All Calculus 2 Resources
Example Questions
Example Question #391 : Limits
Find the following limit
To find the following limit
we can simply plug in to get
Example Question #392 : Calculus Ii
Find the following limit
To find the following limit
we can use the fact that and to get
Example Question #393 : Calculus Ii
Find the following limit
To find the following limit
we can simply plug in , since it's defined there, to get
Example Question #351 : Finding Limits And One Sided Limits
Evaluate:
To evaluate the limit, we factor out a term consisting of the highest power term divided by itself (so we are not changing the original function):
The term we factored out becomes 1, and all of the negative exponent terms go to zero as n goes to infinity (they are all fractions with an infinitely large denominator, so they equal zero). What is left is
Example Question #352 : Finding Limits And One Sided Limits
Find the limit:
The limit does not exist.
The first thing to do is to simply plug in the value that approaches. When you do this:
When you get this type of indeterminate form, you can use L'Hopital's Rule to evaluate the limit. This rules allows you to find the limit by taking the derivatives of the numerator and denominator.
The derivatives are:
The derivatives were found by using the following rule:
With the derivatives of the numerator and denominator taken, you can again plug in the number that approaches:
Example Question #351 : Finding Limits And One Sided Limits
Find the limit:
The limit does not exist.
The first thing to do is simply plug in the value that approaches:
The best way to find this limit is by using L'Hopital's Rule, but the indeterminate form that was found would not allow for you to use the rule. Therefore, you must manipulate the original function:
Now, find the limit:
This indeterminate form allows for you to use L'Hopital's Rule. This rule states that a limit can be found by taking the derivatives of the numerator and denominator of a function.
The derivatives are:
The rules that were used to find the derivatives are:
Now, the value that approaches can be plugged in to the new function:
Once again, you have an indeterminate form that allows you to apply L'Hopital's Rule again:
Now, the value that approaches can be plugged in to the new function:
Example Question #392 : Calculus Ii
For the function
Evaluate the limit
is defined as the limit as approaches from the right.
Doing so we evaluate
to find that
Example Question #353 : Finding Limits And One Sided Limits
Evaluate:
Step 1: We plug in into the function..
We see that the denominator will give me , which I cannot have.
Step 2: Use L'Hospital Rule:
Take the derivative of both the numerator and denominator until zero doesn't result in the denominator when x is substitute in for a specific value...
Taking derivative once:
Step 3: Plug in into the new function:
Example Question #392 : Limits
Does not exist.
The first step to solving limits is direct substituting the limit constant into the function. In this case, direct substitution is the only step.
Example Question #355 : Finding Limits And One Sided Limits
Does not exist.
Infinity.
The first step to solving limits is plugging in the value specified in the problem.
Unfortunately, in this problem, we have a divide by zero after the substitution. That is not allowed, so we must seek a different method. The numerator of this fraction is a difference of squares. Therefore, we need to factor the numerator, which will cancel the factor in the denominator. Then, we can direct substitute.
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