Call Now to Set Up Tutoring:

(888) 888-0446

Common Core: 5th Grade Math : Number & Operations in Base Ten

Study concepts, example questions & explanations for Common Core: 5th Grade Math

Create An Account

All Common Core: 5th Grade Math Resources

7 Diagnostic Tests 225 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #641 : Number & Operations In Base Ten

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 6} \space{\,}5\\ \times\phantom{0}6\space{\,}3 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

4085

4105

4095

40950

Correct answer:

4095

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 63 is the multiplier and 65 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 3 and 5

$\begin{array}{r}\overset{1 \space{\ }}{\ 6} \space{\,}5\\ \times \phantom{0} 6\space{\,}3\\ \hline \phantom{\,} \,5\end{array}$

Then, we multiply 3 and 6 and add the 1 that was carried

$\begin{array}{r}\overset{1 \space{\ }}{\ 6} \space{\,}5\\ \times \phantom{0} 6\space{\,}3 \\ \hline \phantom{\,}1\,9\,5\end{array}$

Now, we multiply the digit in the tens place of the multiplier by each digit of the multiplicand. In order to do this, we need to start a new line in our math problem and put a 0 as a place holder in the ones position.

$\begin{array}{r}\overset{~ \space{\ }}{\ 6} \space{\,}5\\ \times \phantom{0} 6\space{\,}3 \\ \hline \phantom{\,}1\,9\,5 \\ \, 0 \end{array}$

Next, we multiply 6 and 5

$\begin{array}{r}\overset{3 \space{\ }}{\ 6} \space{\,}5\\ \times \phantom{0} 6\space{\,}3 \\ \hline \phantom{\,}1\,9\,5 \\ \, 0 \, 0\end{array}$

Then, we multiply 6 and 6and add the 3 that was carried

$\begin{array}{r}\overset{3 \space{\ }}{\ 6} \space{\,}5\\ \times \phantom{0} 6\space{\,}3 \\ \hline \phantom{\,}1\,9\,5 \\ \, 3 \, 9 \, 0 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{3 \space{\ }}{\ 6} \space{\,}5\\ \times \phantom{0} 6\space{\,}3 \\ \hline \phantom{\,}1\,9\,5 \\+\, 3 \, 9 \, 0 \, 0\\ \hline 4\, 0 \, 9\, 5\end{array}$

Report an Error

Example Question #642 : Number & Operations In Base Ten

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 2} \space{\,}1\\ \times\phantom{0}2\space{\,}0 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

410

420

4200

430

Correct answer:

420

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 20 is the multiplier and 21 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 0 and 1

$\begin{array}{r}\overset{~ \space{\ }}{\ 2} \space{\,}1\\ \times \phantom{0} 2\space{\,}0 \\ \hline \phantom{\,} \,0\end{array}$

Then, we multiply 0 and 2

$\begin{array}{r}\overset{~ \space{\ }}{\ 2} \space{\,}1\\ \times \phantom{0} 2\space{\,}0 \\ \hline \phantom{\,} \,0\,0\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 2} \space{\,}1\\ \times \phantom{0} 2\space{\,}0 \\ \hline \phantom{\,} \,0\,0 \\ \, 0 \end{array}$

Next, we multiply 2 and 1

$\begin{array}{r}\overset{~ \space{\ }}{\ 2} \space{\,}1\\ \times \phantom{0} 2\space{\,}0 \\ \hline \phantom{\,} \,0\,0 \\ \, 2 \, 0\end{array}$

Then, we multiply 2 and 2

$\begin{array}{r}\overset{~ \space{\ }}{\ 2} \space{\,}1\\ \times \phantom{0} 2\space{\,}0 \\ \hline \phantom{\,} \,0\,0 \\ \, 4 \, 2 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{~ \space{\ }}{\ 2} \space{\,}1\\ \times \phantom{0} 2\space{\,}0 \\ \hline \phantom{\,} \,0\,0 \\+\, 4 \, 2 \, 0\\ \hline 4\, 2 \, 0\end{array}$

Report an Error

Example Question #121 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 6} \space{\,}4\\ \times\phantom{0}5\space{\,}8 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

3722

3702

3712

37120

Correct answer:

3712

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 58 is the multiplier and 64 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 8 and 4

$\begin{array}{r}\overset{3 \space{\ }}{\ 6} \space{\,}4\\ \times \phantom{0} 5\space{\,}8\\ \hline \phantom{\,} \,2\end{array}$

Then, we multiply 8 and 6 and add the 3 that was carried

$\begin{array}{r}\overset{3 \space{\ }}{\ 6} \space{\,}4\\ \times \phantom{0} 5\space{\,}8 \\ \hline \phantom{\,}5\,1\,2\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 6} \space{\,}4\\ \times \phantom{0} 5\space{\,}8 \\ \hline \phantom{\,}5\,1\,2 \\ \, 0 \end{array}$

Next, we multiply 5 and 4

$\begin{array}{r}\overset{2 \space{\ }}{\ 6} \space{\,}4\\ \times \phantom{0} 5\space{\,}8 \\ \hline \phantom{\,}5\,1\,2 \\ \, 0 \, 0\end{array}$

Then, we multiply 5 and 6and add the 2 that was carried

$\begin{array}{r}\overset{2 \space{\ }}{\ 6} \space{\,}4\\ \times \phantom{0} 5\space{\,}8 \\ \hline \phantom{\,}5\,1\,2 \\ \, 3 \, 2 \, 0 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{2 \space{\ }}{\ 6} \space{\,}4\\ \times \phantom{0} 5\space{\,}8 \\ \hline \phantom{\,}5\,1\,2 \\+\, 3 \, 2 \, 0 \, 0\\ \hline 3\, 7 \, 1\, 2\end{array}$

Report an Error

Example Question #641 : Number & Operations In Base Ten

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 3} \space{\,}5\\ \times\phantom{0}5\space{\,}1 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

1785

1775

1795

17850

Correct answer:

1785

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 51 is the multiplier and 35 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 1 and 5

$\begin{array}{r}\overset{~ \space{\ }}{\ 3} \space{\,}5\\ \times \phantom{0} 5\space{\,}1 \\ \hline \phantom{\,} \,5\end{array}$

Then, we multiply 1 and 3

$\begin{array}{r}\overset{~ \space{\ }}{\ 3} \space{\,}5\\ \times \phantom{0} 5\space{\,}1 \\ \hline \phantom{\,} \,3\,5\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 3} \space{\,}5\\ \times \phantom{0} 5\space{\,}1 \\ \hline \phantom{\,} \,3\,5 \\ \, 0 \end{array}$

Next, we multiply 5 and 5

$\begin{array}{r}\overset{2 \space{\ }}{\ 3} \space{\,}5\\ \times \phantom{0} 5\space{\,}1 \\ \hline \phantom{\,} \,3\,5 \\ \, 5 \, 0\end{array}$

Then, we multiply 5 and 3and add the 2 that was carried

$\begin{array}{r}\overset{2 \space{\ }}{\ 3} \space{\,}5\\ \times \phantom{0} 5\space{\,}1 \\ \hline \phantom{\,} \,3\,5 \\ \, 1 \, 7 \, 5 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{2 \space{\ }}{\ 3} \space{\,}5\\ \times \phantom{0} 5\space{\,}1 \\ \hline \phantom{\,} \,3\,5 \\+\, 1 \, 7 \, 5 \, 0\\ \hline 1\, 7 \, 8\, 5\end{array}$

Report an Error

Example Question #123 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}2\\ \times\phantom{0}3\space{\,}3 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

1726

17160

1716

1706

Correct answer:

1716

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 33 is the multiplier and 52 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 3 and 2

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}2\\ \times \phantom{0} 3\space{\,}3 \\ \hline \phantom{\,} \,6\end{array}$

Then, we multiply 3 and 5

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}2\\ \times \phantom{0} 3\space{\,}3 \\ \hline \phantom{\,}1\,5\,6\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}2\\ \times \phantom{0} 3\space{\,}3 \\ \hline \phantom{\,}1\,5\,6 \\ \, 0 \end{array}$

Next, we multiply 3 and 2

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}2\\ \times \phantom{0} 3\space{\,}3 \\ \hline \phantom{\,}1\,5\,6 \\ \, 6 \, 0\end{array}$

Then, we multiply 3 and 5

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}2\\ \times \phantom{0} 3\space{\,}3 \\ \hline \phantom{\,}1\,5\,6 \\ \, 1\, 5\, 6 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}2\\ \times \phantom{0} 3\space{\,}3 \\ \hline \phantom{\,}1\,5\,6 \\+\, 1\, 5\, 6 \, 0\\ \hline 1\, 7 \, 1\, 6\end{array}$

Report an Error

Example Question #124 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}4\\ \times\phantom{0}2\space{\,}5 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

21000

2110

2100

2090

Correct answer:

2100

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 25 is the multiplier and 84 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 5 and 4

$\begin{array}{r}\overset{2 \space{\ }}{\ 8} \space{\,}4\\ \times \phantom{0} 2\space{\,}5\\ \hline \phantom{\,} \,0\end{array}$

Then, we multiply 5 and 8 and add the 2 that was carried

$\begin{array}{r}\overset{2 \space{\ }}{\ 8} \space{\,}4\\ \times \phantom{0} 2\space{\,}5 \\ \hline \phantom{\,}4\,2\,0\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}4\\ \times \phantom{0} 2\space{\,}5 \\ \hline \phantom{\,}4\,2\,0 \\ \, 0 \end{array}$

Next, we multiply 2 and 4

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}4\\ \times \phantom{0} 2\space{\,}5 \\ \hline \phantom{\,}4\,2\,0 \\ \, 8 \, 0\end{array}$

Then, we multiply 2 and 8

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}4\\ \times \phantom{0} 2\space{\,}5 \\ \hline \phantom{\,}4\,2\,0 \\ \, 1\, 6\, 8 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}4\\ \times \phantom{0} 2\space{\,}5 \\ \hline \phantom{\,}4\,2\,0 \\+\, 1\, 6\, 8 \, 0\\ \hline 2\, 1 \, 0\, 0\end{array}$

Report an Error

Example Question #125 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}2\\ \times\phantom{0}6\space{\,}1 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

3182

3172

3162

31720

Correct answer:

3172

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 61 is the multiplier and 52 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 1 and 2

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}2\\ \times \phantom{0} 6\space{\,}1 \\ \hline \phantom{\,} \,2\end{array}$

Then, we multiply 1 and 5

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}2\\ \times \phantom{0} 6\space{\,}1 \\ \hline \phantom{\,} \,5\,2\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 5} \space{\,}2\\ \times \phantom{0} 6\space{\,}1 \\ \hline \phantom{\,} \,5\,2 \\ \, 0 \end{array}$

Next, we multiply 6 and 2

$\begin{array}{r}\overset{1 \space{\ }}{\ 5} \space{\,}2\\ \times \phantom{0} 6\space{\,}1 \\ \hline \phantom{\,} \,5\,2 \\ \, 2 \, 0\end{array}$

Then, we multiply 6 and 5and add the 1 that was carried

$\begin{array}{r}\overset{1 \space{\ }}{\ 5} \space{\,}2\\ \times \phantom{0} 6\space{\,}1 \\ \hline \phantom{\,} \,5\,2 \\ \, 3 \, 1 \, 2 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{1 \space{\ }}{\ 5} \space{\,}2\\ \times \phantom{0} 6\space{\,}1 \\ \hline \phantom{\,} \,5\,2 \\+\, 3 \, 1 \, 2 \, 0\\ \hline 3\, 1 \, 7\, 2\end{array}$

Report an Error

Example Question #126 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 3} \space{\,}5\\ \times\phantom{0}6\space{\,}6 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

2300

23100

2320

2310

Correct answer:

2310

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 66 is the multiplier and 35 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 6 and 5

$\begin{array}{r}\overset{3 \space{\ }}{\ 3} \space{\,}5\\ \times \phantom{0} 6\space{\,}6\\ \hline \phantom{\,} \,0\end{array}$

Then, we multiply 6 and 3 and add the 3 that was carried

$\begin{array}{r}\overset{3 \space{\ }}{\ 3} \space{\,}5\\ \times \phantom{0} 6\space{\,}6 \\ \hline \phantom{\,}2\,1\,0\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 3} \space{\,}5\\ \times \phantom{0} 6\space{\,}6 \\ \hline \phantom{\,}2\,1\,0 \\ \, 0 \end{array}$

Next, we multiply 6 and 5

$\begin{array}{r}\overset{3 \space{\ }}{\ 3} \space{\,}5\\ \times \phantom{0} 6\space{\,}6 \\ \hline \phantom{\,}2\,1\,0 \\ \, 0 \, 0\end{array}$

Then, we multiply 6 and 3and add the 3 that was carried

$\begin{array}{r}\overset{3 \space{\ }}{\ 3} \space{\,}5\\ \times \phantom{0} 6\space{\,}6 \\ \hline \phantom{\,}2\,1\,0 \\ \, 2 \, 1 \, 0 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{3 \space{\ }}{\ 3} \space{\,}5\\ \times \phantom{0} 6\space{\,}6 \\ \hline \phantom{\,}2\,1\,0 \\+\, 2 \, 1 \, 0 \, 0\\ \hline 2\, 3 \, 1\, 0\end{array}$

Report an Error

Example Question #127 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 1} \space{\,}2\\ \times\phantom{0}5\space{\,}7 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

684

6840

674

694

Correct answer:

684

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 57 is the multiplier and 12 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 7 and 2

$\begin{array}{r}\overset{1 \space{\ }}{\ 1} \space{\,}2\\ \times \phantom{0} 5\space{\,}7\\ \hline \phantom{\,} \,4\end{array}$

Then, we multiply 7 and 1 and add the 1 that was carried

$\begin{array}{r}\overset{1 \space{\ }}{\ 1} \space{\,}2\\ \times \phantom{0} 5\space{\,}7 \\ \hline \phantom{\,} \,8\,4\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 1} \space{\,}2\\ \times \phantom{0} 5\space{\,}7 \\ \hline \phantom{\,} \,8\,4 \\ \, 0 \end{array}$

Next, we multiply 5 and 2

$\begin{array}{r}\overset{1 \space{\ }}{\ 1} \space{\,}2\\ \times \phantom{0} 5\space{\,}7 \\ \hline \phantom{\,} \,8\,4 \\ \, 0 \, 0\end{array}$

Then, we multiply 5 and 1and add the 1 that was carried

$\begin{array}{r}\overset{1 \space{\ }}{\ 1} \space{\,}2\\ \times \phantom{0} 5\space{\,}7 \\ \hline \phantom{\,} \,8\,4 \\ \, 6 \, 0 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{1 \space{\ }}{\ 1} \space{\,}2\\ \times \phantom{0} 5\space{\,}7 \\ \hline \phantom{\,} \,8\,4 \\+\, 6 \, 0 \, 0\\ \hline 6\, 8 \, 4\end{array}$

Report an Error

Example Question #128 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Solve:

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}6\\ \times\phantom{0}3\space{\,}4 \\ \hline \phantom{\,}\end{array}$

Possible Answers:

29240

2914

2934

2924

Correct answer:

2924

Explanation:

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

$\frac{\begin{array}[b]{r}\textup{multiplicand}\\ \times\ \ \ \ \textup{multiplier}\end{array}}{\ \ \ \ \textup{product}}$

For this problem, 34 is the multiplier and 86 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 4 and 6

$\begin{array}{r}\overset{2 \space{\ }}{\ 8} \space{\,}6\\ \times \phantom{0} 3\space{\,}4\\ \hline \phantom{\,} \,4\end{array}$

Then, we multiply 4 and 8 and add the 2 that was carried

$\begin{array}{r}\overset{2 \space{\ }}{\ 8} \space{\,}6\\ \times \phantom{0} 3\space{\,}4 \\ \hline \phantom{\,}3\,4\,4\end{array}$

$\begin{array}{r}\overset{~ \space{\ }}{\ 8} \space{\,}6\\ \times \phantom{0} 3\space{\,}4 \\ \hline \phantom{\,}3\,4\,4 \\ \, 0 \end{array}$

Next, we multiply 3 and 6

$\begin{array}{r}\overset{1 \space{\ }}{\ 8} \space{\,}6\\ \times \phantom{0} 3\space{\,}4 \\ \hline \phantom{\,}3\,4\,4 \\ \, 8 \, 0\end{array}$

Then, we multiply 3 and 8and add the 1 that was carried

$\begin{array}{r}\overset{1 \space{\ }}{\ 8} \space{\,}6\\ \times \phantom{0} 3\space{\,}4 \\ \hline \phantom{\,}3\,4\,4 \\ \, 2 \, 5 \, 8 \, 0\end{array}$

Finally, we add the two products together to find our final answer

$\begin{array}{r}\overset{1 \space{\ }}{\ 8} \space{\,}6\\ \times \phantom{0} 3\space{\,}4 \\ \hline \phantom{\,}3\,4\,4 \\+\, 2 \, 5 \, 8 \, 0\\ \hline 2\, 9 \, 2\, 4\end{array}$

Report an Error

View Tutors

Patrick
Certified Tutor

LeTourneau University, Bachelors, Electrical Engineering. LeTourneau University, Masters, Electrical Engineering.

View Tutors

Jamie
Certified Tutor

East Central University, Bachelors, Special Education.

View Tutors

Kenneth
Certified Tutor

North Georgia University, Bachelors, Accounting. Brenau University, Masters, Business.

All Common Core: 5th Grade Math Resources

7 Diagnostic Tests 225 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

English Tutors in San Francisco-Bay Area, French Tutors in San Francisco-Bay Area, Spanish Tutors in San Diego, GMAT Tutors in Dallas Fort Worth, Physics Tutors in Chicago, Biology Tutors in New York City, ISEE Tutors in Boston, Calculus Tutors in Miami, Computer Science Tutors in San Francisco-Bay Area, Computer Science Tutors in Los Angeles

Popular Courses & Classes

ISEE Courses & Classes in New York City, GRE Courses & Classes in Washington DC, SSAT Courses & Classes in Denver, Spanish Courses & Classes in Los Angeles, Spanish Courses & Classes in Chicago, Spanish Courses & Classes in Boston, ISEE Courses & Classes in Atlanta, LSAT Courses & Classes in Denver, SAT Courses & Classes in Dallas Fort Worth, SSAT Courses & Classes in Dallas Fort Worth

Popular Test Prep

ISEE Test Prep in Dallas Fort Worth, SSAT Test Prep in Houston, ISEE Test Prep in Philadelphia, GMAT Test Prep in Los Angeles, GRE Test Prep in San Francisco-Bay Area, ACT Test Prep in Seattle, ISEE Test Prep in San Diego, LSAT Test Prep in Phoenix, MCAT Test Prep in Seattle, SSAT Test Prep in Miami

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

Common Core: 5th Grade Math : Number & Operations in Base Ten

Study concepts, example questions & explanations for Common Core: 5th Grade Math

All Common Core: 5th Grade Math Resources

Example Questions

Example Question #641 : Number & Operations In Base Ten

Example Question #642 : Number & Operations In Base Ten

Example Question #121 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Example Question #641 : Number & Operations In Base Ten

Example Question #123 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Example Question #124 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Example Question #125 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Example Question #126 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Example Question #127 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

Example Question #128 : Fluently Multiply Multi Digit Whole Numbers: Ccss.Math.Content.5.Nbt.B.5

All Common Core: 5th Grade Math Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: