To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$\displaystyle A=6\times 8$            $\displaystyle A=7\times 5$

$\displaystyle A=48in^2$           $\displaystyle A=35in^2$

To find our final answer, we need to add the areas together. 

$\displaystyle 48in^2+35in^2=83in^2$

To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$\displaystyle A=7\times 3$            $\displaystyle A=6\times 3$

$\displaystyle A=21in^2$           $\displaystyle A=18in^2$

To find our final answer, we need to add the areas together. 

$\displaystyle 21in^2+18in^2=39in^2$

To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$\displaystyle A=8\times 3$            $\displaystyle A=7\times 4$

$\displaystyle A=24in^2$           $\displaystyle A=28in^2$

To find our final answer, we need to add the areas together. 

$\displaystyle 24in^2+28in^2=52in^2$

To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$\displaystyle A=10\times 9$            $\displaystyle A=9\times 4$

$\displaystyle A=90in^2$           $\displaystyle A=36in^2$

To find our final answer, we need to add the areas together. 

$\displaystyle 90in^2+36in^2=126in^2$

To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$\displaystyle A=7\times 5$            $\displaystyle A=5\times 3$

$\displaystyle A=35in^2$           $\displaystyle A=15in^2$

To find our final answer, we need to add the areas together. 

$\displaystyle 35in^2+15in^2=50in^2$

To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$\displaystyle A=6\times 6$            $\displaystyle A=4\times 4$

$\displaystyle A=36in^2$           $\displaystyle A=16in^2$

To find our final answer, we need to add the areas together. 

$\displaystyle 36in^2+16in^2=52in^2$

To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$\displaystyle A=5\times 10$            $\displaystyle A=5\times 3$

$\displaystyle A=50in^2$           $\displaystyle A=15in^2$

To find our final answer, we need to add the areas together. 

$\displaystyle 50in^2+15in^2=65in^2$

To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$\displaystyle A=4\times 4$            $\displaystyle A=12\times 3$

$\displaystyle A=16in^2$           $\displaystyle A=36in^2$

To find our final answer, we need to add the areas together. 

$\displaystyle 16in^2+36in^2=52in^2$

To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$\displaystyle A=9\times 6$            $\displaystyle A=7\times 5$

$\displaystyle A=54in^2$           $\displaystyle A=35in^2$

To find our final answer, we need to add the areas together. 

$\displaystyle 54in^2+35in^2=89in^2$

To find the area of the figure above, we need to slip the figure into two rectangles. 

Using our area formula, $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$\displaystyle A=11\times 3$            $\displaystyle A=3\times 3$

$\displaystyle A=33in^2$           $\displaystyle A=9in^2$

To find our final answer, we need to add the areas together. 

$\displaystyle 33in^2+9in^2=42in^2$