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Common Core: 6th Grade Math : Expressions & Equations

Study concepts, example questions & explanations for Common Core: 6th Grade Math

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All Common Core: 6th Grade Math Resources

6 Diagnostic Tests 186 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #6 : Identify Parts Of An Expression Using Mathematical Terms: Ccss.Math.Content.6.Ee.A.2b

Identify the coefficient(s) in the equation below.

5x+13=28

Possible Answers:

Both and

Correct answer:

Explanation:

A coefficient is a number or symbol that is being multiplied by an unknown. In this case, is our unknown and it's being multiplied by , thus is our coefficient.

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Example Question #11 : Identify Parts Of An Expression Using Mathematical Terms: Ccss.Math.Content.6.Ee.A.2b

Identify the coefficient(s) in the equation below.

7x+8=22

Possible Answers:

Both and

Correct answer:

Explanation:

A coefficient is a number or symbol that is being multiplied by an unknown. In this case, is our unknown and it's being multiplied by , thus is our coefficient.

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Example Question #675 : Grade 6

Solve for :

x+17=81

Possible Answers:

Correct answer:

Explanation:

The equation x+17=81 asks us to identify which number, , plus is equal to .

In order to solve this equation, we need to isolate the variable on one side of the equals sign. We will do this by performing the opposite of the operations that were done on the variable,. We need to remember that whatever we do to one side of the equals sign, we have to do to the other.

Since was added to the variable, we can subtract from both sides of the equation.

$\frac{\begin{array}[b]{r}x+17=81\\ -17-17\end{array}}{\\\\x+0=64}$

Simplify by dropping the because it has not numerical value; therefore:

x=64

We can check to make sure we have the correct value for by plugging into the original equation; thus:

64+17=81

81=81

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Example Question #221 : Expressions & Equations

Which of the following choices represent terms in the equation 31-6=25 ?

Possible Answers:

All of the options are correct

Correct answer:

All of the options are correct

Explanation:

A term is a number or variable in an equation. Terms are separated by mathematical signs $(+,-,\times, \div, etc)$

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Example Question #1 : Evaluate Expressions: Ccss.Math.Content.6.Ee.A.2c

Solve for :

x+7=2

Possible Answers:

Correct answer:

Explanation:

Isolate the variable to one side.

Subtract from both sides:

x+7=2

x+7-7=2-7

x=-5

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Example Question #2 : Evaluate Expressions: Ccss.Math.Content.6.Ee.A.2c

Solve for :

3x=27

Possible Answers:

Correct answer:

Explanation:

We need to isolate by dividing by 3.

Remember, what you do on one side, you must do on the other side.

Since you divided by , you also have to divde by :

$\frac{3x}{3}= \frac{27}{3}$

x=9

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Example Question #2 : Evaluate Expressions: Ccss.Math.Content.6.Ee.A.2c

Solve for $\small x$ :

x+1=0

Possible Answers:

$\small 1$

$\small -1$

Correct answer:

$\small -1$

Explanation:

To solve this you must isolate your $\small x$ by subtracting 1 from both sides to get

x=0-1 or x=-1

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Example Question #3 : Evaluate Expressions: Ccss.Math.Content.6.Ee.A.2c

Solve for x:

x + 4 = -12

Possible Answers:

x= -16

x= -48

x= -3

x= -8

x= 4

Correct answer:

x= -16

Explanation:

Step 1: isolate x

x+4-4=-12-4

x=-12-4

Step 2: solve

x=-16

If it's helpful, when you subtract a positive integer from a negative integer, you can think of it in terms of absolute value:

$-12-4=-\left | 12+4\right |=-\left | 16\right |=-16$

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Example Question #3 : Evaluate Expressions: Ccss.Math.Content.6.Ee.A.2c

Solve for $\small x$ :

$\small 8x = 64$

Possible Answers:

Correct answer:

Explanation:

To solve this equation, isolate $\small x$ by dividing both sides of the equation by 8:

$\small 8x=64$

$\small \frac{8x}{8}= \frac{64}{8}$

$\small x=8$

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Example Question #4 : One Step Equations With Integers

3x = 18

Possible Answers:

Correct answer:

Explanation:

To solve this equation, isolate the variable. Since 3x is a multiplication operation, do the opposite (division) to remove the 3. Keep in mind that you must do the same step on each side of the equation every time you change something.

$\frac{3x}{3} = \frac{18}{3} = 6$

x=6

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All Common Core: 6th Grade Math Resources

6 Diagnostic Tests 186 Practice Tests Question of the Day Flashcards Learn by Concept

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Common Core: 6th Grade Math : Expressions & Equations

Study concepts, example questions & explanations for Common Core: 6th Grade Math

All Common Core: 6th Grade Math Resources

Example Questions

Example Question #6 : Identify Parts Of An Expression Using Mathematical Terms: Ccss.Math.Content.6.Ee.A.2b

Example Question #11 : Identify Parts Of An Expression Using Mathematical Terms: Ccss.Math.Content.6.Ee.A.2b

Example Question #675 : Grade 6

Example Question #221 : Expressions & Equations

Example Question #1 : Evaluate Expressions: Ccss.Math.Content.6.Ee.A.2c

Example Question #2 : Evaluate Expressions: Ccss.Math.Content.6.Ee.A.2c

Example Question #2 : Evaluate Expressions: Ccss.Math.Content.6.Ee.A.2c

Example Question #3 : Evaluate Expressions: Ccss.Math.Content.6.Ee.A.2c

Example Question #3 : Evaluate Expressions: Ccss.Math.Content.6.Ee.A.2c

Example Question #4 : One Step Equations With Integers

All Common Core: 6th Grade Math Resources

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