Call Now to Set Up Tutoring:

(888) 888-0446

Basic Geometry : Quadrilaterals

Study concepts, example questions & explanations for Basic Geometry

Create An Account

All Basic Geometry Resources

9 Diagnostic Tests 164 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #211 : Quadrilaterals

Find the area of a rectangle given length 7 and width 2.

Possible Answers:

Correct answer:

Explanation:

To solve, simply use the formula for the area of a rectangle. Thus,

A=l*w=7*2=14

If you forget the formula, simply imagine you have two rows of blocks with 7 in them each. If you count the total number of blocks you have, you will realize you have 14!

Report an Error

Example Question #619 : Basic Geometry

If the radius of the circle is , find the area of the shaded region of the rectangle.

Possible Answers:

201.32

202.28

209.46

208.64

Correct answer:

209.46

Explanation:

In order to find the area of the shaded region, we will need to subtract the area of the circle from the area of the rectangle.

Let's start by finding the area of a circle. Recall the formula to find the area of a circle:

$\text{Area of circle}=\pi\times\text{radius}^2$

Substitute in the value of the radius, which is given by the question.

$\text{Area of circle}=\pi\times(5)^2$

$\text{Area of circle}=25\pi$

Now, recall how to find the area of a rectangle.

$\text{Area of Rectangle}=\text{length}\times\text{width}$

Substitute in the values given by the figure to find the area of the rectangle.

$\text{Area of Rectangle}=12 \times 24$

$\text{Area of Rectangle} =288$

Now, find the area of the shaded region.

$\text{Area of shaded region}=\text{Area of Rectangle}-\text{Area of Circle}$

$\text{Area of shaded region}=288-25\pi$

Solve and round to two decimal places.

$\text{Area of shaded region}=209.46$

Report an Error

Example Question #212 : Quadrilaterals

If the radius of the circle is , find the area of the shaded region of the rectangle.

Possible Answers:

365.21

398.74

373.24

336.90

Correct answer:

336.90

Explanation:

In order to find the area of the shaded region, we will need to subtract the area of the circle from the area of the rectangle.

Let's start by finding the area of a circle. Recall the formula to find the area of a circle:

$\text{Area of circle}=\pi\times\text{radius}^2$

Substitute in the value of the radius, which is given by the question.

$\text{Area of circle}=\pi\times(6)^2$

$\text{Area of circle}=36\pi$

Now, recall how to find the area of a rectangle.

$\text{Area of Rectangle}=\text{length}\times\text{width}$

Substitute in the values given by the figure to find the area of the rectangle.

$\text{Area of Rectangle}=15 \times 30$

$\text{Area of Rectangle}=450$

Now, find the area of the shaded region.

$\text{Area of shaded region}=\text{Area of Rectangle}-\text{Area of Circle}$

$\text{Area of shaded region}=450-36\pi$

Solve and round to two decimal places.

$\text{Area of shaded region}=336.90$

Report an Error

Example Question #64 : How To Find The Area Of A Rectangle

If the radius of the circle is $\frac{2}{3}$ , what is the area of the shaded region of the rectangle?

Possible Answers:

17.50

16.33

16.98

16.60

Correct answer:

16.60

Explanation:

In order to find the area of the shaded region, we will need to subtract the area of the circle from the area of the rectangle.

Let's start by finding the area of a circle. Recall the formula to find the area of a circle:

$\text{Area of circle}=\pi\times\text{radius}^2$

Substitute in the value of the radius, which is given by the question.

$\text{Area of circle}=\pi\times\left(\frac{2}{3}\right)^2$

$\text{Area of circle}=\frac{4}{9}\pi$

Now, recall how to find the area of a rectangle.

$\text{Area of Rectangle}=\text{length}\times\text{width}$

Substitute in the values given by the figure to find the area of the rectangle.

$\text{Area of Rectangle}=3\times 6$

$\text{Area of Rectangle}=18$

Now, find the area of the shaded region.

$\text{Area of shaded region}=\text{Area of Rectangle}-\text{Area of Circle}$

$\text{Area of shaded region}=18-\frac{4}{9}\pi$

Solve and round to two decimal places.

$\text{Area of shaded region}=16.60$

Report an Error

Example Question #213 : Quadrilaterals

If the radius of the circle is 1.3 , what is the area of the shaded region of the rectangle?

Possible Answers:

21.69

21.99

20.54

20.79

Correct answer:

21.69

Explanation:

In order to find the area of the shaded region, we will need to subtract the area of the circle from the area of the rectangle.

Let's start by finding the area of a circle. Recall the formula to find the area of a circle:

$\text{Area of circle}=\pi\times\text{radius}^2$

Substitute in the value of the radius, which is given by the question.

$\text{Area of circle}=\pi\times(1.3)^2$

$\text{Area of circle}=1.69\pi$

Now, recall how to find the area of a rectangle.

$\text{Area of Rectangle}=\text{length}\times\text{width}$

Substitute in the values given by the figure to find the area of the rectangle.

$\text{Area of Rectangle}=3\times 9$

$\text{Area of Rectangle}=27$

Now, find the area of the shaded region.

$\text{Area of shaded region}=\text{Area of Rectangle}-\text{Area of Circle}$

$\text{Area of shaded region}=27-1.69\pi$

Solve and round to two decimal places.

$\text{Area of shaded region}=21.69$

Report an Error

Example Question #214 : Quadrilaterals

If the radius of the circle is , what is the area of the shaded region of the rectangle?

Possible Answers:

37.15

32.43

33.69

31.02

Correct answer:

32.43

Explanation:

In order to find the area of the shaded region, we will need to subtract the area of the circle from the area of the rectangle.

Let's start by finding the area of a circle. Recall the formula to find the area of a circle:

$\text{Area of circle}=\pi\times\text{radius}^2$

Substitute in the value of the radius, which is given by the question.

$\text{Area of circle}=\pi\times(2)^2$

$\text{Area of circle}=4\pi$

Now, recall how to find the area of a rectangle.

$\text{Area of Rectangle}=\text{length}\times\text{width}$

Substitute in the values given by the figure to find the area of the rectangle.

$\text{Area of Rectangle}=5\times 9$

$\text{Area of Rectangle}=45$

Now, find the area of the shaded region.

$\text{Area of shaded region}=\text{Area of Rectangle}-\text{Area of Circle}$

$\text{Area of shaded region}=45-4\pi$

Solve and round to two decimal places.

$\text{Area of shaded region}=32.43$

Report an Error

Example Question #71 : How To Find The Area Of A Rectangle

If the radius of the circle is 3.2 , what is the area of the shaded region of the rectangle?

Possible Answers:

70.67

74.89

72.83

71.54

Correct answer:

72.83

Explanation:

In order to find the area of the shaded region, we will need to subtract the area of the circle from the area of the rectangle.

Let's start by finding the area of a circle. Recall the formula to find the area of a circle:

$\text{Area of circle}=\pi\times\text{radius}^2$

Substitute in the value of the radius, which is given by the question.

$\text{Area of circle}=\pi\times(3.2)^2$

$\text{Area of circle}=10.24\pi$

Now, recall how to find the area of a rectangle.

$\text{Area of Rectangle}=\text{length}\times\text{width}$

Substitute in the values given by the figure to find the area of the rectangle.

$\text{Area of Rectangle}=7\times 15$

$\text{Area of Rectangle}=105$

Now, find the area of the shaded region.

$\text{Area of shaded region}=\text{Area of Rectangle}-\text{Area of Circle}$

$\text{Area of shaded region}=105-10.24\pi$

Solve and round to two decimal places.

$\text{Area of shaded region}=72.83$

Report an Error

Example Question #623 : Plane Geometry

If the radius of the circle is , what is the area of the shaded region of the rectangle?

Possible Answers:

83.73

80.05

81.11

84.69

Correct answer:

83.73

Explanation:

In order to find the area of the shaded region, we will need to subtract the area of the circle from the area of the rectangle.

Let's start by finding the area of a circle. Recall the formula to find the area of a circle:

$\text{Area of circle}=\pi\times\text{radius}^2$

Substitute in the value of the radius, which is given by the question.

$\text{Area of circle}=\pi\times(3)^2$

$\text{Area of circle}=9\pi$

Now, recall how to find the area of a rectangle.

$\text{Area of Rectangle}=\text{length}\times\text{width}$

Substitute in the values given by the figure to find the area of the rectangle.

$\text{Area of Rectangle}=7\times 16$

$\text{Area of Rectangle}=112$

Now, find the area of the shaded region.

$\text{Area of shaded region}=\text{Area of Rectangle}-\text{Area of Circle}$

$\text{Area of shaded region}=112-9\pi$

Solve and round to two decimal places.

$\text{Area of shaded region}=83.73$

Report an Error

Example Question #73 : How To Find The Area Of A Rectangle

If the radius of the circle is $\frac{3}{4}$ , find the area of the shaded region of the rectangle.

Possible Answers:

14.23

11.22

13.97

12.68

Correct answer:

14.23

Explanation:

In order to find the area of the shaded region, we will need to subtract the area of the circle from the area of the rectangle.

Let's start by finding the area of a circle. Recall the formula to find the area of a circle:

$\text{Area of circle}=\pi\times\text{radius}^2$

Substitute in the value of the radius, which is given by the question.

$\text{Area of circle}=\pi\times\left(\frac{3}{4} \right) ^2$

$\text{Area of circle}=\frac{9}{16}\pi$

Now, recall how to find the area of a rectangle.

$\text{Area of Rectangle}=\text{length}\times\text{width}$

Substitute in the values given by the figure to find the area of the rectangle.

$\text{Area of Rectangle}=2\times 8$

$\text{Area of Rectangle}=16$

Now, find the area of the shaded region.

$\text{Area of shaded region}=\text{Area of Rectangle}-\text{Area of Circle}$

$\text{Area of shaded region}=16-\frac{9}{16}\pi$

Solve and round to two decimal places.

$\text{Area of shaded region}=14.23$

Report an Error

Example Question #74 : How To Find The Area Of A Rectangle

If the radius of the circle is 3.75 , what is the area of the shaded region of the rectangle?

Possible Answers:

89.66

81.64

83.82

85.47

Correct answer:

83.82

Explanation:

In order to find the area of the shaded region, we will need to subtract the area of the circle from the area of the rectangle.

Let's start by finding the area of a circle. Recall the formula to find the area of a circle:

$\text{Area of circle}=\pi\times\text{radius}^2$

Substitute in the value of the radius, which is given by the question.

$\text{Area of circle}=\pi\times(3.75)^2$

$\text{Area of circle}=14.0625\pi$

Now, recall how to find the area of a rectangle.

$\text{Area of Rectangle}=\text{length}\times\text{width}$

Substitute in the values given by the figure to find the area of the rectangle.

$\text{Area of Rectangle}=8\times 16$

$\text{Area of Rectangle}=128$

Now, find the area of the shaded region.

$\text{Area of shaded region}=\text{Area of Rectangle}-\text{Area of Circle}$

$\text{Area of shaded region}=128-14.0625\pi$

Solve and round to two decimal places.

$\text{Area of shaded region}=83.82$

Report an Error

View Tutors

Shruthi
Certified Tutor

Nottingham Trent University, Bachelor of Science, Biomedical Engineering.

View Tutors

Londyn
Certified Tutor

University of Central Missouri, Bachelor of Commerce, Business, General.

View Tutors

Matthew
Certified Tutor

Bluffton University, Bachelor of Education, Mathematics. Bluffton University, Masters in Education, Education.

All Basic Geometry Resources

9 Diagnostic Tests 164 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

French Tutors in Seattle, Reading Tutors in Boston, Biology Tutors in Boston, Chemistry Tutors in Seattle, ISEE Tutors in Chicago, Chemistry Tutors in Philadelphia, Statistics Tutors in Boston, Calculus Tutors in Washington DC, GMAT Tutors in Washington DC, Calculus Tutors in Atlanta

Popular Courses & Classes

Spanish Courses & Classes in San Francisco-Bay Area, SAT Courses & Classes in San Francisco-Bay Area, SSAT Courses & Classes in San Francisco-Bay Area, GMAT Courses & Classes in Los Angeles, GMAT Courses & Classes in Dallas Fort Worth, GMAT Courses & Classes in San Diego, SAT Courses & Classes in Denver, ACT Courses & Classes in San Francisco-Bay Area, LSAT Courses & Classes in Seattle, MCAT Courses & Classes in Denver

Popular Test Prep

SSAT Test Prep in Atlanta, LSAT Test Prep in Boston, GRE Test Prep in New York City, ACT Test Prep in Seattle, MCAT Test Prep in Washington DC, GMAT Test Prep in Los Angeles, GMAT Test Prep in San Diego, SSAT Test Prep in Chicago, MCAT Test Prep in Dallas Fort Worth, MCAT Test Prep in Denver

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

Basic Geometry : Quadrilaterals

Study concepts, example questions & explanations for Basic Geometry

All Basic Geometry Resources

Example Questions

Example Question #211 : Quadrilaterals

Example Question #619 : Basic Geometry

Example Question #212 : Quadrilaterals

Example Question #64 : How To Find The Area Of A Rectangle

Example Question #213 : Quadrilaterals

Example Question #214 : Quadrilaterals

Example Question #71 : How To Find The Area Of A Rectangle

Example Question #623 : Plane Geometry

Example Question #73 : How To Find The Area Of A Rectangle

Example Question #74 : How To Find The Area Of A Rectangle

All Basic Geometry Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: