All Calculus 2 Resources
Example Questions
Example Question #131 : Calculus Ii
Evaluate the limit:
There is no limiting situation in this equation (like a denominator) so we can just plug in the value that x approaches into the limit and solve:
Example Question #132 : Calculus Ii
Evaluate the limit:
The limiting situation in this equation would be the denominator. Plug the value that x is approaching into the denominator to see if the denominator will equal 0. In this question, the denominator will not equal zero when x=0; so we proceed to insert the value of x into the entire equation.
Example Question #133 : Calculus Ii
Evaluate the limit:
The limiting situation in this equation would be the denominator. Plug the value that x is approaching into the denominator to see if the denominator will equal 0. In this question, the denominator will not equal zero when x=1001; so we proceed to insert the value of x into the entire equation.
Example Question #134 : Calculus Ii
Evaluate the limit:
The limiting situation in this equation would be the denominator. Plug the value that x is approaching into the denominator to see if the denominator will equal 0. In this question, the denominator will not equal zero when x=2; so we proceed to insert the value of x into the entire equation.
Example Question #92 : Finding Limits And One Sided Limits
Given the above graph of , what is ?
Does Not Exist
Does Not Exist
Examining the graph above, we need to look at three things:
1) What is the limit of the function as approaches zero from the left?
2) What is the limit of the function as approaches zero from the right?
3) What is the function value as and is it the same as the result from statement one and two?
Therefore, we can observe that does not exist, as approaches two different limits: from the left and from the right.
Example Question #135 : Calculus Ii
Given the above graph of , what is ?
Examining the graph, we want to find where the graph tends to as it approaches zero from the left hand side. We can see that there appears to be a vertical asymptote at zero. As the x values approach zero from the left, the function values of the graph tend towards negative infinity.
Thus, we can observe that as approaches from the left.
Example Question #94 : Finding Limits And One Sided Limits
Given the above graph of , what is ?
Examining the graph, we want to find where the graph tends to as it approaches zero from the right hand side. We can see that there appears to be a vertical asymptote at zero. As the x values approach zero from the right, the function values of the graph tend towards negative infinity.
Therefore, we can observe that as approaches from the right.
Example Question #95 : Finding Limits And One Sided Limits
Determine the following limit.
First, we can factor the numerator to obtain the following form.
The term can now cancel on the numerator and denominator. Therefore, this problem becomes
Alternatively we can also use L'Hopital's rule since the limit of the following is not defined. L'Hopital's rule states to take the derivative of both the numerator and the denominator then substitute the value into the new fraction. Repeat those steps until the limit is found.
Taking the derivative of the numerator and denominator with respect to , we get
Example Question #136 : Calculus Ii
Evaluate the following limit:
The limit does not exist.
To evaluate the limit, we must first determine whether the limit is a right or left sided limit; the plus sign indicates that values slightly greater than 1 are being approached (from the right side), so the function that we use the second function, corresponding to values greater than or equal to 1. When we plug 1 into this function, we get our answer, .
Example Question #137 : Calculus Ii
Evaluate the following limit:
To evaluate the limit, we must first determine whether the limit is being approached from the right or left. The negative sign "exponent" on 4 indicates that numbers slightly less than 4 are being approached, and that the limit is being evaluated from the left side. Now, simply use the first function (for values less than 4) to evaluate the limit. We see that we get by subsituting 4 into the first function.
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