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Common Core: 5th Grade Math : Measurement & Data

Study concepts, example questions & explanations for Common Core: 5th Grade Math

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All Common Core: 5th Grade Math Resources

7 Diagnostic Tests 225 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #1 : Recognize Volume As Additive: Ccss.Math.Content.5.Md.C.5c

What is the volume of the figure below?

Screen shot 2015 12 22 at 9.31.36 am

Possible Answers:

18in^3

48in^3

18in^2

20in^2

30in^3

Correct answer:

48in^3

Explanation:

If you look closely at this figure, you can see that it is made up of two rectangular prisms. In order to solve for the volume, we need to find the volume of each rectangular prism and then add the volumes together to find the total.

Screen shot 2015 12 22 at 9.32.19 am

In order to find the length of the rectangular prism on the right, we had to take the length of the original figure (which was ) and subtract the length of the rectangular prism on the left (which is )

5-2=3

Now that we have the dimensions of both our rectangular prisms, we can solve for the volumes.

Remember, the formula for volume is

$v=l\times w\times h$

$v=2\times3\times5$ and $v=3\times2\times3$

v=30in^3 and v=18in^3

Next, we add the volumes together to solve for the total volume of the original figure.

$\frac{\begin{array}[b]{r}30in^3\\ +\ 18in^3\end{array}}{ \ \ \ \space 48in^3}$

*Remember, volume is always measured in cubic units!

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Example Question #1 : Recognize Volume As Additive: Ccss.Math.Content.5.Md.C.5c

What is the volume of the figure below?

Screen shot 2015 12 22 at 9.47.11 am

Possible Answers:

75in^3

96in^2

171in^3

96in^3

75in^2

Correct answer:

171in^3

Explanation:

Screen shot 2015 12 22 at 9.46.50 am

9-4=5

Now that we have the dimensions of both our rectangular prisms, we can solve for the volumes.

Remember, the formula for volume is

$v=l\times w\times h$

$v=4\times3\times8$ and $v=5\times3\times5$

v=96in^3 and v=75in^3

Next, we add the volumes together to solve for the total volume of the original figure.

$\frac{\begin{array}[b]{r}96in^3\\ +\ 75in^3\end{array}}{ \ \ \space 171in^3}$

*Remember, volume is always measured in cubic units!

Report an Error

Example Question #2 : Recognize Volume As Additive: Ccss.Math.Content.5.Md.C.5c

What is the volume of the figure below?

Screen shot 2015 12 22 at 9.48.40 am

Possible Answers:

80in^3

80in^2

270in^3

350in^2

260in^3

Correct answer:

350in^2

Explanation:

Screen shot 2015 12 22 at 9.48.57 am

10-6=4

Now that we have the dimensions of both our rectangular prisms, we can solve for the volumes.

Remember, the formula for volume is

$v=l\times w\times h$

$v=6\times5\times9$ and $v=4\times4\times5$

v=270in^3 and v=80in^3

Next, we add the volumes together to solve for the total volume of the original figure.

$\frac{\begin{array}[b]{r}270in^3\\ +\ 80in^3\end{array}}{ \ \ \space 350in^3}$

*Remember, volume is always measured in cubic units!

Report an Error

Example Question #2 : Recognize Volume As Additive: Ccss.Math.Content.5.Md.C.5c

What is the volume of the figure below?

Screen shot 2015 12 22 at 9.50.01 am

Possible Answers:

725in^2

552in^3

300in^3

600in^3

252in^3

Correct answer:

552in^3

Explanation:

Screen shot 2015 12 22 at 9.49.41 am

12-6=6

Now that we have the dimensions of both our rectangular prisms, we can solve for the volumes.

Remember, the formula for volume is

$v=l\times w\times h$

$v=6\times5\times10$ and $v=6\times6\times7$

v=300in^3 and v=252in^3

Next, we add the volumes together to solve for the total volume of the original figure.

$\frac{\begin{array}[b]{r}300in^3\\ +\ 252in^3\end{array}}{ \ \ \ \space 552in^3}$

*Remember, volume is always measured in cubic units!

Report an Error

Example Question #4 : Recognize Volume As Additive: Ccss.Math.Content.5.Md.C.5c

What is the volume of the figure below?

Screen shot 2015 12 22 at 9.50.38 am

Possible Answers:

216in^3

216in^2

361in^3

316in^3

100in^2

Correct answer:

316in^3

Explanation:

Screen shot 2015 12 22 at 9.50.54 am

11-6=5

Now that we have the dimensions of both our rectangular prisms, we can solve for the volumes.

Remember, the formula for volume is

$v=l\times w\times h$

$v=6\times4\times9$ and $v=5\times4\times5$

v=216in^3 and v=100in^3

Next, we add the volumes together to solve for the total volume of the original figure.

$\frac{\begin{array}[b]{r}216in^3\\ +\ 100in^3\end{array}}{ \ \ \ \space 316in^3}$

*Remember, volume is always measured in cubic units!

Report an Error

Example Question #3 : Recognize Volume As Additive: Ccss.Math.Content.5.Md.C.5c

What is the volume of the figure below?

Screen shot 2015 12 22 at 9.51.50 am

Possible Answers:

100in^3

512in^3

426in^3

324in^3

432in^3

Correct answer:

324in^3

Explanation:

Screen shot 2015 12 22 at 9.51.28 am

13-6=7

Now that we have the dimensions of both our rectangular prisms, we can solve for the volumes.

Remember, the formula for volume is

$v=l\times w\times h$

$v=6\times3\times11$ and $v=7\times3\times6$

v=198in^3 and v=126in^3

Next, we add the volumes together to solve for the total volume of the original figure.

$\frac{\begin{array}[b]{r}198in^3\\ +\ 126in^3\end{array}}{ \ \ \ \space 324in^3}$

*Remember, volume is always measured in cubic units!

Report an Error

Example Question #4 : Recognize Volume As Additive: Ccss.Math.Content.5.Md.C.5c

What is the volume of the figure below?

Screen shot 2015 12 22 at 9.54.53 am

Possible Answers:

640in^3

520in^3

120in^3

400in^3

280in^3

Correct answer:

400in^3

Explanation:

Screen shot 2015 12 22 at 9.55.09 am

13-7=6

Now that we have the dimensions of both our rectangular prisms, we can solve for the volumes.

Remember, the formula for volume is

$v=l\times w\times h$

$v=7\times4\times10$ and $v=6\times4\times5$

v=280in^3 and v=120in^3

Next, we add the volumes together to solve for the total volume of the original figure.

$\frac{\begin{array}[b]{r}280in^3\\ +\ 120in^3\end{array}}{ \ \ \ \space 400in^3}$

*Remember, volume is always measured in cubic units!

Report an Error

Example Question #5 : Recognize Volume As Additive: Ccss.Math.Content.5.Md.C.5c

What is the volume of the figure below?

Screen shot 2015 12 22 at 9.55.46 am

Possible Answers:

352in^3

492in^3

140in^3

280in^3

600in^3

Correct answer:

492in^3

Explanation:

Screen shot 2015 12 22 at 9.55.29 am

15-8=7

Now that we have the dimensions of both our rectangular prisms, we can solve for the volumes.

Remember, the formula for volume is

$v=l\times w\times h$

$v=8\times4\times11$ and $v=7\times4\times5$

v=352in^3 and v=140in^3

Next, we add the volumes together to solve for the total volume of the original figure.

$\frac{\begin{array}[b]{r}352in^3\\ +\ 140in^3\end{array}}{ \ \ \ \space 492in^3}$

*Remember, volume is always measured in cubic units!

Report an Error

Example Question #311 : Measurement & Data

What is the volume of the figure below?

Screen shot 2015 12 22 at 9.56.34 am

Possible Answers:

724in^3

792in^3

552in^3

638in^2

492in^3

Correct answer:

552in^3

Explanation:

Screen shot 2015 12 22 at 9.56.51 am

14-8=6

Now that we have the dimensions of both our rectangular prisms, we can solve for the volumes.

Remember, the formula for volume is

$v=l\times w\times h$

$v=8\times4\times12$ and $v=6\times4\times7$

v=384in^3 and v=168in^3

Next, we add the volumes together to solve for the total volume of the original figure.

$\frac{\begin{array}[b]{r}384in^3\\ +\ 168in^3\end{array}}{ \ \ \ \space 552in^3}$

*Remember, volume is always measured in cubic units!

Report an Error

Example Question #311 : Measurement & Data

What is the volume of the figure below?

Screen shot 2015 12 22 at 9.57.53 am

Possible Answers:

540in^3

780in^3

240in^3

780in^2

540in^2

Correct answer:

780in^3

Explanation:

Screen shot 2015 12 22 at 9.57.37 am

17-9=8

Now that we have the dimensions of both our rectangular prisms, we can solve for the volumes.

Remember, the formula for volume is

$v=l\times w\times h$

$v=9\times5\times12$ and $v=8\times5\times6$

v=540in^3 and v=240in^3

Next, we add the volumes together to solve for the total volume of the original figure.

$\frac{\begin{array}[b]{r}540in^3\\ +\ 240in^3\end{array}}{ \ \ \ \space 780in^3}$

*Remember, volume is always measured in cubic units!

Report an Error

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Common Core: 5th Grade Math : Measurement & Data

Study concepts, example questions & explanations for Common Core: 5th Grade Math

All Common Core: 5th Grade Math Resources

Example Questions

Example Question #1 : Recognize Volume As Additive: Ccss.Math.Content.5.Md.C.5c

Example Question #1 : Recognize Volume As Additive: Ccss.Math.Content.5.Md.C.5c

Example Question #2 : Recognize Volume As Additive: Ccss.Math.Content.5.Md.C.5c

Example Question #2 : Recognize Volume As Additive: Ccss.Math.Content.5.Md.C.5c

Example Question #4 : Recognize Volume As Additive: Ccss.Math.Content.5.Md.C.5c

Example Question #3 : Recognize Volume As Additive: Ccss.Math.Content.5.Md.C.5c

Example Question #4 : Recognize Volume As Additive: Ccss.Math.Content.5.Md.C.5c

Example Question #5 : Recognize Volume As Additive: Ccss.Math.Content.5.Md.C.5c

Example Question #311 : Measurement & Data

Example Question #311 : Measurement & Data

All Common Core: 5th Grade Math Resources

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