Calculus 1 : Graphing Functions

Study concepts, example questions & explanations for Calculus 1

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Example Questions

Example Question #1 : Lines

Find the equation of the line tangent to  at .

Possible Answers:

Correct answer:

Explanation:

To find the equation of the line at that point, you need two things: the slope at that point and the y adjustment of the function, in the form , where m is the slope and  is the y adjustment. To get the slope, find the derivative of  and plug in the desired point  for , giving us an answer of  for the slope.

To find the y adjustment pick a point 0 in the original function. For simplicity, let's plug in , which gives us a y of 1, so an easy point is . Next plug in those values into the equation of a line, . The new equation with all parameters plugged in is

Now you simply solve for , which is .

Final equation of the line tangent to  at  is 

Example Question #3 : Lines

Find the equation of the line tangent to  at .

Possible Answers:

Correct answer:

Explanation:

To get the slope, find the derivative of  and plug in the desired point  for , giving us an answer of  for the slope.

Remember that the derivative of .

 

To find the  adjustment pick a point  (for example) in the original  function. For simplicity, let's plug in , which gives us a  of , so an easy point is . Next plug in those values into the equation of a line, . The new equation with all parameters plugged in is

The coefficient in front of the  is the slope.

Now you simply solve for , which is .

Final equation of the line tangent to  at is .

Example Question #4 : Lines

Find the equation of the line tangent to  at  .

Possible Answers:

Correct answer:

Explanation:

The equation of the tangent line is  To find , the slope, calculate the derivative and plug in the desired point.

The next step is to choose a coordinate on the original  function. We can choose any  value and calculate its  value.

Let's choose .

The  value at this point is .

Plugging in those values we can solve for .

Solving for  we get =.

Example Question #3 : Lines

A function, , is given by

.

Find the line tangent to  at .

Possible Answers:

Correct answer:

Explanation:

First we need to find the slope of  at . To do this we need the derivative of . To take the derivative we need to use the power rule for the first term and recognize that the derivative of sine is cosine.

At,

 

Now we need to know

.

Now we have a slope,  and a point 

so we can use the point-slope formula to find the equation of the line.

Plugging in and rearranging we find

.

Example Question #2 : Lines

Let 

Find the equation for a line tangent to  when .

Possible Answers:

Correct answer:

Explanation:

First, evaluate  when .

Thus, we need a line that contains the point 

Next, find the derivative of  and evaluate it at .

To find the derivative we will use the power rule,

.

This indicates that we need a line with a slope of 8.

In point-slope form, , a line with the point  and a slope of 8 will be:

Example Question #4 : Lines

What is the equation of the line tangent to  at ? Round to the nearest hundreth. 

Possible Answers:

Correct answer:

Explanation:

The tangent line to  at  must have the same slope as .

Applying the chain rule we get

.

Therefore the slope of the line is, 

.

In addition, the tangent line touches the graph of  at . Since , the point  lies on the line.

Plugging in the slope and point we get .

Example Question #2711 : Calculus

Find the equation of the tangent line, where

, at .

Possible Answers:

Correct answer:

Explanation:

In order to find the equation of the tangent line at , we first find the slope.

To do this we need to find .

Since we have found , now we simply plug in 1.

Now we need to plug in 1, into , to find a point that the tangent line touches.

Now we can use point-slope form to figure out what the equation of the tangent line is at .

Remember that point-slope for is

where  and  is the point where the tangent line touches , and  is the slope of the tangent line.

In our case, , and .

Thus our tangent line equation at  is

.

 

Example Question #1 : Equation Of Line

Find the equation of the tangent line of 

, at .

Possible Answers:

Correct answer:

Explanation:

In order to find the equation of the tangent line at , we first find the slope.

To do this we need to find  using the power rule .

Since we have found , now we simply plug in 1.

Now we need to plug in 1, into , to find a point that the tangent line touches.

Now we can use point-slope form to figure out what the equation of the tangent line is at .

Remember that point-slope for is

where  and  is the point where the tangent line touches , and  is the slope of the tangent line.

In our case, , and .

Thus our tangent line equation at  is

.

 

Example Question #11 : How To Find Equation Of Line By Graphing Functions

Give the general equation for the line tangent to  at the point .

Possible Answers:

Correct answer:

Explanation:

The equation of the tangent line has the form .

The slope  can be determined by evaluating the derivative of the function at .

Plugging this into the point slope equation, we get

 can be determined by evaluating the original function at .

Plugging this into the previous equation and simplifying gives us

Example Question #2714 : Calculus

Find the slope of the line tangent to the following function at .

Possible Answers:

None of these

Correct answer:

Explanation:

To find the slope of the line tangent you must take the derivative of the function. The derivative of cosine is negative sine and the derivative of sine is cosine.

This makes the derivative of the function

.

Plug in the given x to get the slope.

 

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