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Common Core: 2nd Grade Math : Common Core Math: Grade 2

Study concepts, example questions & explanations for Common Core: 2nd Grade Math

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All Common Core: 2nd Grade Math Resources

7 Diagnostic Tests 217 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #121 : Operations

$\frac{\begin{array}[b]{r}11\\ -\ 6\end{array}}{ \ \ \ \space ?}$ $\displaystyle \frac{\begin{array}[b]{r}11\\ -\ 6\end{array}}{ \ \ \ \space ?}$

Possible Answers:

$\displaystyle 7$

$\displaystyle 5$

$\displaystyle 8$

$\displaystyle 4$

$\displaystyle 6$

Correct answer:

$\displaystyle 5$

Explanation:

To subtract we can count backwards. Start at $\displaystyle 11$ and count back $\displaystyle 6$.

$\displaystyle 11, 10, 9, 8, 7, 6, 5$

$\frac{\begin{array}[b]{r}11\\ -\ 6\end{array}}{ \ \ \ \space 5}$ $\displaystyle \frac{\begin{array}[b]{r}11\\ -\ 6\end{array}}{ \ \ \ \space 5}$

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Example Question #1702 : Common Core Math: Grade 2

$\frac{\begin{array}[b]{r}10\\ -\ 3\end{array}}{ \ \ \ \space ?}$ $\displaystyle \frac{\begin{array}[b]{r}10\\ -\ 3\end{array}}{ \ \ \ \space ?}$

Possible Answers:

$\displaystyle 11$

$\displaystyle 10$

$\displaystyle 8$

$\displaystyle 13$

$\displaystyle 7$

Correct answer:

$\displaystyle 7$

Explanation:

To subtract we can count backwards. Start at $\displaystyle 10$ and count back $\displaystyle 3$.

$\displaystyle 10, 9, 8, 7$

$\frac{\begin{array}[b]{r}10\\ -\ 3\end{array}}{ \ \ \ \space 7}$ $\displaystyle \frac{\begin{array}[b]{r}10\\ -\ 3\end{array}}{ \ \ \ \space 7}$

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Example Question #131 : How To Subtract

$\frac{\begin{array}[b]{r}9\\ -\ 7\end{array}}{ \ \ \ \space ?}$ $\displaystyle \frac{\begin{array}[b]{r}9\\ -\ 7\end{array}}{ \ \ \ \space ?}$

Possible Answers:

$\displaystyle 5$

$\displaystyle 3$

$\displaystyle 1$

$\displaystyle 4$

$\displaystyle 2$

Correct answer:

$\displaystyle 2$

Explanation:

To subtract we can count backwards. Start at $\displaystyle 9$ and count back $\displaystyle 7$.

$\displaystyle 9, 8, 7, 6, 5, 4, 3, 2$

$\frac{\begin{array}[b]{r}9\\ -\ 7\end{array}}{ \ \ \ \space 2}$ $\displaystyle \frac{\begin{array}[b]{r}9\\ -\ 7\end{array}}{ \ \ \ \space 2}$

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Example Question #131 : Operations

$\frac{\begin{array}[b]{r}9\\ -\ 9\end{array}}{ \ \ \ \space ?}$ $\displaystyle \frac{\begin{array}[b]{r}9\\ -\ 9\end{array}}{ \ \ \ \space ?}$

Possible Answers:

$\displaystyle 1$

$\displaystyle 13$

$\displaystyle 12$

$\displaystyle 18$

$\displaystyle 0$

Correct answer:

$\displaystyle 0$

Explanation:

To subtract we can count backwards. Start at $\displaystyle 9$ and count back $\displaystyle 9$.

$\displaystyle 9, 8,7 ,6 ,5 ,4, 3, 2, 1, 0$

$\frac{\begin{array}[b]{r}9\\ -\ 9\end{array}}{ \ \ \ \space 0}$ $\displaystyle \frac{\begin{array}[b]{r}9\\ -\ 9\end{array}}{ \ \ \ \space 0}$

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Example Question #41 : Operations & Algebraic Thinking

$\frac{\begin{array}[b]{r}8\\ -\ 5\end{array}}{ \ \ \ \space ?}$ $\displaystyle \frac{\begin{array}[b]{r}8\\ -\ 5\end{array}}{ \ \ \ \space ?}$

Possible Answers:

$\displaystyle 6$

$\displaystyle 2$

$\displaystyle 4$

$\displaystyle 3$

$\displaystyle 5$

Correct answer:

$\displaystyle 3$

Explanation:

To subtract we can count backwards. Start at $\displaystyle 8$ and count back $\displaystyle 5$.

$\displaystyle 8, 7, 6, 5, 4, 3$

$\frac{\begin{array}[b]{r}8\\ -\ 5\end{array}}{ \ \ \ \space 3}$ $\displaystyle \frac{\begin{array}[b]{r}8\\ -\ 5\end{array}}{ \ \ \ \space 3}$

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Example Question #131 : How To Subtract

$\frac{\begin{array}[b]{r}7\\ -\ 5\end{array}}{ \ \ \ \space ?}$ $\displaystyle \frac{\begin{array}[b]{r}7\\ -\ 5\end{array}}{ \ \ \ \space ?}$

Possible Answers:

$\displaystyle 2$

$\displaystyle 12$

$\displaystyle 1$

$\displaystyle 10$

$\displaystyle 9$

Correct answer:

$\displaystyle 2$

Explanation:

To subtract we can count backwards. Start at $\displaystyle 7$ and count back $\displaystyle 5$.

$\displaystyle 7, 6, 5, 4, 3, 2$

$\frac{\begin{array}[b]{r}7\\ -\ 5\end{array}}{ \ \ \ \space 2}$ $\displaystyle \frac{\begin{array}[b]{r}7\\ -\ 5\end{array}}{ \ \ \ \space 2}$

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Example Question #51 : Operations & Algebraic Thinking

$\frac{\begin{array}[b]{r}6\\ -\ 3\end{array}}{ \ \ \ \space ?}$ $\displaystyle \frac{\begin{array}[b]{r}6\\ -\ 3\end{array}}{ \ \ \ \space ?}$

Possible Answers:

$\displaystyle 4$

$\displaystyle 2$

$\displaystyle 9$

$\displaystyle 1$

$\displaystyle 3$

Correct answer:

$\displaystyle 3$

Explanation:

To subtract we can count backwards. Start at $\displaystyle 6$ and count back $\displaystyle 3$.

$\displaystyle 6, 5,4, 3$

$\frac{\begin{array}[b]{r}6\\ -\ 3\end{array}}{ \ \ \ \space 3}$ $\displaystyle \frac{\begin{array}[b]{r}6\\ -\ 3\end{array}}{ \ \ \ \space 3}$

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Example Question #52 : Operations & Algebraic Thinking

$\frac{\begin{array}[b]{r}5\\ -\ 4\end{array}}{ \ \ \ \space ?}$ $\displaystyle \frac{\begin{array}[b]{r}5\\ -\ 4\end{array}}{ \ \ \ \space ?}$

Possible Answers:

$\displaystyle 4$

$\displaystyle 3$

$\displaystyle 5$

$\displaystyle 2$

$\displaystyle 1$

Correct answer:

$\displaystyle 1$

Explanation:

To subtract we can count backwards. Start at $\displaystyle 5$ and count back $\displaystyle 4$.

$\displaystyle 5, 4, 3, 2, 1$

$\frac{\begin{array}[b]{r}5\\ -\ 4\end{array}}{ \ \ \ \space 1}$ $\displaystyle \frac{\begin{array}[b]{r}5\\ -\ 4\end{array}}{ \ \ \ \space 1}$

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Example Question #51 : Operations & Algebraic Thinking

$\frac{\begin{array}[b]{r}4\\ -\ 2\end{array}}{ \ \ \ \space ?}$ $\displaystyle \frac{\begin{array}[b]{r}4\\ -\ 2\end{array}}{ \ \ \ \space ?}$

Possible Answers:

$\displaystyle 5$

$\displaystyle 6$

$\displaystyle 3$

$\displaystyle 4$

$\displaystyle 2$

Correct answer:

$\displaystyle 2$

Explanation:

To subtract we can count backwards. Start at $\displaystyle 4$ and count back $\displaystyle 2$.

4, 3, 2 $\displaystyle 4, 3, 2$

$\frac{\begin{array}[b]{r}4\\ -\ 2\end{array}}{ \ \ \ \space 2}$ $\displaystyle \frac{\begin{array}[b]{r}4\\ -\ 2\end{array}}{ \ \ \ \space 2}$

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Example Question #52 : Operations & Algebraic Thinking

$\frac{\begin{array}[b]{r}3\\ -\ 3\end{array}}{ \ \ \ \space ?}$ $\displaystyle \frac{\begin{array}[b]{r}3\\ -\ 3\end{array}}{ \ \ \ \space ?}$

Possible Answers:

$\displaystyle 1$

$\displaystyle 0$

$\displaystyle 2$

$\displaystyle 6$

$\displaystyle 3$

Correct answer:

$\displaystyle 0$

Explanation:

To subtract we can count backwards. Start at $\displaystyle 3$ and count back $\displaystyle 3$.

3,2,1,0 $\displaystyle 3,2,1,0$

$\frac{\begin{array}[b]{r}3\\ -\ 3\end{array}}{ \ \ \ \space 0}$ $\displaystyle \frac{\begin{array}[b]{r}3\\ -\ 3\end{array}}{ \ \ \ \space 0}$

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All Common Core: 2nd Grade Math Resources

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Common Core: 2nd Grade Math : Common Core Math: Grade 2

Study concepts, example questions & explanations for Common Core: 2nd Grade Math

All Common Core: 2nd Grade Math Resources

Example Questions

Example Question #121 : Operations

Example Question #1702 : Common Core Math: Grade 2

Example Question #131 : How To Subtract

Example Question #131 : Operations

Example Question #41 : Operations & Algebraic Thinking

Example Question #131 : How To Subtract

Example Question #51 : Operations & Algebraic Thinking

Example Question #52 : Operations & Algebraic Thinking

Example Question #51 : Operations & Algebraic Thinking

Example Question #52 : Operations & Algebraic Thinking

All Common Core: 2nd Grade Math Resources

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