If you look closely at this figure, you can see that it is made up of two rectangular prisms. In order to solve for the volume, we need to find the volume of each rectangular prism and then add the volumes together to find the total.

In order to find the length of the rectangular prism on the right, we had to take the length of the original figure (which was \(\displaystyle 5\)) and subtract the length of the rectangular prism on the left (which is \(\displaystyle 2\))

\(\displaystyle 5-2=3\)

Now that we have the dimensions of both our rectangular prisms, we can solve for the volumes. 

Remember, the formula for volume is 

\(\displaystyle v=l\times w\times h\)

\(\displaystyle v=2\times3\times5\)   and \(\displaystyle v=3\times2\times3\)

\(\displaystyle v=30in^3\)         and \(\displaystyle v=18in^3\)

Next, we add the volumes together to solve for the total volume of the original figure.

\(\displaystyle \frac{\begin{array}[b]{r}30in^3\\ +\ 18in^3\end{array}}{ \ \ \ \space 48in^3}\)

*Remember, volume is always measured in cubic units! 

If you look closely at this figure, you can see that it is made up of two rectangular prisms. In order to solve for the volume, we need to find the volume of each rectangular prism and then add the volumes together to find the total.

In order to find the length of the rectangular prism on the right, we had to take the length of the original figure (which was \(\displaystyle 9\)) and subtract the length of the rectangular prism on the left (which is \(\displaystyle 4\))

\(\displaystyle 9-4=5\)

Now that we have the dimensions of both our rectangular prisms, we can solve for the volumes. 

Remember, the formula for volume is 

\(\displaystyle v=l\times w\times h\)

\(\displaystyle v=4\times3\times8\)   and \(\displaystyle v=5\times3\times5\)

\(\displaystyle v=96in^3\)         and \(\displaystyle v=75in^3\)

Next, we add the volumes together to solve for the total volume of the original figure.

\(\displaystyle \frac{\begin{array}[b]{r}96in^3\\ +\ 75in^3\end{array}}{ \ \ \space 171in^3}\)

*Remember, volume is always measured in cubic units! 

If you look closely at this figure, you can see that it is made up of two rectangular prisms. In order to solve for the volume, we need to find the volume of each rectangular prism and then add the volumes together to find the total.

In order to find the length of the rectangular prism on the right, we had to take the length of the original figure (which was \(\displaystyle 10\)) and subtract the length of the rectangular prism on the left (which is \(\displaystyle 6\))

\(\displaystyle 10-6=4\)

Now that we have the dimensions of both our rectangular prisms, we can solve for the volumes. 

Remember, the formula for volume is 

\(\displaystyle v=l\times w\times h\)

\(\displaystyle v=6\times5\times9\)   and \(\displaystyle v=4\times4\times5\)

\(\displaystyle v=270in^3\)         and \(\displaystyle v=80in^3\)

Next, we add the volumes together to solve for the total volume of the original figure.

\(\displaystyle \frac{\begin{array}[b]{r}270in^3\\ +\ 80in^3\end{array}}{ \ \ \space 350in^3}\)

*Remember, volume is always measured in cubic units! 

If you look closely at this figure, you can see that it is made up of two rectangular prisms. In order to solve for the volume, we need to find the volume of each rectangular prism and then add the volumes together to find the total.

In order to find the length of the rectangular prism on the right, we had to take the length of the original figure (which was \(\displaystyle 12\)) and subtract the length of the rectangular prism on the left (which is \(\displaystyle 6\))

\(\displaystyle 12-6=6\)

Now that we have the dimensions of both our rectangular prisms, we can solve for the volumes. 

Remember, the formula for volume is 

\(\displaystyle v=l\times w\times h\)

\(\displaystyle v=6\times5\times10\)   and \(\displaystyle v=6\times6\times7\)

\(\displaystyle v=300in^3\)         and \(\displaystyle v=252in^3\)

Next, we add the volumes together to solve for the total volume of the original figure.

\(\displaystyle \frac{\begin{array}[b]{r}300in^3\\ +\ 252in^3\end{array}}{ \ \ \ \space 552in^3}\)

*Remember, volume is always measured in cubic units! 

If you look closely at this figure, you can see that it is made up of two rectangular prisms. In order to solve for the volume, we need to find the volume of each rectangular prism and then add the volumes together to find the total.

In order to find the length of the rectangular prism on the right, we had to take the length of the original figure (which was \(\displaystyle 11\)) and subtract the length of the rectangular prism on the left (which is \(\displaystyle 6\))

\(\displaystyle 11-6=5\)

Now that we have the dimensions of both our rectangular prisms, we can solve for the volumes. 

Remember, the formula for volume is 

\(\displaystyle v=l\times w\times h\)

\(\displaystyle v=6\times4\times9\)   and \(\displaystyle v=5\times4\times5\)

\(\displaystyle v=216in^3\)         and \(\displaystyle v=100in^3\)

Next, we add the volumes together to solve for the total volume of the original figure.

\(\displaystyle \frac{\begin{array}[b]{r}216in^3\\ +\ 100in^3\end{array}}{ \ \ \ \space 316in^3}\)

*Remember, volume is always measured in cubic units! 

If you look closely at this figure, you can see that it is made up of two rectangular prisms. In order to solve for the volume, we need to find the volume of each rectangular prism and then add the volumes together to find the total.

In order to find the length of the rectangular prism on the right, we had to take the length of the original figure (which was \(\displaystyle 13\)) and subtract the length of the rectangular prism on the left (which is \(\displaystyle 6\))

\(\displaystyle 13-6=7\)

Now that we have the dimensions of both our rectangular prisms, we can solve for the volumes. 

Remember, the formula for volume is 

\(\displaystyle v=l\times w\times h\)

\(\displaystyle v=6\times3\times11\)   and \(\displaystyle v=7\times3\times6\)

\(\displaystyle v=198in^3\)         and \(\displaystyle v=126in^3\)

Next, we add the volumes together to solve for the total volume of the original figure.

\(\displaystyle \frac{\begin{array}[b]{r}198in^3\\ +\ 126in^3\end{array}}{ \ \ \ \space 324in^3}\)

*Remember, volume is always measured in cubic units! 

If you look closely at this figure, you can see that it is made up of two rectangular prisms. In order to solve for the volume, we need to find the volume of each rectangular prism and then add the volumes together to find the total.

In order to find the length of the rectangular prism on the right, we had to take the length of the original figure (which was \(\displaystyle 13\)) and subtract the length of the rectangular prism on the left (which is \(\displaystyle 7\))

\(\displaystyle 13-7=6\)

Now that we have the dimensions of both our rectangular prisms, we can solve for the volumes. 

Remember, the formula for volume is 

\(\displaystyle v=l\times w\times h\)

\(\displaystyle v=7\times4\times10\)   and \(\displaystyle v=6\times4\times5\)

\(\displaystyle v=280in^3\)         and \(\displaystyle v=120in^3\)

Next, we add the volumes together to solve for the total volume of the original figure.

\(\displaystyle \frac{\begin{array}[b]{r}280in^3\\ +\ 120in^3\end{array}}{ \ \ \ \space 400in^3}\)

*Remember, volume is always measured in cubic units! 

If you look closely at this figure, you can see that it is made up of two rectangular prisms. In order to solve for the volume, we need to find the volume of each rectangular prism and then add the volumes together to find the total.

In order to find the length of the rectangular prism on the right, we had to take the length of the original figure (which was \(\displaystyle 15\)) and subtract the length of the rectangular prism on the left (which is \(\displaystyle 8\))

\(\displaystyle 15-8=7\)

Now that we have the dimensions of both our rectangular prisms, we can solve for the volumes. 

Remember, the formula for volume is 

\(\displaystyle v=l\times w\times h\)

\(\displaystyle v=8\times4\times11\)   and \(\displaystyle v=7\times4\times5\)

\(\displaystyle v=352in^3\)         and \(\displaystyle v=140in^3\)

Next, we add the volumes together to solve for the total volume of the original figure.

\(\displaystyle \frac{\begin{array}[b]{r}352in^3\\ +\ 140in^3\end{array}}{ \ \ \ \space 492in^3}\)

*Remember, volume is always measured in cubic units! 

If you look closely at this figure, you can see that it is made up of two rectangular prisms. In order to solve for the volume, we need to find the volume of each rectangular prism and then add the volumes together to find the total.

In order to find the length of the rectangular prism on the right, we had to take the length of the original figure (which was \(\displaystyle 14\)) and subtract the length of the rectangular prism on the left (which is \(\displaystyle 8\))

\(\displaystyle 14-8=6\)

Now that we have the dimensions of both our rectangular prisms, we can solve for the volumes. 

Remember, the formula for volume is 

\(\displaystyle v=l\times w\times h\)

\(\displaystyle v=8\times4\times12\)   and \(\displaystyle v=6\times4\times7\)

\(\displaystyle v=384in^3\)         and \(\displaystyle v=168in^3\)

Next, we add the volumes together to solve for the total volume of the original figure.

\(\displaystyle \frac{\begin{array}[b]{r}384in^3\\ +\ 168in^3\end{array}}{ \ \ \ \space 552in^3}\)

*Remember, volume is always measured in cubic units! 

If you look closely at this figure, you can see that it is made up of two rectangular prisms. In order to solve for the volume, we need to find the volume of each rectangular prism and then add the volumes together to find the total.

In order to find the length of the rectangular prism on the right, we had to take the length of the original figure (which was \(\displaystyle 17\)) and subtract the length of the rectangular prism on the left (which is \(\displaystyle 9\))

\(\displaystyle 17-9=8\)

Now that we have the dimensions of both our rectangular prisms, we can solve for the volumes. 

Remember, the formula for volume is 

\(\displaystyle v=l\times w\times h\)

\(\displaystyle v=9\times5\times12\)   and \(\displaystyle v=8\times5\times6\)

\(\displaystyle v=540in^3\)         and \(\displaystyle v=240in^3\)

Next, we add the volumes together to solve for the total volume of the original figure.

\(\displaystyle \frac{\begin{array}[b]{r}540in^3\\ +\ 240in^3\end{array}}{ \ \ \ \space 780in^3}\)

*Remember, volume is always measured in cubic units!