Basic Geometry : Basic Geometry
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Example Questions
Example Question #831 : Plane Geometry
If a checkerboard is a perfect square and has a diagonal length of 
To find the area, we first need to know the length of the sides. Since this is a perfect square, we can use the Pythagorean Theorem with just the value for the diagonal:
Now that we know the length of the sides, we can solve for area, which is really just the same value as 
Example Question #831 : Basic Geometry
What is the area of a square whose side length, 
The formula for the area of a square is 
Example Question #832 : Basic Geometry
If the perimeter of a square is 45.2 centimeters, what is its area?
Because this is a square, all the sides are the same, so the perimeter is 4 times whatever the side lengths area.
To find the side lengths, just divide by 4:
If the side lengths are all 11.3, the area would be
Example Question #833 : Basic Geometry
One side of a square is 9cm long. What is the perimeter and area?
Another side of the square is needed to find the perimeter and area.
Perimeter is the sum of all the sides.
A square has 4 equal sides. Therefore the perimeter is,
Area is length*width. In this case both the length and the width are 9.
Example Question #425 : Quadrilaterals
The length of BC is twice the length of CD. The total area is 
None of the answers given are correct.
The area of any quadrilateral is equal to length x width. To find the area of the rectangle, set up an equation.
Since BC is twice the length of CD, you can replace the W in the equation with 2L
Now, your equation is
Bring the 2 to the other side by dividing each side by 2.
Example Question #834 : Basic Geometry
Know that in a Major League Baseball infield the distance between home plate and first base is 90 feet and the infield is a perfect square.
What is the area of a Major League Baseball infield?
Because the infield is a square, the distance between each set of bases is 90 feet.
To find the area of a square you multiply the length by the width.
In this case
Example Question #152 : How To Find The Area Of A Square
Know that in a Major League Baseball infield the distance between home plate and first base is 90 feet and the infield is a perfect square.
What is the area of the half of the infield formed by home plate to first base, first base to second base, and an imaginary straight line between home plate and second base?
Because this imaginary triangle is half of the entire infield it means it is the area of the square infield divided by two.
If the area if the infield is 90x90=8100 then the triangle is 8100 divided by two, which equals 4050 Square Feet.
Example Question #835 : Basic Geometry
Know that in a Major League Baseball infield the distance between home plate and first base is 90 feet and the infield is a perfect square.
If for some reason the baseball players decided to play with the basepaths at half of their usual length, what would the area of the infield be?
If the base paths were half of their original length they would be 45 feet long.
To find the area of this new square, one must multiply 45 times 45.
This equals 2025 square feet.
Example Question #153 : How To Find The Area Of A Square
Know that in a Major League Baseball infield the distance between home plate and first base is 90 feet and the infield is a perfect square.
If a field designer accidentally put two infields right next to each other, what would the area of the giant infield be?
The answer can be found multiple ways, either by adding the area of the two square infields together,
Or, by picturing the two infields as a rectangle and finding the are by measuring the length and the width. If the length of one side of an infield is 90 feet then the double infield rectangle will have a length of 180 feet and a width of 90 feet.
Therefore,
Example Question #153 : How To Find The Area Of A Square
True or false: The area of a square with sidelength 3 is 12.
True
False
False
Given the length of each side of a square, the area of the square is the square of this length. Therefore, since the square has sidelength 3, its area is
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