All Calculus 1 Resources
Example Questions
Example Question #21 : Equations
Set up the integral to find the area of a region bounded by the curve from to .
In order to find the area of the region under the curve of the parabola, simply integrate from the given bounds. Ensure that there is no negative area within the bounds by setting the parabola equal to zero.
After testing the numbers to the left and right of the critical values, the positive region is in between bounds.
Set up the integral.
Example Question #21 : Integral Expressions
Evaluate:
We get this by applying the inverse power rule to each polynomial term.
Therefore we get,
Since this is an indefinite integral, we need to add a constant term at the end of the function.
Example Question #2101 : Calculus
Evaluate:
In order to evaluate the integral, we need to use the inverse power law and the integral of trig functions.
Remember that the inverse power rule is
and the integral of sine is a negative cosine.
Example Question #1074 : Functions
Evaluate:
In order to evaluate the integral, we need to use the inverse power rule.
Remember that the inverse power rule is
Remember to have the constant term since this is an indefinite integral.
Example Question #21 : Equations
Evalulate:
We evaluate the definite integral by using the definition of the integral for .
Example Question #1076 : Functions
A given derivative is defined as . What is ?
None of the above
In order to find , we must take the indefinite integral of the given derivative .
Noting that the power rule for integrals is
for all and with an arbitrary constant of integration ,
we can determine that
.
Example Question #1077 : Functions
A given derivative is defined as . What is ?
None of the above
In order to find , we must take the indefinite integral of the given derivative .
Noting that the power rule for integrals is
for all and with an arbitrary constant of integration ,
we can determine that
.
Example Question #1078 : Functions
A given derivative is defined as . What is ?
None of the above
In order to find , we must take the indefinite integral of the given derivative .
Noting that the power rule for integrals is
for all and with an arbitrary constant of integration ,
we can determine that
.
Example Question #1079 : Functions
Evaluate the indefinite integral:
To integrate, one must use the "u-substitution" or substitution method for integration, because one cannot simply integrate .
In this case, we are calling , and therefore .
Replace with , and with .
The integral becomes far easier:
, and is equal to .
The rule used for this integration is
.
(The constant -3/2 remains unchanged.) Finally, replace with to go back to the original variable/term being integrated.
Example Question #1081 : Functions
Evaluate .
Take the anti-derivative (integrate using the Power Rule : ) of the expression:
Plug in the number at the top of the integral:
Then, plug in the number at the bottom of the integral:
Lastly, subtract the top from the bottom:
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