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Basic Geometry : Basic Geometry

Study concepts, example questions & explanations for Basic Geometry

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All Basic Geometry Resources

9 Diagnostic Tests 164 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #1411 : Basic Geometry

Find the area of a right triangle with leg lengths of $\frac{1}{7}$ and $\frac{1}{8}$ .

Possible Answers:

$\frac{1}{28}$

$\frac{1}{112}$

$\frac{1}{14}$

$\frac{1}{56}$

Correct answer:

$\frac{1}{112}$

Explanation:

Recall how to find the area of a right triangle:

$\text{Area}=\frac{1}{2}(\text{base}\times\text{height})$

Because the legs of the right triangle form a right angle, the legs are also the base and the height.

To find the area of the right triangle, just plug in the values for the lengths of the legs into the equation given above.

$\text{Area}=\frac{1}{2}\left(\frac{1}{7} \times \frac{1}{8}\right)$

Simplify.

$\text{Area}=\frac{1}{2}\left( \frac{1}{56}\right)$

Solve.

$\text{Area}=\frac{1}{112}$

Report an Error

Example Question #422 : Triangles

Find the area of a right triangle with leg lengths of and $\frac{1}{6}$ .

Possible Answers:

$\frac{1}{4}$

$\frac{1}{2}$

Correct answer:

Explanation:

Recall how to find the area of a right triangle:

$\text{Area}=\frac{1}{2}(\text{base}\times\text{height})$

Because the legs of the right triangle form a right angle, the legs are also the base and the height.

To find the area of the right triangle, just plug in the values for the lengths of the legs into the equation given above.

$\text{Area}=\frac{1}{2}\left(12 \times \frac{1}{6}\right)$

Simplify.

$\text{Area}=\frac{1}{2}\left( \frac{12}{6}\right)$

Solve.

$\text{Area}=\frac{12}{12}$

Reduce.

$\text{Area}=1$

Report an Error

Example Question #1412 : Basic Geometry

Find the area of a right triangle with leg lengths of and .

Possible Answers:

$\frac{15}{2}$

$\frac{9}{2}$

Correct answer:

$\frac{15}{2}$

Explanation:

Recall how to find the area of a right triangle:

$\text{Area}=\frac{1}{2}(\text{base}\times\text{height})$

Because the legs of the right triangle form a right angle, the legs are also the base and the height.

To find the area of the right triangle, just plug in the values for the lengths of the legs into the equation given above.

$\text{Area}=\frac{1}{2}(3 \times 5)$

Simplify.

$\text{Area}=\frac{1}{2}(15)$

Solve.

$\text{Area}=\frac{15}{2}$

Report an Error

Example Question #1413 : Basic Geometry

Find the area of a right triangle with leg lengths of $\frac{2}{3}$ and $\frac{1}{4}$ .

Possible Answers:

$\frac{1}{4}$

$\frac{1}{6}$

$\frac{1}{24}$

$\frac{1}{12}$

Correct answer:

$\frac{1}{12}$

Explanation:

Recall how to find the area of a right triangle:

$\text{Area}=\frac{1}{2}(\text{base}\times\text{height})$

Because the legs of the right triangle form a right angle, the legs are also the base and the height.

To find the area of the right triangle, just plug in the values for the lengths of the legs into the equation given above.

$\text{Area}=\frac{1}{2}\left(\frac{2}{3} \times \frac{1}{4}\right)$

Simplify.

$\text{Area}=\frac{1}{2}\left(\frac{2}{12} \right)$

Solve.

$\text{Area}=\frac{2}{24}$

Reduce.

$\text{Area}=\frac{1}{12}$

Report an Error

Example Question #1414 : Basic Geometry

Find the area of a right triangle with leg lengths of and .

Possible Answers:

150

120

180

Correct answer:

Explanation:

Recall how to find the area of a right triangle:

$\text{Area}=\frac{1}{2}(\text{base}\times\text{height})$

Because the legs of the right triangle form a right angle, the legs are also the base and the height.

To find the area of the right triangle, just plug in the values for the lengths of the legs into the equation given above.

$\text{Area}=\frac{1}{2}(12 \times 15)$

Simplify.

$\text{Area}=\frac{1}{2}(180)$

Solve.

$\text{Area}=90$

Report an Error

Example Question #1415 : Basic Geometry

Find the area of a right triangle with leg lengths of and .

Possible Answers:

Correct answer:

Explanation:

Recall how to find the area of a right triangle:

$\text{Area}=\frac{1}{2}(\text{base}\times\text{height})$

Because the legs of the right triangle form a right angle, the legs are also the base and the height.

To find the area of the right triangle, just plug in the values for the lengths of the legs into the equation given above.

$\text{Area}=\frac{1}{2}(3 \times 10)$

Simplify.

$\text{Area}=\frac{1}{2}(30)$

Solve.

$\text{Area}=15$

Report an Error

Example Question #1416 : Basic Geometry

Find the area of a right triangle with leg lengths of and .

Possible Answers:

Correct answer:

Explanation:

Recall how to find the area of a right triangle:

$\text{Area}=\frac{1}{2}(\text{base}\times\text{height})$

Because the legs of the right triangle form a right angle, the legs are also the base and the height.

To find the area of the right triangle, just plug in the values for the lengths of the legs into the equation given above.

$\text{Area}=\frac{1}{2}(5 \times 12)$

Simplify.

$\text{Area}=\frac{1}{2}(60)$

Solve.

$\text{Area}=30$

Report an Error

Example Question #431 : Triangles

Find the area of a right triangle with leg lengths of and .

Possible Answers:

Correct answer:

Explanation:

Recall how to find the area of a right triangle:

$\text{Area}=\frac{1}{2}(\text{base}\times\text{height})$

Because the legs of the right triangle form a right angle, the legs are also the base and the height.

To find the area of the right triangle, just plug in the values for the lengths of the legs into the equation given above.

$\text{Area}=\frac{1}{2}(10 \times 15)$

Simplify.

$\text{Area}=\frac{1}{2}(150)$

Solve.

$\text{Area}=75$

Report an Error

Example Question #1418 : Basic Geometry

Find the area of a right triangle with leg lengths of and .

Possible Answers:

300

150

600

900

Correct answer:

300

Explanation:

Recall how to find the area of a right triangle:

$\text{Area}=\frac{1}{2}(\text{base}\times\text{height})$

Because the legs of the right triangle form a right angle, the legs are also the base and the height.

To find the area of the right triangle, just plug in the values for the lengths of the legs into the equation given above.

$\text{Area}=\frac{1}{2}(50 \times 12)$

Simplify.

$\text{Area}=\frac{1}{2}(600)$

Solve.

$\text{Area}=300$

Report an Error

Example Question #1419 : Basic Geometry

Find the area of a right triangle with leg lengths of and .

Possible Answers:

288

108

144

Correct answer:

144

Explanation:

Recall how to find the area of a right triangle:

$\text{Area}=\frac{1}{2}(\text{base}\times\text{height})$

Because the legs of the right triangle form a right angle, the legs are also the base and the height.

To find the area of the right triangle, just plug in the values for the lengths of the legs into the equation given above.

$\text{Area}=\frac{1}{2}(24 \times 12)$

Simplify.

$\text{Area}=\frac{1}{2}(288)$

Solve.

$\text{Area}=144$

Report an Error

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All Basic Geometry Resources

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Basic Geometry : Basic Geometry

Study concepts, example questions & explanations for Basic Geometry

All Basic Geometry Resources

Example Questions

Example Question #1411 : Basic Geometry

Example Question #422 : Triangles

Example Question #1412 : Basic Geometry

Example Question #1413 : Basic Geometry

Example Question #1414 : Basic Geometry

Example Question #1415 : Basic Geometry

Example Question #1416 : Basic Geometry

Example Question #431 : Triangles

Example Question #1418 : Basic Geometry

Example Question #1419 : Basic Geometry

All Basic Geometry Resources

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