00\\ -\ 6.20\end{array}}{ \ \ \space 24.80}$

Report an Error

Example Question #28 : Use Proportional Relationships To Solve Multistep Ratio And Percent Problems: Ccss.Math.Content.7.Rp.A.3

A sweater was originally $\$15.00$ , but the department store is running a $20\%$ off sale. What is the sale price of the sweater?

Possible Answers:

$\$15.00$

$\$10.60$

$\$12.00$

$\$6.30$

$\$3.00$

Correct answer:

$\$12.00$

Explanation:

In order to solve this problem, we need to calculate $20\%$ of $\$15.00$ . The key word "of" is indicative of multiplication; however, we need to start by converting the percentage into a decimal because you cannot multiply a number by a percent.

We can convert a percent into a decimal by moving the decimal two places to the left:

$20\%\rightarrow0.20$

Next, we can multiply:

$\frac{\begin{array}[b]{r}15\\ \times\ .20\end{array}}{ \ \ \ \space 3.00}$

Remember, we are taking $20\%$ off the original price, which means we need to subtract.

$\frac{\begin{array}[b]{r}15.00\\ -\ 3.00\end{array}}{ \ \ \space 12.00}$

Report an Error

Example Question #1 : Negative Numbers

Compute the following: -12 -(-3)-(-4)+5

Possible Answers:

Correct answer:

Explanation:

Convert all the double signs to a single sign before solving. Remember, two minus (negative) signs combine to form a plus (positive) sign, and a plus (positive) sign and a minus (negative) sign combine to form a minus (negative) sign.

-12 -(-3)-(-4)+5

-12+3+4+5=0

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Example Question #1 : Describe Situations In Which Opposite Quantities Combine To Make 0: Ccss.Math.Content.7.Ns.A.1a

For the equation provided, what value when substituted for , will equal

11+x=0

Possible Answers:

Correct answer:

Explanation:

In order to answer this question, we can solve for . When solving for we need to isolate the variable on one side of the equation.

We can subtract to both sides in order to isolate the variable, .

$\frac{\begin{array}[b]{r}11+x=0\\ -11\ \ \ \ -11\end{array}}{\\\\x=-11}$

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All Common Core: 7th Grade Math Resources

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Common Core: 7th Grade Math : Grade 7

Study concepts, example questions & explanations for Common Core: 7th Grade Math

All Common Core: 7th Grade Math Resources

Example Questions

Example Question #21 : Use Proportional Relationships To Solve Multistep Ratio And Percent Problems: Ccss.Math.Content.7.Rp.A.3

Example Question #22 : Use Proportional Relationships To Solve Multistep Ratio And Percent Problems: Ccss.Math.Content.7.Rp.A.3

Example Question #23 : Use Proportional Relationships To Solve Multistep Ratio And Percent Problems: Ccss.Math.Content.7.Rp.A.3

Example Question #24 : Use Proportional Relationships To Solve Multistep Ratio And Percent Problems: Ccss.Math.Content.7.Rp.A.3

Example Question #25 : Use Proportional Relationships To Solve Multistep Ratio And Percent Problems: Ccss.Math.Content.7.Rp.A.3

Example Question #26 : Use Proportional Relationships To Solve Multistep Ratio And Percent Problems: Ccss.Math.Content.7.Rp.A.3

Example Question #27 : Use Proportional Relationships To Solve Multistep Ratio And Percent Problems: Ccss.Math.Content.7.Rp.A.3

Example Question #28 : Use Proportional Relationships To Solve Multistep Ratio And Percent Problems: Ccss.Math.Content.7.Rp.A.3

Example Question #1 : Negative Numbers

Example Question #1 : Describe Situations In Which Opposite Quantities Combine To Make 0: Ccss.Math.Content.7.Ns.A.1a

All Common Core: 7th Grade Math Resources

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