All Calculus 2 Resources
Example Questions
Example Question #131 : Finding Limits And One Sided Limits
Evaluating this limit will require use of L'Hopital's Rule, because when plugging in "-2" into the given function, it results in an indeterminate form of type 0/0.
We can now use L'Hopital's Rule, which requires us to take the derivative of the numerator and denominator of this function individually:
Example Question #182 : Limits
Given the above graph of , what is ?
Does Not Exist
Does Not Exist
Examining the graph, we can observe that does not exist, as is not continuous at . We can see this by checking the three conditions for which a function is continuous at a point :
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A value exists in the domain of
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The limit of exists as approaches
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The limit of at is equal to
Given , we can see that condition #1 is not satisfied because the graph has a vertical asymptote instead of only one value for and is therefore an infinite discontinuity at .
We can also see that condition #2 is not satisfied because approaches two different limits: from the left and from the right.
Based on the above, condition #3 is also not satisfied because is not equal to the multiple values of .
Thus, does not exist.
Example Question #182 : Calculus Ii
Given the above graph of , what is ?
Does Not Exist
Examining the graph, we can observe that as approaches from the left.
Example Question #183 : Calculus Ii
Given the above graph of , what is ?
Does Not Exist
Examining the graph, we can observe that as approaches from the right.
Example Question #181 : Calculus Ii
Evaluate the following limit:
To evaluate the limit, we must first determine whether the limit is right or left sided. The negative sign "exponent" on 1 indicatest that we are approaching one using values slightly less than 1, or from the left. Thus, we must use the part of the piecewise function corresponding to x values less than (or equal to) 1. When we evaluate
because the natural log function as it reaches zero equals negative infinity.
Example Question #185 : Calculus Ii
Evaluate the following limit:
To evaluate the limit, we must first pull out a factor consisting of the highest power term divided by the highest power term (so we are pulling out a factor of 1):
After the factor we pulled out cancels to become 1, and the negative power terms go to zero (infinity in the denominator makes zero), we are left with our final answer, .
Example Question #182 : Calculus Ii
Evaluate the following limit:
The limit does not exist
First, we must determine whether the limit is being approached from the left or right. The negative sign "exponent" on the 10 indicates we are approaching 10 from the left, or using values slightly less than 10. Therefore we must use the piecewise function associated with values less than 10. When we evaluate the limit using this function, we get 10.
Example Question #183 : Calculus Ii
Evaluate the following limit:
The limit does not exist
Because we are given a piecewise function without a one-sided limit, it is tempting to declare "the limit does not exist," when in reality, when 4 is approached from the left or right, both functions have the same output at 4, which is .
Example Question #184 : Calculus Ii
Evaluate the following limit:
The limit does not exist
The limit does not exist
We are given a piecewise function in which the limit differs depending on what side we approach 6 from. From the left side, we get a value of but from the right we get . The limit does not exist because this conflict remains (we don't have a one-sided limit).
Example Question #185 : Calculus Ii
Evaluate the following limit:
The limit does not exist
To evaluate the limit, we must see whether the limit is right or left sided. The plus sign "exponent" on the 0 indicates that we have a right sided limit, that we are approaching 0 using values slightly larger than 0. So, we must evaluate the limit using the part of the piecewise function corresponding to values greater than or equal to 0. When we do this, we get .