In order to answer this question correctly, we need to solve for the mean, median, and mode of this data set. 

To begin, let's sort the data from least to greatest:

Now that our data is ordered from least to greatest, we can solve for the median:

Remember, the median is the middle most number when a data set is ordered from least to greatest.

The median for this data set is 

Next, we can look at our data set to determine the mode:

There is no mode for this set because each value only appears once.

Remember, the mode is the number in a set that appears most often. 

Finally, we can solve for the mean:

Remember, the mean of a data set is the average of the numbers in a data set. 

The mean for this data set is 

Now that we've done our calculation we should have:

Median: 

Mode: None 

Mean: 

We are looking for the value that is representative of the center of the data; thus the mean would be the best measure because of how varied the set is. Normally, when a data set is varied the mean is normally the best measure of center.

In order to answer this question correctly, we need to solve for the range and the interquartile range. 

To begin, let's sort the data from least to greatest:

Next, we can solve for the range. Remember, the range of a data set is the difference between the highest value and the lowest value in the set. 

The range for this data set is 

Now, we can solve for the interquartile range. Remember, the interquartile range is the difference between the upper quartile median and the lower quartile median. This means that we need to first calculate these two values. In order to do this, we need to split the data set into quartiles. 

First, we will find the median:

We will then use the median to split the data in half. Next,  we must find the median of the first half—or lower quartile—and then the median of the second half—or upper quartile:

Now we can solve for the difference between the upper quartile median and the lower quartile median:

Now that we have completed these operations, we should have calculated the following values:

Range: 

Interquartile range: 

As you can see, solving for the interquartile range requires more steps because it takes into account more of the data points; thus, given our options, interquartile range is best to use when solving for variability. 

In order to answer this question correctly, we need to solve for the mean, median, and mode of this data set. 

To begin, let's sort the data from least to greatest:

Now that our data is ordered from least to greatest, we can solve for the median:

Remember, the median is the middle most number when a data set is ordered from least to greatest.

The median for this data set is 

Next, we can look at our data set to determine the mode:

The mode for this set is 

Remember, the mode is the number in a set that appears most often. 

Finally, we can solve for the mean:

Remember, the mean of a data set is the average of the numbers in a data set. 

The mean for this data set is 

Now that we've done our calculation we should have:

Median: 

Mode: 

Mean: 

We are looking for the value that is representative of the center of the data; thus the mean would be the best measure because of how varied the set is. Normally, when a data set is varied the mean is normally the best measure of center.

In order to answer this question correctly, we need to solve for the mean, median, and mode of this data set. 

To begin, let's sort the data from least to greatest:

Now that our data is ordered from least to greatest, we can solve for the median:

Remember, the median is the middle most number when a data set is ordered from least to greatest.

The median for this data set is 

Next, we can look at our data set to determine the mode:

The mode for this set is 

Remember, the mode is the number in a set that appears most often. 

Finally, we can solve for the mean:

Remember, the mean of a data set is the average of the numbers in a data set. 

The mean for this data set is 

Now that we've done our calculation we should have:

Median: 

Mode: 

Mean: 

We are looking for the value that is representative of the center of the data. In this data set we have an outlier, which means the mean is not going to be the best measure of center. Also, the mode is the lowest value in our set; thus, the median is the best measure of center. 

In order to answer this question correctly, we need to solve for the range and the interquartile range. 

To begin, let's sort the data from least to greatest:

Next, we can solve for the range. Remember, the range of a data set is the difference between the highest value and the lowest value in the set. 

The range for this data set is 

Now, we can solve for the interquartile range. Remember, the interquartile range is the difference between the upper quartile median and the lower quartile median. This means that we need to first calculate these two values. In order to do this, we need to split the data set into quartiles. 

First, we will find the median:

We will then use the median to split the data in half. Next,  we must find the median of the first half—or lower quartile—and then the median of the second half—or upper quartile:

Now we can solve for the difference between the upper quartile median and the lower quartile median:

Now that we have completed these operations, we should have calculated the following values:

Range: 

Interquartile range: 

As you can see, solving for the interquartile range requires more steps because it takes into account more of the data points; thus, given our options, interquartile range is best to use when solving for variability. 

In order to answer this question correctly, we need to solve for the mean, median, and mode of this data set. 

To begin, let's sort the data from least to greatest:

Now that our data is ordered from least to greatest, we can solve for the median:

Remember, the median is the middle most number when a data set is ordered from least to greatest.

The median for this data set is 

Next, we can look at our data set to determine the mode:

The mode for this set is 

Remember, the mode is the number in a set that appears most often. 

Finally, we can solve for the mean:

Remember, the mean of a data set is the average of the numbers in a data set. 

The mean for this data set is 

Now that we've done our calculation we should have:

Median: 

Mode: 

Mean: 

We are looking for the value that is representative of the center of the data. In this data set we have an outlier, which means the mean is not going to be the best measure of center. Also, the mode is the lowest value in our set; thus, the median is the best measure of center. 

In order to answer this question correctly, we need to solve for the range and the interquartile range. 

To begin, let's sort the data from least to greatest:

Next, we can solve for the range. Remember, the range of a data set is the difference between the highest value and the lowest value in the set. 

The range for this data set is 

Now, we can solve for the interquartile range. Remember, the interquartile range is the difference between the upper quartile median and the lower quartile median. This means that we need to first calculate these two values. In order to do this, we need to split the data set into quartiles. 

First, we will find the median:

We will then use the median to split the data in half. Next,  we must find the median of the first half—or lower quartile—and then the median of the second half—or upper quartile:

Now we can solve for the difference between the upper quartile median and the lower quartile median:

Now that we have completed these operations, we should have calculated the following values:

Range: 

Interquartile range: 

As you can see, solving for the interquartile range requires more steps because it takes into account more of the data points; thus, given our options, interquartile range is best to use when solving for variability. 

If the average of 4 books was 10, then the total number of pages was . Adding in the 20 new pages, but now dividing by 5 you get .

Add the six elements and divide the sum by 6:

Firrst, add the numbers:

Then, divide by the amount of numbers in the set:

Answer: The mean is 76.