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Example Questions
Example Question #31 : Homeostasis And The Biological Environment
Suppose that a biochemist is interested in studying the carbonic acid/bicarbonate buffer system in humans. To that end, the biochemist needs to make a solution of carbonic acid/bicarbonate buffer at a pH of 7.4. Assuming that the dissociation of bicarbonate is negligible, how many moles each of carbonic acid and sodium bicarbonate does the biochemist need in order to achieve a solution at this pH?
Note: The pKa of carbonic acid is 6.35.
carbonic acid and bicarbonate
carbonic acid and bicarbonate
carbonic acid and bicarbonate
carbonic acid and bicarbonate
carbonic acid and bicarbonate
carbonic acid and bicarbonate
In this question, we're told that a buffer solution consisting of carbonic acid and bicarbonate needs to be prepared. The solution needs to have a concentration of , a volume of , and a pH of .
First, we need to recognize that in order to solve this problem, we'll need to utilize the Henderson-Hasselbalch equation.
The acid in the above expression will be carbonic acid, and its conjugate base is bicarbonate. We can plug in the values we have for pH and pKa to obtain the ratio of base to acid.
Now that we have the ratio of base to acid, we can figure out what fraction of our solution will be base, and what fraction of it will be acid. To find this fraction, we have to realize that for every moles of base, there is mole of acid. Thus, there are a total of moles of acid and base.
Next, we need to take into account the volume and molarity that we want in our desired solution in order to find the total number of moles for our final solution.
Equipped with knowing how many total moles we want in our desired solution, in addition to the portion of our solution that is acid and the portion that is base, we can at last calculate how many moles each of carbonic acid and bicarbonate we need in our solution.
Carbonic acid:
Bicarbonate:
Example Question #31 : Homeostasis And The Biological Environment
The higher the concentration of , the lower the affinity hemoglobin has for binding oxygen. Why is this the case?
concentration is highest in the lungs. This therefore facilitates hemoglobin offloading oxygen near these tissues so that it can bind carbon dioxide.
If one's blood has too much in it, hemoglobin begins to bind it instead of oxygen so that the cells can use carbon dioxide to respire through an alternate pathway.
concentration is lowest in the peripheral tissues, such as the muscle. This therefore facilitates hemoglobin binding oxygen around these tissues so that they can use the oxygen.
concentration is highest in the peripheral tissues, such as the muscle. This therefore facilitates hemoglobin offloading oxygen so that it can be delivered to actively respiring tissues which need it.
concentration is highest in the peripheral tissues, such as the muscle. This therefore facilitates hemoglobin binding more oxygen near these tissues so that the oxygen can be delivered to more important tissues, such as the brain.
concentration is highest in the peripheral tissues, such as the muscle. This therefore facilitates hemoglobin offloading oxygen so that it can be delivered to actively respiring tissues which need it.
Carbon dioxide concentration is low in the blood surrounding the lungs and high in those around muscle, relatively speaking, because cell respiration by the muscles produces carbon dioxide. Therefore, hemoglobin binds oxygen quite well at the lungs, as it should in order for us to be able to breathe, and then binds it much less effectively around the muscles. This allows the oxygen to unbind and enter the muscle tissue (this process is facilitated by myoglobin) where it is used by the actively respiring muscle cells.
Example Question #32 : Homeostasis And The Biological Environment
Heavy exercise results in heavy breathing in order to maximize oxygen and rid excess carbon dioxide, but it also results in a temporary increase in lactic acid levels (lactic acidosis) near the working muscles. This slightly lowers the pH of the blood. Why would rapidly eliminating carbon dioxide help raise the pH of the blood back to normal levels?
Ridding of causes the pH of the blood to drop because is an acidic molecule itself
Ridding of increases the relative amount of freely dissolved oxygen in plasma, which binds to protons to form water
Ridding of causes carbonic anhydrase to convert more carbonic acid to and water, raising the pH by removing protons
Ridding of causes carbonic anhydrase to convert more and water to carbonic acid, raising the pH by removing protons
Ridding of causes the pH of the blood to drop because is a basic molecule itself
Ridding of causes carbonic anhydrase to convert more carbonic acid to and water, raising the pH by removing protons
Carbonic anhydrase in red blood cells catalyzes the following equilibrium reaction:
The carbonic acid formed then naturally gives up a proton to form . This is why elevated levels lower the blood pH. When more is removed through more rapid breathing, this shifts the equilibrium reaction back to the left (Le Chatelier's principle), prompting more and to turn into which then turns into and . Thus, carbonic anhydrase now catalyzes the reaction toward the left in this scenario, raising the pH. is neither an acidic nor basic molecule by itself (and if it were basic then ridding of it would actually lower the pH further), and while the answer involving oxygen may be tempting, oxygen is not found dissolved in blood plasma; it is bound to hemoglobin, and thus it does not bind protons in the blood to form water.
Example Question #14 : P H Regulation
If the pH of blood is considered to be 7.4 and the pKa of a compound in the blood is 6.4, what is the ratio of the acid form of the compound to the base form of the compound?
Using the Henderson Hasselbach equation:
Thus, the ratio of acid to base =
Example Question #12 : P H Regulation
Calculate the pH of an ammonia buffer when the molar ratio of is . The pKa to be used is 9.75.
This question requires you to use the Henderson-Hasselbach equation, one of the most important equations in biochemistry. The equation is:
where is the concentration of the conjugate base, and is the concentration of the acid. In this scenario, is the conjugate base, while is the acid. With the numbers given in this question, the equation should look like this:
Example Question #31 : Homeostasis And The Biological Environment
What is the hydrogen ion concentration of an solution with a pH of 3.5?
Here is the equation used to find the correct answer:
Example Question #589 : Biochemistry
Is water an acid or a base?
Acid
Base
It is impossible to predict.
Both
Both
Water, , is an amphoteric substance--it can act as either an acid or a base. In certain circumstances, water can act as a Bronsted-Lowry acid by donating a proton.
As seen above, donated one of its hydrogen atoms, becoming .
In other cases, water can act as a Bronsted-Lowry base by accepting a proton.
As seen above, accepted a hydrogen atom to become .
Therefore, water can act as either an acid or a base depending on the situation. There are other amphoteric substances, but water is definitely the most common.
Example Question #201 : Fundamental Macromolecules And Concepts
What is the pH of a solution of ?
Here is the equation that you need to find the answer.
Thus, the pH of this solution is closest to .
Example Question #201 : Fundamental Macromolecules And Concepts
If a patient's lab values from the doctor's office show a blood plasma pH of 7.1, which of the following could be the correct diagnosis?
Respiratory alkalosis
Metabolic alkalosis
Respiratory acidosis
The results show normal blood plasma pH.
Respiratory acidosis
Normal blood pH is 7.4. A decrease in pH could indicate acidosis, which is associated with too much in the blood. Respiratory acidosis occurs as the result of the lungs failing to eliminate enough .
Example Question #22 : P H Regulation
What is the concentration in an solution with a pH of ?
Here is the equation needed to find the correct answer to this question.
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