All Common Core: 7th Grade Math Resources
Example Questions
Example Question #502 : New Sat
If a rectangle possesses a width of and has a perimeter of , then what is the length?
In order to solve this problem, we need to recall the formula for perimeter of a rectangle:
We can substitute in our known values and solve for our unknown variable (i.e. length):
We want to isolate the to one side of the equation. In order to do this, we will first subtract from both sides of the equation.
Next, we can divide each side by
The length of the rectangle is
Example Question #71 : Expressions & Equations
If a rectangle possesses a width of and has a perimeter of , then what is the length?
In order to solve this problem, we need to recall the formula for perimeter of a rectangle:
We can substitute in our known values and solve for our unknown variable (i.e. length):
We want to isolate the to one side of the equation. In order to do this, we will first subtract from both sides of the equation.
Next, we can divide each side by
The length of the rectangle is
Example Question #504 : New Sat
If a rectangle possesses a width of and has a perimeter of , then what is the length?
In order to solve this problem, we need to recall the formula for perimeter of a rectangle:
We can substitute in our known values and solve for our unknown variable (i.e. length):
We want to isolate the to one side of the equation. In order to do this, we will first subtract from both sides of the equation.
Next, we can divide each side by
The length of the rectangle is
Example Question #111 : New Sat Math Calculator
If a rectangle possesses a width of and has a perimeter of , then what is the length?
In order to solve this problem, we need to recall the formula for perimeter of a rectangle:
We can substitute in our known values and solve for our unknown variable (i.e. length):
We want to isolate the to one side of the equation. In order to do this, we will first subtract from both sides of the equation.
Next, we can divide each side by
The length of the rectangle is
Example Question #71 : Expressions & Equations
If a rectangle possesses a width of and has a perimeter of , then what is the length?
In order to solve this problem, we need to recall the formula for perimeter of a rectangle:
We can substitute in our known values and solve for our unknown variable (i.e. length):
We want to isolate the to one side of the equation. In order to do this, we will first subtract from both sides of the equation.
Next, we can divide each side by
The length of the rectangle is
Example Question #1 : Writing Inequalities
Write as an algebraic inequality:
Twenty subtracted from the product of seven and a number exceeds one hundred.
"The product of seven and a number " is . "Twenty subtracted from the product of seven and a number" is . "Exceeds one hundred" means that this is greater than one hundred, so the correct inequality is
Example Question #2 : Writing Inequalities
Write as an algebraic inequality:
Twice the sum of a number and sixteen is no less than sixty.
"The sum of a number and sixteen" is translates to ; twice that sum is . " Is no less than sixty" means that this is greater than or equal to sixty, so the desired inequality is
.
Example Question #1 : Writing Inequalities
Write as an algebraic inequality:
Twice the sum of a number and sixteen does not exceed eighty.
"The sum of a number and sixteen" translates to ; twice that sum is . "Does not exceed eighty" means that it is less than or equal to eighty, so the desired inequality is
Example Question #1 : Solve Word Problems Leading To Inequalities: Ccss.Math.Content.7.Ee.B.4b
How would you write the equations: "I can spend no more than dollars when I go to the store today."
The way the sentence is phrased suggests that the person can spend up to dollars but not a penny more. This suggests that , the amount spend can be but not exceed it.
So your answer is:
Example Question #2 : Solve Word Problems Leading To Inequalities: Ccss.Math.Content.7.Ee.B.4b
Given the following problem, write the inequality.
Seven less than two times a number is greater than fourteen.
Seven less than two times a number is greater than fourteen.
Let's look at the problem step by step.
If we do not know the value of a number, we give it a variable name. Let's say x. So, we see in the problem
Seven less than two times a number is greater than fourteen.
So, we will replace a number with x.
Seven less than two times x is greater than fourteen.
Now, we see that is says "two times" x, so we will write it like
Seven less than 2x is greater than fourteen.
The problem says "seven less" than 2x. This simply means we are taking 2x and subtracting seven. So we get
2x - 7 is greater than fourteen
We know the symbol for "is greater than". We can write
2x - 7 > fourteen
Finally, we write out the number fourteen.
2x - 7 > 14