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Example Questions
Example Question #1 : How To Find The Distance Between Clock Hands
The minute hand of a clock is exactly six inches in length, and the tip of the minute hand has traveled exactly ten inches since noon. To the nearest minute, what time is it?
12:32
12:28
12:08
12:44
12:16
12:16
The path traveled by the tip of the minute hand over the course of one hour is a circle of radius . The circumference of that circle is
.
The tip has traveled 10 inches since noon, so the fraction of the circle traveled is ,
and the number of minutes that have expired since noon is .
Therefore, to the nearest minute, the time is 12:16.
Example Question #2 : How To Find The Distance Between Clock Hands
What is the distance, in minutes and seconds, between the minute and hour hands of a clock at ?
The clock face is divided into sixty equal parts, each minute. The minute hand is located on the 20 minute mark at 6:20, the hour hand located between the 30 minute mark and the 35 minute mark. When the minute hand goes all sixty minutes, the hour hand only moves five, so to figure out the location of the hour hand, we look at how much the hour has progressed, in this case 20 minutes, or one third of the hour. So the minute hand has moved one third of the way through the hour, so has the hour hand moved one third of the way through the five minutes, or, five thirds of a minute, which is one and two thirds minute, one minute forty seconds. That puts the hour hand at thirty minutes plus one minute and forty seconds—at 31min 40sec—which is 11min 40sec farther than the minute hand.
Example Question #1 : Clock Math
Which pair of hands is further apart and by how much? Clock A is pointing at and the hands on clock B arevpointing at .
A's hands are further apart by
B's hands are further apart by
A's hands are further apart by
B's hand are further apart by
A's hands are further apart by
The distance between A's hands is simple to find, the minute hand is on the 6 at 30 minutes, halfway through the hour and the hour hand is resting just past the 3 at 15 minutes. What the minute hand travels in an hour, the hour hand travels in five minutes, so halfway through five minutes is added to 15 minutes puts the hour hand at 17.5 minutes.
To find the distance we subtract 17.5 from 30:
Therefore A's hands have a 12.5 minutes distance.
The distance between B's hands is the same procedure, the minute hand is on the 7 at 35 minutes, 35/60 through the hour, and the hour hand is resting past the 4 at 20 minutes, so is added to 20, which is approximately 23 minutes, To find the distance we subtract 23 from the 35:
putting B's hands 12 minutes apart.
Example Question #2 : Clock Math
Find the distance between the clock hands when the time is . The hour hand is mm and the minute hand is mm (you do not have to measure tip to tip).
The first thing you will have to do is determine the degrees that the hour hand is away from the minute hand. To help find the degrees of the hour and minute hand, you have to realize that when the minute hand is at 30 minutes, the hour hand is halfway between the hours of 10 and 11. Using the fact that at 9:00, the hour and minute hands create a angle. Knowing that the hour hand is in between 10 and 11, which is HALFWAY between 9 and 12, the hour hand and the 12 create a angle. So adding that to the the half circle creates from 12 to 6, then the total would be:
Using the degrees and the circumference of a circle, you can find the distance of the arc length with the following formula.
where,
The minute hand represents our radius therefore .
Therefore, our equation becomes:
Example Question #2 : How To Find The Distance Between Clock Hands
A certain clock has a minute hand 12 cm long and an hour hand that is 9 cm long. At 9:00, how far apart are the ends to the two hands of the clock?
A picture will help a bunch for this problem, so we begin by looking at a clock at 9:00
We should notice two things. The first is that by drawing in the distance we wish to find, namely that between the ends of the two hands, we end up with a triangle. Secondly, remembering that a full circle is 360 degrees, we see that the distance between the two hands spans 3 hours, or one fourth of the circle. One fourth of 360 is 90, so the angle between our two hands is a right angle.
We now realize that we have a right triangle, and our desired distance is simply the hypotenuse, which we can name . This means we can find our distance by utilizing the Pythagorean Theorem. Plugging our known values in gives
Taking the square root gives our answer.
Example Question #1 : How To Find The Distance Between Clock Hands
A clock has two equally long hands on it, each measuring inches. If the minute hand is directly on and the hour hand is directly on , what is the distance between the two hands?
Our clock looks roughly like this:
Now, between every number on the clock, there are or degrees. Therefore, from to , there are degrees. To find the arc length, you use the equation:
Now, we know:
We know that . Therefore, we can write our equation:
Example Question #2 : How To Find The Distance Between Clock Hands
A clock has two equally long hands on it, each measuring inches and extending to the edge of the clock. If the minute hand is directly on and the hour hand is directly on , what is the length of the minor arc connecting the two hands?
Our clock looks roughly like this:
Now, between every number on the clock, there are or degrees. Therefore, from to there are of these sectors. Therefore, there are degrees. To find the arc length, you use the equation:
Now, we know:
We know that . Therefore, we can write our equation:
Example Question #5 : How To Find The Distance Between Clock Hands
A clock has two equally long hands on it, each measuring inches. If the minute hand is directly on and the hour hand is directly in the middle of and , what is the distance between the two hands?
Our clock looks roughly like this:
Now, between every number on the clock, there are or degrees. We have a little trickier math to do, however. Let's subdivide the clock into subsections instead. Each of these will have degrees. Now, between and , there are such subsections. Since the hour hand is directly in the middle of and , there is one more such subsection. Therefore, we have total subsections or degrees. To find the arc length, you use the equation:
Now, we know:
We know that . Therefore, we can write our equation:
Example Question #1 : How To Find The Angle Of Clock Hands
What is the angle formed by the minute hand and the hour hand at 4:45?
The angle measure between any two consecutive numbers on a clock is .
Call the "12" point on the clock the zero-degree point.
At 4:45, the minute hand is at the "9" - that is, at the mark. The hour hand is three-fourths of the way from the "4" to the "5; that is,
Therefore, the angle between the hands is
, the desired measure.
Example Question #2 : How To Find The Angle Of Clock Hands
What is the angle between the hour hand and the minute hand at 4:40?
At 4:40, the minute hand is on the 8, and the hour hand is two-thirds of the way from the 4 to the 5. That is, the hands are three and one-third number positions apart. Each number position is thirty degrees around the clock, so the hands form an angle of .
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